Jee mains aur board toh bahot wallah aur unacademy padhalete hn RUclips pe lekin Ashish Arora sir basic to advanced level teach krtehn And the biggest thing that being an academic head of Allen jaipur he never promotes Allen Hats off u sir 🙏🙏
@@siddhantkhatri1017 tum physics me aashish sir ya kisi aur sir ke lecture dekhte ho baad me hi NCERT ke aalawa ke topics ke questions bante hai na mera aisa hi hai but hamare school me 2 -3 students school ke NCERT ke lecture dekhke hi NCERT ke bahar ke topics ke questions karte hai aisa kaise ho sakta hai samaj nahi aa raha unko puche to kahte ki kisi aur ke lecture nahi dekhte fir bhi questions hote hai and me aashish sir ya kisi aur sir ke lecture dekhta hu baad me hi jee ke questions hote hai
@@godhaninisarg387 bhai apna apna h sb ka mai to koi acche teacher se hi pdhta hun jo jee level ke qtns karae mjhse tbhi hota h bhai. Ya to jhoot bol rhe h wo qki mjhe nhi lgta aisa possible h ,nhi to bhai intelligent honge 😂 . But i think jhoot hi bol rhe h qki us level ka approach ncert kbhi build nhi kr skta jaisa adv ya mains me lgta h.
@@maneeshsinghgautam7300 bro I want to spend minimum for books, pg volume 1 mechanics will be a good choice? Cengage has 2 volumes for mechanics and it costs 1200 bundled, pg costs around 400, pg seems value for money? Is it good?
Itne bade teacher free me padate hai, as your senior achhe se padhna I wish 100 percent efficiency rahe jee main and some jee advanced me select hone ki..
21:26 it is - Vy= uy - gt velocity in y direction. Vy=Vx= ( angle of impact 45 deg to ground). and projectile motion so Vx = ux . Therefore Vy= Vx= ux = √3/2u
Ashish Sir is the oldest teacher of Physics...Don't compare him with anyone... Subscribers r not the only way to judge.Judge karna hain toh experience se karo..Sir is teaching Physics from past 29 years.
No it's not underated. Level ke students hi kam hai youTube pe joki inke content ko handle kar paye I got 91 marks in jee main in physics by following revision checklist and concept videos
how can he simply say ki pdf download kr lo as this will hamper his earnings from the book he is a true gem who has nothing to do with money making he just wants the betterment of students 🙂🙂🙂
In the last question, we can easily observe that graph of y - coordinate wr.t x coordinate is parabolic and we can differentiate the eqn get the value of x at which y is maximum. That is Range/2 and put that value of x in the eqn to get Hmax. That x that we obtained earlier is Range/2. So mutliply by 2 so that is Range = 1unit. Height = 1/4 units
@@gamobytes9189 bro if you go to a coaching do it’s material first, and then move to other books. Agar material complete hai aur confident ho to fir PG karo, hcv basic book hai material Mai cover ho jati hai, provided the material you solved is from a quality coaching
In IL 1.45-sir, is there any symmetry between the two wheels as when you had calculated 'h' then you have written 2a- 2b which means top of front wheel is at same height as that of centre of rare wheel .But while finding range you have written [ c^2-(a-b)^2]^1/2 . It should be rather [c^2-b^2]^1/2
No, you are wrong, you are basically saying a=2b, no its not given, just drop a perpendicular from centre of small wheel on the radius of bigger wheel, now apply pythagorus.
Que 66's answer is wrong because it is impossible to do that physically to make perpendicular velocity the initial angle must be greater than 45... For that que the time of flight will be 11 sec and the time to be perpendicular is 22 sec how is this possible sir...
It's absolutely correct man... You are comprehending it inappropriately. If you dot these 2 vectors V1=Vcos∅i+Vsin∅j And V2=Vcos∅+(Vsin∅-gt) you'll get a standard result of time which is t=u/gsin∅. If you put those values in that you'll get t=22sec. Simple
@@adityarathod4200 For that i've an explanation but, I don't know whether it's correct or not. If we draw a graph for the velocity it 1st decreases and then again increases. After Vy=0 at top most point it increases gradually so, for t=22 sec, if we put it in this eq. Vy=uy-gt it shows that if, time will decrease Vy is gonna to increase. So, ultimately hitting velocity will be more only if Time at that hitting point is less..
@@MohitKumar-ds6ok resnick Halliday is more detailed but language is little complex for those who are not comfortable with english. So first we should read pg books then foreign writer books
It's correct man.. In vector we don't use sign for writing any vectors in this form V vector= Vx+Vy or it can be V=Vx+(-Vy) It's just called "Vector Addition". Ever heard of " vector subtraction",Lol!?? Hope you get it rn.
