Banked Curve with Friction: Finding Maximum and Minimum Speed
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- Опубликовано: 30 июн 2024
- Banked curve without friction video: • Banked Curve Physics -...
Physics Ninja looks at the banked curve problem with friction and finds the minimum and maximum speeds that you can safely navigate the turn.
This is by far the best video for banked curves because it covers the general case.. Thanks a bunch!
This video is actually terrific!
The concepts helped me adapt the FBD for upside down banked curves as well!
10/10, shared it with the Physics C bois
Keep up the great work man!
This vid is the GOAT for this concept. Keep coming back to it multiple times
nicely done. Thx for doing the general cases. Was a good check for my problem set.
Fantastic - so clear and simple - makes a lot of university lecturers look like twits
It’s 11:12 pm right now, I’ll watch your video tomorrow and thank you for what you do
Thanks for the Excellent video! It was helpful showed the simple way to convert between the sin and cos version to tan by just dividing them all through by cos. That makes it much easier to compare to results from other sources.
thank you for the video! Much better explanation than my physics c teacher...
AMAZING thank u ninja
Great explanation sir.
Thank you. Made a lot of sense
Great explanation
you helped me out so so so much !!! thank you amazing video
It’s comments like yours that motivate me to make more videos.
You deserved more likes, thank you😉
Again, great! ❤️
thanks a hell of alot
Thanx sir , all doubts clear.
Thanks sir...It was really helpful
You deserve more likes and subscribers.
Tell your friends!!! Thanks for watching, I appreciate your support.
Thank you 🙏🏼
Very helpful...
You are a godsend
awesome!
i really struggle with knowing where to place theta. Could you briefly explain, or provide a link to a video that does? rest of the video is great!
LOVE THISSS!!!!!!!!
If we add the center of gravity and the distance between the tires to this same situation, would it affect the problem in anyway? Because Im stuck on a question where they also gave the center of gravity height and the distance between the tires
This exact question showed up on an MIT 8.01 pset. Thanks lol
video helped a lot for my physics midterm! voice sounds like lightning mcqueen is teaching me racing physics
You got this!!!
Thanks a lot for this video! Was really helpful. I recently started to learn physics and am not sure why we should use static friction than kinetic friction here :-( Could anyone explain it a little bit? Thanks a lot in advance!
Can the N you found in the end be used for both slow and fast case?
Oh my god thank you
thanks
At what speed does the friction switch direction?
this video fye
Sir, may I know why we do not resolve the force as what we will do in the case of a block sliding down the slope?
For a block sliding down a slope the acceleration is down the slope so we break down the forces into components using a coordinate system that has one axis along the slope. For this problem the acceleration is toward the center of the circle. It's easiest to use a coordinate system with one axis toward the center of the circle and break forces down into those components.
@@PhysicsNinja oh. Ok. Thank you. May i know how is the dynamics of a cyclist bending the bicycle during a turn?
Why is the static force acting down the ramp when it's max speed, why is it acting up the ramp when it's minimum speed.
Take the case when the speed is 0, in that case the force of friction would be up the ramp because the car would want to slide down the ramp. same is true for small value of speed.
The picture is actually of Daytona lol. Nice informative video though.
Why is friction acting in the opposite direction for the second case?
Friction will act to oppose motion. Consider the case where the car isn’t moving. Here friction tries to hold the object on the slope and acting up the ramp.
Great video! Why can we not initally say that N =mg. This way we would only have to consider one dimension. For example for x it ould be mgsin(x)-umgcos(x)=mv^2/r. Then all m's could cancel. However it gives rise to a different answer then the one you found later for v. Why is this? Thanks :)
when you measure the radius. do you measure it horizontally. or measure it along the banked road?
Horizontal
@@PhysicsNinjaThanks. The reason that I ask is because in your video Banked Curve Physics - Uniform Circular Motion, at time 13.24, the line R = 1100 ft looks like it is from the center to where the car is along the ramp, rather than from the center to the horizontal projection of the car. Other than that, you explanation is really good.
