Couples and Their Moments Brain Waves
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- Опубликовано: 16 июл 2012
- Couples and moments are an important part of statics. I show you how to solve a statics problem both with and without using an equivalent moment. The answer is the same both ways, so they are mathmatically equivalent.
This guy talking for three minutes made more sense than my professor talking for 52
Got an exam tomorrow morning... haven't understood a thing the last three weeks, but pretty sure i got at least 50% done in the last twenty minutes because of your videos.
I can't believe how much this video helped me. My current instruction was not helping!!! Thanks Mark!
Many years later and I'm watching this video, preparing for a test. You explain it very well. Thank you (from Denmark btw)!
You sir are indeed a rock freaking star!!
I started watching your videos a few years ago and whenever I tend to forget something or want to learn something new I always end up on one of your stuff.
Thanks again for making this free. I know that it definitely cost you something to learn it
Been looking something like this for 2 hours, finally found it.
Thank You So Much Sir for such a great way of making us understand such things! It really helped a lot! Regards from India! :)
My professor told that "every couple has its moment". Suddenly the entire class started to laugh like hell. Well he said that in purpose although he was actually right and true... Hahaha
Jesus Christ, I think you saved me from failing my Statics Assignment!
Thank you so damn much!!
Wow, thanks very much. I hope you crush that assignment :-)
Thank you so much sir it did help me. I hope there will be videos regarding different terminologies used for the same types of problems to achieve application and exam orientation. It's encouraging to keep learning everything that comes my way but hard to find out what's relevant.
I am a computer professional pursuing Mechanical engineering out of interest in Mechanics for Robotics. I do it at Institute of Engineers(India) which was established by British in my country- the course is tough but there lies the challenge.
Thanks again and am looking forward to learn a lot from you.
sweeet!!! thanks
Hey Professor, I have a question to you that I saw you moving the upward force (100N)to the center of the bar (i assume). Do I have to move the downward force to center as well as? thanks
You didn't mention which point you chose as the pivot when shifting the force to get the moment. Do you just assume?
Does that mean with couple and moments we dont need to draw freebody diagram or what?
The force on the left side would cause an opposite moment.
how do u assume that the force at Point B is going downwards
Hopefully you've got your degree in engineering already, but it's arbitrary. He just did it like that for the sake of showing equilibrium.
I don't understand how you got the 500 Newton metres 😭
he looks like the guy from athlean X
SUBSCRIBED SUBSCRIBED SUBSCRIBED!!!
i know this video is 5 years old but like after watching something i already knew but just told to me in such a clear way it just made me understand everything really well instead of memorising every scenario. Thank you
Thank you Doc. you helped me
i love u and your simple and easy method waoo sir..................
God bless u sir.
when you do the second method, do you assume the direction of moment for both Fa and Fb?
Thank U Sir ! Really helped !
but if I'm given a square and have to calculate the sum of moments around each point how to do it ? is there any video explain this ?
Sir its really helpful,if possible then try to upload more videos related to end moments(fixed end,rotation and translation),thanks from india.
Still confused... at the end, did you just divide the moments you know by the length of the body? or where did the 3 come from?
sir how about dynamics course ?
why divide by 3 meters and not 1.5 meters because the moment is in the middle right?
yes 1.5 meter is the center point of enter line,but he is using 0.5m because that's the distance from a force to the center. So from the force going down to the force pointing up has a distance of 1 meter between them.
The reason 3m is used is that to find reaction Fb a moment is taken about Fa which is 3m away. As there is a 1000Nm moment counterclockwise in the system to be resisted by a clockwise moment (from Fa) by 3m x Fb, giving Fb = 1000/3N. Fa = Fb (remember the 1000N loads one meter apart were replaced by the midpoint moment.)
Ezz topic