Good evening dear sir and PG team, I kindly request you to publish the kindle version/EBOOK Version of the physics galaxy book as I live in kuwait (NRI) and I'm not able to access the book here nor through courier due to covid Pls help Thank you
I have a doubt ,hope someone can clear it,at 13:18 the velocity which sir took to solve the equation is taken wrt to front wheel or the back wheel of the carriage
Sir why you always wear black shirt while taking lectures ?? Thank you for your support to JEE aspirants like me, onion physics series really helping me to create proper understanding of the chapters 👍🏼👍🏼.
First teacher on youtube who teaches advanced level
Search Mohit Tyagi on youtube
Abj sir also from)0 to 2 nd level pgysics olympiad
@@parbonnath4393 BRO HE SAID 1st Teacher and we all know ashish sir has delivered advance content since 2011..
@@jitmandal8379 NOPE PAR ABHI DEKHA UNKA BHI CONTENT ACCHA HAI.BUT ASHISH SIR IS COMPLETE PACKAGE.
Bhai kaha koe ho
"True Gem always lies under deep black mines "
- For Physics Galaxy and all Physics Lovers❤
Jee mains aur board toh bahot wallah aur unacademy padhalete hn RUclips pe lekin Ashish Arora sir basic to advanced level teach krtehn
And the biggest thing that being an academic head of Allen jaipur he never promotes Allen
Hats off u sir 🙏🙏
@@godhaninisarg387 bhai q prachaar kr rha h 😂 competition bdhwa rha h bhhai tu bs
@@siddhantkhatri1017 ok bas delete kar diya ab competition nahi badhegi
@@godhaninisarg387 😂 bdhiya kia
@@siddhantkhatri1017 tum physics me aashish sir ya kisi aur sir ke lecture dekhte ho baad me hi NCERT ke aalawa ke topics ke questions bante hai na mera aisa hi hai but hamare school me 2 -3 students school ke NCERT ke lecture dekhke hi NCERT ke bahar ke topics ke questions karte hai aisa kaise ho sakta hai samaj nahi aa raha unko puche to kahte ki kisi aur ke lecture nahi dekhte fir bhi questions hote hai and me aashish sir ya kisi aur sir ke lecture dekhta hu baad me hi jee ke questions hote hai
@@godhaninisarg387 bhai apna apna h sb ka mai to koi acche teacher se hi pdhta hun jo jee level ke qtns karae mjhse tbhi hota h bhai. Ya to jhoot bol rhe h wo qki mjhe nhi lgta aisa possible h ,nhi to bhai intelligent honge 😂 . But i think jhoot hi bol rhe h qki us level ka approach ncert kbhi build nhi kr skta jaisa adv ya mains me lgta h.
Sir I am very glad with ur series and PG books these r awesome
Bro cengage se achi hai?
@@uditraj5729 bro I can't tell you which is better but both are good books.
@@maneeshsinghgautam7300 bro I want to spend minimum for books, pg volume 1 mechanics will be a good choice? Cengage has 2 volumes for mechanics and it costs 1200 bundled, pg costs around 400, pg seems value for money? Is it good?
telling to get his own book`s pdf and print it... LEGEND FOR A REASON 👑👑👑
He’s physics god for a reason
He is very brilliant cuz saying us to get a print for 300 as he knew that we would more recommend to buy riyal book for 400😂😂
12:39 Sir,the horizontal range should be sqrt(c^2-(a-b)^2).Please check once more.
Yes you are right
correct
bhai sir ne kya bola tha ...calculation thodi bohot idhar udhar ho sakti hai ....obvious hai sir ne vha Pythogouras lagaya hai toh -ve hee aayega vha
Itne bade teacher free me padate hai, as your senior achhe se padhna I wish 100 percent efficiency rahe jee main and some jee advanced me select hone ki..
Thanks bhai :)
21:26 it is - Vy= uy - gt velocity in y direction. Vy=Vx= ( angle of impact 45 deg to ground). and projectile motion so Vx = ux . Therefore Vy= Vx= ux = √3/2u
Sir is so good that he doesn't mind if his book is being pirated and only want students to get benefit.
1:59 can any author see like this SIR UH ARE LEGENDARY....🔥🔱
Bruh🔥
Thanks RUclips for recommending this gems channel.
Every educator yelling mine is advance level video.
Ashish sir be like: ruko jara sabar karo🙄🙄🙄🙄😎😎
Can't describe this man in words.
A true gem.
