𝗟𝗶𝗺𝗶𝘁𝗶𝗻𝗴 𝗥𝗲𝗮𝗴𝗲𝗻𝘁 - Revise in 10 Minutes

In this video we will learn the limiting reagent.
Join us on telegram : t.me/chemistryvibes
#visionneet #limitingreagent #anushkamam

[@visionneetofficial]

vision NEET Helpline Number : 9711975344
play.google.com/store/apps/details?id=com.visionNeet.apps

[@Shreyshi-jh3cc]

4.1 g Homework answer

[@mrpechcus]

answer is 4.1 gm

[@user-lw2ot3np3v]

how ,,,plz explain

[@sulaimyt6872]

Couls you Elaborate how you come to the expression of Stochiometry Cofficent And No of moles one in the video ?

[@vedant2910]

Answer will be 4.1 gm

[@pretty_monster]

why am i getting 8.2 gm?

[@Soundarya7328]

Mam I am studying this chapter from your lecture "wo 28 points bala" .. please tell me am I going in Correct direction

[@sunilshukla680]

It help a lot as a jee aspirant .

[@Pathshalap]

Thank for the lecture 🎉

[@SiD07986]

Thank you for Nice Explanation 😊

[@vanithanageswarakanth4813]

Ur classes are so good mam ❤loved it 😊

[@aanchalscreativityworld2388]

Thankyou mam for this amazing video i understand clearly after watching your video 📸

[@Apppliedscience]

Best example I have ever stood ❤❤❤❤😮😮😮😮

[@NEET.aspirant02]

Thank you ma'am 💙

[@Hrishikesh-0707]

Fantastic explanation mam🙏🙏

[@anushkahalder5638]

Can write these in school exam ? .

[@ABDULWAKIL-cg5om]

AP ko dekh kar mind diverted ho gya❤

[@lofisoftmusic4348]

Thank you so much ma'am 😊

[@Nmdcattestpreparation]

Why we have to study the concept of linting reagent and excess reagent

[@user-rr7zz7lq2j]

Mam why you left pw

[@rajpandey-ib4ct]

Thank you mam❤❤❤❤

[@shreya-Mondal2003]

Answer is 4.1 gm

[@subhasreesahu5476]

Mam this is very helpful please complete all imp topics of physical che before neet

[@SanjayKumar-ds8xv]

Mam Homework answer is 4.1 gram.

[@rekhatiwari1057]

short and nice explaination mam thankyou

[@himanshupalaneetaspirant2421]

Mam please percentage yield bhi samjha dijiye 🙏🙏

[@jatinkundnani26]

Thank you so much mam ❤

[@nazeerullah7996]

AL is limiting reagent which tells that 4.1g of aln will form by mass

[@Teletopinfo]

Pls explain bro ans kaise aaya

[@silochana8674]

4.1g -ans for hw q

[@abdulhaleemsiddiqui1014]

Thanks 🎉🎉

[@jenimahaque3081]

Ans is 4.1g

[@DivyanshDubey-rk8kr]

Thank you ma'am❤❤❤❤❤❤

[@RahulYumlembamVibes]

Superb lecture 👍👍👍👍👍

[@user-qp5jd2fv7h]

Home work answer is 4.1grams

[@Lolcomedyshorts36]

Very helpful video ❤

[@Dayanidhi-ve7ic]

8.2 gram hoga mam

[@rogerlitchford7356]

Are you mean "eight point two gram.

[@Hrishikesh-0707]

Mam.. I've downloaded vision NEET app and registered also....

[@RudhraRana-pb3bu]

Answer of Last question is 4.1g

[@AmarNayak-gh6sz]

It's really helpful

[@dajixiiconvertable7968]

I got 4.1g as mass of AlN

[@Nihirameharunkar]

Ans is 4.1 grams ☺️👍♥️

[@mateen_bhi2071]

4.1 gram. thank you mam

[@naveenjangid253]

Mam your last question is wrong acc. To law of conservation mass
Mass of product is equal to mass of reactants

[@Deepali-wz9kz]

Are thik to hai bhyi

[@saumyakumari2332]

Thanks mam ❤

[@_Simran_7860_]

4.1 g ans

[@PriyaKumari-ol7os]

Answer of last question is 4.1grams

[@rajpandey-ib4ct]

Homework answer is 4.1 gms

[@ARCLASSES625]

Same as your answer

[@ARYAN_12049]

kaise ?

[@ashasingh8758]

*Ya bro you are right my answer is also the same as yours* 😊

[@ashasingh8758]

​​@@ARYAN_120491.* ​Pehle dono ke moles nikalo
2. Fir pta kaise kre ki kon Limiting reagent hai tab uske liye
3. No.of moles ÷ stiochemetry coefficient
4. Then jo smaller ayega Al aur N2 me se wahi Limiting reagent hoga
5. Jo Limiting reagent hoga decide krega ki product kitna form hoga
6. Limiting reagent Al hoga
7.Aluminium ke 2 mole se 2 mole of AlN form hoga toh no. Of moles bhi same honge
8. Fir mass nikalne ke liye No. Of moles of Limiting reagent × Molecular mass of ALN which is
9. 0.1 × 41 = 4.1 gram * < Ans>

[@uchihaitachi3039]

​​@@ashasingh8758thank you for explaining😊🤝

[@hemangineeanddivyanjanasah7258]

Answer is 4.1 gram

[@hriday9148]

Y u left PW

[@Light_10f]

But my ans 2.06g

[@AshishKasana-0001]

Mam our channel is reached to 200k

[@rudrakshsingh05]

4.1 gm answer

[@karangupta123]

4.1 gm

[@Kd-FunBruh]

thnx mam

[@kaveri_ojha]