I did a question in which I had to calculate max and min velocity. The value of min velocity came out to be a complex number. What does it mean in physical world?
Interesting question! First of all, congratulations for the video. It's amazing! About your question, really, 1-tg33º is negative, so, we can't calculate the minimum speed. Not really, though, I think the minimum speed, in this case, is zero. In this case, we can't use the maximum static friction coeficient, 0,7. We need to use a little less, so that we won't have x acceleration (neither y acceleration), so, the speed is zero. In the first equation, the second membre will be zero, instead of mv^2/R, so that u=tg33º=0,65 (less than 0,7, ok?!). In this case, we won't have the maximum static friction, but this is how static friction works: it increases until the maximum, assuming all the values between 0 and u_s.
In the same way, if 1-utg(theta)
Hi, I have a homework question that ask “why is the max speed for banked roads generally lower than roads that are flat?” But isn’t the max speed for banked roads higher? I tried substituting in values of theta and mu and the banked road gave a higher max speed
The bank is usually not uniform especially near the point where you leave the bank. If it’s slippery and the and the angle is small this would really be unsafe. Better to play it safe and reduce the speed limit.
What would the proper alignment be of the vehicle on a 33 degree Banking.
The maximum speed recorded is
How friction is towards the radius,not along road
There is both
❤️❤️❤️❤️❤️❤️
what if theta was 45 degrees and the coefficient was 1
Great question. The equation says that the max speed tends toward infinity, however that equation only holds if the denominator is greater than zero. The problem with this limit can be seen if you look at Newton's laws in this limit. You see that the perpendicular component of the Normal and the perpendicular component of the friction cancel out which means we are left with only the weight in this direction.....but that means that the forces can't equal to zero in this limit - mathematically they can if the Normal force is infinite. If the normal force is really big you would need an infinitely strong ramp or tires and this is where the simple picture breaks down. In the limit of mu=1 and the angle approaches 45 degrees it means you can go really fast!!
Physics Ninja thank you!
The Fast Case is odd. If you happen to have mu = 1 and an angle > 45 degrees, you get a negative square root (which does not exist). Does that mean that the body will never slide (i.e. You can go as fast as possible)?
EDIT: Actually, there is a HUGE mistake in the fast case, before using the 1st equation to get the Vmax, you isolated the N in the 2nd equation, but YOU CAN'T do that if the angle = 45 and mu = 1, because you would be dividing by zero. Something is very wrong with this model
No mistake, trust me. This is a great question and I’ve answered it before. See below comment from Lavender
@@PhysicsNinja Oh just read it. I got it now. The Vmax equation is undefined for a 45° angle and mu = 1. But, by being undefined, that means there is no max speed, the body can go infinitely fast and it is not going to slide. In other words, the friction force will never reach its maximum possible value (mu * N). Thanks!
@@robertosabinospina1066 you got it
gooodeo viiiideo
10q sir
2:39 how do you know that?
The car drives in a curve or a perfect circle. We know that we because we have defined/assumed that.
For Min speed , a negative Speed🤔?
The expression will never be negative, it would slide down first. sin(theta) is always greater than >us*cos(theta)
@@PhysicsNinja i tried with a degree of 15 for a problem, i come to the same formulas , the max speed Is ok , but when i try with Min speed the numerator became negative rg(sin 15 - 0.5 cos 15)
@@coachtofu412 That means the minimum speed is 0! The object doesn't have to move in a circle and it will remain on the ramp and not slide down.
The force of friction is more than enough to hold up the object.
@@PhysicsNinja finally i find an answer, love you man
The calculations are fine as far as they go but this cannot be compared to reality as you try to do at the end. The reason is that you have ignored the aerodynamic downforce that is generated by the cars themselves, which itself is dependent on the square of speed.