Love u 3000 times sir. ❤
wow a perfect learning is this.
we have sir's lectures,book and now analysis of books questions.
Sir , really blessed for having you and having your channel sir, thank you very much
Waiting for surprise eagerly❤️👍❤️
Ashish Sir is the oldest teacher of Physics...Don't compare him with anyone...
Subscribers r not the only way to judge.Judge karna hain toh experience se karo..Sir is teaching Physics from past 29 years.
Surely going to donate my first salary to Physics Galaxy because of how helpful they are to me
❤
9:38 Sir is telling to use pirated online copy of his own book.........
Yaaaaaaaar!!!
Mxa hi aagya... Teachers ho toh ase.... Bs.... Nazar ni lg ni chahte apko
Haa yar
19:16
Sir , here time of flight is 11 sec
And the time they are perpendicular is 22 sec.
Most underrated channel for physics
No it's not underated.
Level ke students hi kam hai youTube pe joki inke content ko handle kar paye
I got 91 marks in jee main in physics by following revision checklist and concept videos
@@jeeaspirant3550 congratulations
@@jeeaspirant3550 congratulations🎉🎉🥳🥳🥳👏👏
@@ujwal8151 thanks bro
@@godhaninisarg387 thanks bro
how can he simply say ki pdf download kr lo as this will hamper his earnings from the book
he is a true gem who has nothing to do with money making
he just wants the betterment of students 🙂🙂🙂
no wonder he worked in allen for sooo many years and created many AIRs under 100... legend😍❤❤
In the last question, we can easily observe that graph of y - coordinate wr.t x coordinate is parabolic and we can differentiate the eqn get the value of x at which y is maximum. That is Range/2 and put that value of x in the eqn to get Hmax. That x that we obtained earlier is Range/2. So mutliply by 2 so that is Range = 1unit. Height = 1/4 units
Last mey sach mey mazzzzza aa gaya sir ji
Tushi great ho
One and only one. Ashish Arora sir king .
He is one of serious teacher
Very useful for jee aspirants.
Thank you sir, from today I am going to start my jee preparation as a dropper.
Which nit?
Gajab lecture tha 🔥🔥🔥
5:32
1 question m b) part m angle between velocity and acceleration m un dono ja angle add hona chahiye na??
You are explanation is creditable sir thanq
Bahut bahut thank you sir ji
Waiting for the next video in the NCERT short notes series!
Sir should I start with hcv first or Pg book as I am a Beginner
Jee ke liye prep kar rahe ho toh pehle hilana start krdo
@@bettertomorrow8235 😂😂😂😂😂😂
Woh to Kab Ka chalu Kar Diya par plz help I'm really serious mujhe November me nsep BHI dena hai
@@gamobytes9189 if you are a serious aspirant than I would only say that you should start working hard for the next two years!
@@gamobytes9189 konsa liya book pg mechanics he thoda hard he i say u can also take bm sharna but pg is ultimate
@@gamobytes9189 bro if you go to a coaching do it’s material first, and then move to other books. Agar material complete hai aur confident ho to fir PG karo, hcv basic book hai material Mai cover ho jati hai, provided the material you solved is from a quality coaching
In IL 1.45-sir, is there any symmetry between the two wheels as when you had calculated 'h' then you have written 2a- 2b which means top of front wheel is at same height as that of centre of rare wheel .But while finding range you have written [ c^2-(a-b)^2]^1/2 . It should be rather [c^2-b^2]^1/2
Correct
No, you are wrong, you are basically saying a=2b, no its not given, just drop a perpendicular from centre of small wheel on the radius of bigger wheel, now apply pythagorus.
Sir pls continue class 12 onion physics side by side 🙏🙏
great video sir
Unlisted mode should be public
Sir Last question can also be done by
differentiating equation of trajectory.
Using knowledge of quardatic equations ( parabolic trajectory)
Sir can 2021 students can also follow onion physics???
Only if have completed the syllabus and want extra practice
Thank you Sir ☺️
19:23 why would you take the angle with vertical should'nt we take the angle with horizontal?
At time 21:45 in video , how you have used vertical initial velocity in x direction
Sir last wala question, distance between the roots and maxima (by dy/dx=0) use kar ke bhi answers same aata hain, kya yeh method bhi valid hain?
At 13:45, range ke equation me c square -(A-B)^2 hone chahiye kyunki vo hypotenuse of∆ nhi h na
19:00 sir 22 seconds is more than the tme of flight in this question
Sir,U r such a gineous
19:10 its not posible because time of flight is 11 sec.
sir at 17:51 we can directly solve without dot product using tan-1(v_y/v_x) = -60°
19:24 IN THIS QUESTION TIME OF FLIGHT IS 11 SECOND . SO, HOW 22 SEC IS POSSIBLE.