8.2g

[@adritaacharya9296]

answer is 4.1g

[@jayasingh7597]

Homework and is 4.1 g of 2AlN are there

[@taanusiyasharma8923]

How is it 4.1 can u explain

[@Aadarshu355]

MAM APNE JO DIVIDE KARA HAI WO GALAT HAI 0.1/2=0.05 HOGA ,0.2 NHI HOGA .
MAM YE APNE IDHAR CONFUSE KAR DIYA .
APNE PAHLE BHI PADHYA HAI AUR YAHI GALTI TH I❤

[@selfmotivated304]

Dude its o.1÷1/2 when 1 /2 will b converted into multiply it will b 0.1×2 /1 =0.2

[@shiddheshsingh]

Mam question practice plz❤

[@NuzhatHashmi-q5h]

The correct ans is 4.1 g

[@LaibaAfzal-rf9sj]

plz explain

[@KishoriKaremore]

4.1g

[@DivyeJain1]

Ans - 4.1 g

[@VikashVarun-fd8vs]

4.1gm are exactly answer we proved it

[@Duluu-5]

❤

[@sufiyanmirza340]

4.05gm

[@nupurgarg2181]

Homework answer is 4.1 gm

[@DharmendarKumar-yt6lo]

🎉

[@AllahWadhio-gg9dd]

Answer is 2.05 grams.is it correct mam ❤❤❤❤❤❤❤❤❤

[@ShreshiSingh-il8zl]

Yeahh

[@Devilface18]

Galt h bhai

[@user-mk8kf7rg2q]

❤😊

[@V.G987]

mam aap bohot acha padhate ho please again join pw

[@preranaitankar171]

4.8 gm

[@vibhabetjewargi9385]

Mass= 4.1 gms

[@user-yw1zr6hq8q]

0.5125 answer

[@Sanatan1539]

Mam aapko wrinkles aur fine line aarhi

[@GudduKing-hi7vy]

4.1 gram is the answer😅

[@bhajanwithme1106]

Thankyou mam 🙎🏻🙎🏻

[@SuhaniGupta-ox9be]

Mam class 12 ke video solution lesson ka please 😢😢

[@manaspatra5071]

Mass formed is 2.05 g. I hope my answer is not wrong😢😢😢

[@AshokKumarMaurya-ql2bi]

4.1 gram hoga

[@AshokKumarMaurya-ql2bi]

Your answer is incorrect

[@yuktakalra128]

Mine is also this

[@Anas14369]

Wtf

[@anshukureshi9103]

Correct ha

[@Rakeshdesilva]

4.1 g is the correct answer ❤❤❤

[@atarabaidora1460]

I'm getting it 4.1 gram

[@ytcricshorts27]

4.1

[@tejaswinikhairnar2455]

Ma'am agar limiting reagent ka ans same aajaye...
Toh jiski jyada stoichiometric value voh limiting reagent hoga na?

[@krish10082]

Nhi

[@tejaswinikhairnar2455]

@@krish10082
Then how will we decide? ...in that case

[@Neet_student3311]

4.1❤

[@mehakdeep777]

No. Of moles (Al) = 2.7/27=0.1moles.
No. Of moles (N2)=2.8/28=0.1moles.
nAl/Al=nN2/N.
0.1/2=0.1/1
0.2=0.1
N2 - IT IS A LIMITING REAGANT .
No.of mole = given mass / molar mass .
0.1×41/10=4.1 gm/mole [ANSWER].

[@shajahanshaik8697]

how did u get 0.1/2=0.2 ?? it should be 0.05 ryt?? Al should be limiting regent not N2.

[@shajahanshaik8697]

@mehakdeep777 if N2 is limiting reagent, then the answer should be 8.2g/mol

[@GMSSIPPER]

4.1gm answer 🎉🎉🎉🎉

[@Dayanidhi-ve7ic]

8.2 hoga ya 4.1

[@AnshBitan]

8.2 bro

[@NEHADHAKAD-wt7bu]

Hello ma'am

[@abhi123jaipur]

Ma'am bio wali ma'am kaha gyi 🥺🥺🥺🥺🥺 unka teaching style awesome h 🙏🏻🙏🏻🙏🏻

[@Techacks137]

Hello mam

[@JIGEESHA]

Ma'am please H.W ka ans bata do , 8 g. Aa rha hai... wrong or right ?..

[@mindokumari1589]

Mera bhi yhi aa rha hai

[@mohammed5881]

Mam answer is 4.1 g.. thanks for the session..can u please bring such videos on chemicsl bonding and structure

[@niharika1864]

thank you mam

[@kamalkalita1705]

Very cute maam

[@Piyushx.editz666]

I am first please pin me ❤❤
Mam please jee ke liye bhi padao Naa
Answer -- 8.2 grams ( exactly )
❤❤❤❤❤❤❤❤❤❤❤❤

[@JIGEESHA]

Mine is also same , but comment mein max 4.1 bol rhe h , right kids h ??😢

[@AyushMehra-g1e]

8.2gram❤

[@AmrikSingh-ex1qr]

4.1 gram 😊

[@Royal_girl151]

Mam please maharevison kravado please 😭

[@AshokKumarMaurya-ql2bi]

Maam 4.1 gram

[@mobarakkhan8969]

Mam tum to bohut cute ho

[@alangamerz.304k6]

Bhut achi class thi tips :- kadhpe thode dhanke pahne ke padhya karo lage jaise kisi teacher se padh rhe ho 👍

[@taanusiyasharma8923]

What's wrong with the clothes

[@RahulYumlembamVibes]

4.1gm🤗🤗🤗

[@neurotherapistgagan]

8.2 gm hoga mam

[@Devilface18]

Galt h bhai

[@anvimedico699]

Ans-8.2 gram..