2T
Still wandering is it a white board or smart board or both🤔🤔
Mee too 😂 but I think it is editing 😅
onion physics is badly underrated
Thank You so much sir 🙏🙏
Kaisa gya apka exam neet ya jee
22:03 can anyone explain me why did sir take negative sign for Vx
2:02 why we respect him
Que 66's answer is wrong because it is impossible to do that physically to make perpendicular velocity the initial angle must be greater than 45... For that que the time of flight will be 11 sec and the time to be perpendicular is 22 sec how is this possible sir...
It's absolutely correct man...
You are comprehending it inappropriately.
If you dot these 2 vectors
V1=Vcos∅i+Vsin∅j
And V2=Vcos∅+(Vsin∅-gt)
you'll get a standard result of time which is t=u/gsin∅. If you put those values in that you'll get t=22sec. Simple
@@nobarakugisaki_._ but that particle ends its projection at 11 sec so after 11 sec that particle will be at rest ( for projectile motion )
@@adityarathod4200 For that i've an explanation but, I don't know whether it's correct or not.
If we draw a graph for the velocity it 1st decreases and then again increases. After Vy=0 at top most point it increases gradually so, for t=22 sec, if we put it in this eq. Vy=uy-gt it shows that if, time will decrease Vy is gonna to increase. So, ultimately hitting velocity will be more only if Time at that hitting point is less..
Sir i do not have pg mechanics book....Which book should i use for reference?
can you plz send the link to join that grp or provide me some direct source??
A pdf is also available. Type it on google
@@MohitKumar-ds6ok resnick Halliday is more detailed but language is little complex for those who are not comfortable with english. So first we should read pg books then foreign writer books
@@MohitKumar-ds6ok ncert language is so weird.
Sir please test series ke liye kijiye kuchh
sir i am 2021 aspirant.should i watch only ncert shortnotes or both nvert shortnotes and concept checklist
What is poji? 23:04
I am poji , the one who cleans the board once filled up 🎉🎉
What about the surprise sir
At19:16 .... velocity at time t ka y component to negative hoga na
It's correct man..
In vector we don't use sign for writing any vectors in this form V vector= Vx+Vy or it can be V=Vx+(-Vy)
It's just called "Vector Addition". Ever heard of " vector subtraction",Lol!??
Hope you get it rn.
Sir onion kyu phul ghobi Rakha ligeye channel ka name.
Thank you sir
Good evening dear sir and PG team,
I kindly request you to publish the kindle version/EBOOK Version of the physics galaxy book as I live in kuwait (NRI) and I'm not able to access the book here nor through courier due to covid
Pls help
Thank you
N mcq
1-66
Time of flight is 11 sec.
and time when U and V(t) are perpendicular is 22 sec
if projectile complete in 11 sec then how is it possible??
Same doubt
Last question i solved by making graph of y=x-x^2 (Maths❤)
I have a doubt ,hope someone can clear it,at 13:18 the velocity which sir took to solve the equation is taken wrt to front wheel or the back wheel of the carriage
Both the wheels will have the same velocity so the entire cart will have the velocity v as in translational motion velocity of every particle is same
Can anyone say me best books for iit jee preparation for PCM. AND how many books atleast I should purchase??
Sir book me toh data wrong diya hua rehta hai
In last question we had to tick the incorrect option and the answer was c option
My teacher has also taught these concepts
Does that mean my teacher for jee adv
21:25 nahi samajh aaya
May Allah secure uh from selfishness
Sirrr plz,zz what about 12thhhhh
Baap ka physics
Ncert short notes series
guys 1 like for sir
Sir what about 12thhhh😭😭😭
sequentially chalega sir is also a person he is academic and administrative head of allen JAIPUR, HE has huge workload..
Sir neet 2021 postpone ho kya??
Last q could hv been done just by putting y=0
Sir agar ground pe observer hota toh woh toh dust particle ko 3V ke speed se jaate dekhta
No
Nhi vo 2v se dekhta
Sir hume physics ka paid course chaiye sir please contact number dijiye
Sir why you always wear black shirt while taking lectures ??
Thank you for your support to JEE aspirants like me, onion physics series really helping me to create proper understanding of the chapters 👍🏼👍🏼.
15:00
Postpone hogi kya?? Neet 2021
Postpone nahi hoga app self study karte 👍
Thanks RUclips for recommending this gems channel.
Every educator yelling mine is advance level video.
Ashish sir be like: ruko jara sabar karo🙄🙄🙄🙄😎😎
Thanks sir