Link for Lecture -1 : Introduction to Mechanics - ruclips.net/video/793ddiMke3E/видео.html Link for Lecture -2 : Class 11 Physics | Motion in One Dimension #1| Onion Physics Lecture - 2 for JEE & NEET - ruclips.net/video/1C7l7ryDQHU/видео.html Link for Lecture -3 : Class 11 Physics | Motion in One Dimension #2 | Onion Physics Lecture - 3 for JEE & NEET - ruclips.net/video/A6qWwYHXhV4/видео.html Playlist link for complete Concept Videos of Motion in One Dimension Chapter - ruclips.net/video/gI7vOjqNAeE/видео.html
@@MohammedAli-uv6oj can anyone please explain me that in 25.40 sir has taken acc = 10 but we have to take g-2 na because from the ground its acceleration of bott is not 10 because the elevator is also moving with 2 acce upwards so net acceleration will be 8 downwards na.Please explain
From point of projection to rest position, Time t = u/a = 20/10 = 2 seconds Displacement S = at²/2 = 20m From rest position to hitting wall, this can be thought as the motion of a ball dropped from a height 'H'. So Time of flight = √(2H/g) Here time to reach the wall is given by T = √(2S/a) S = 100 + 20 = 120m a = 10m/s² T = √(2×120)/10 = √24 = 2√6 Total time = t + T = 2 + 2√6
Sir,regarding the distance vs displacement question at 28:20 : If we carefully use sign convention, we realise that at the instant when bolt hits elevator its v is in upward direction.Which means that the bolt won't even get enough time to reach topmost point of its trajectory and then fall from there because the elevator will hit it before it reaches the topmost point. IN SIMPLE TERMS,IN THIS CASE DISPLACEMENT & DISTANCE WOULD BE EQUAL. Point to be noted : If the length of elevator were sufficiently larger than 2m,say something like 10m,bolt would have got chance to reach its topmost point and then fall from there. In that case displacement & distance would have been different. This idea calls for an important question : Find the length of elevator for which its bottom would hit the bolt exactly at the instant when it is at the topmost point of its trajectory?? This boundary length,according to me,would be 6m.
Koi inhe alakh sir se kese compare kr skta h Alakh sir se jyada accha toh unke Batch vale teacher h Harshhh Truth And Ashish Sir is Just God Level.... Ab agar sch bolne pr galiya milegi toh koi dikkat nhi.... BTW Arjuna JEE Student
Please sir as you have uploaded solutions for jee advanced 2020 please upload for last 10 years solutions for jee advanced please sir I was mesmerized the level of attacking questions with basics .
A teacher😍😍 is like a candle 🕯 it consume itself to light the way of others T 🥀think outside the box E 🥀 easy goin and flexible A🥀adopted in all situation C 🥀child centred approach H 🥀hard working, committed E🥀 enthusiastic in everything R 🥀respect pupils opinion To the whole world you may be just a teacher ❤️🥀 but to your student you're a hero means a lot sirrrr 🙏❤️
Sir 🙂...these situation based questions😣 never seem easy 😮🙃before this lecture...💖💖💜💜 Thank you so much sir💜🙏 for this to the point 🤐🤓concept grasping videos...💮 And also thanks to poji💖😊😊 for extra questions...☺that helped us to clear the concept...😊
Sir onion physics ko dekhne ke baad aur proper notes banane ke baad kya concept videos dekh sakte hai bina notes banaye ya we should make notes of that also
24:22 solving this question using relative motion gives the answer of 4√3 acceleration of bolt is 12 initial velocity is 0 and the distance it have to travel is 2m using formula v=√2as. If someone know where i went wrong pls explain
sir in second condition of ball projection in wind with no gravity why we used s1=1/2at1^2 instead of s1=ut+1/2at^2 u is not even 0 in this case ,u=20m/s ???
Sir has taken the time from release of the ball till v=0 as t1 and t2 as time taken by the ball to reach the wall after the release i.e. you can think like, t1 + time taken by ball from v=0 to reach the wall=t2 So, we need to remove t1 from t2 to find the time of taken by ball to cover 120 m from v=0
@@rishitha9808rom above explanation, since, in time t2(i.e. total time), t1 was also included i.e. time taken by ball till the point where its velocity became 0. Now, when we remove t1 from t2, in new time t2` ball will reach the wall from the point v=0 which means, in time t2` we have displacement of only 120m Therefore, on solving, t2`= t2 - t1 =√2as we get t2-t1 =√24 and on adding t1 both sides t2=t1+√24 => 2+√24=> this is total time.
In S2 when we have to find midway time , there why we have added 2 , we have to find from t=0 ?? & If we don't have PG book the can we solve ill. from concept video & maine ill.
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Link for Lecture -1 : Introduction to Mechanics - ruclips.net/video/793ddiMke3E/видео.html
Link for Lecture -2 : Class 11 Physics | Motion in One Dimension #1| Onion Physics Lecture - 2 for JEE & NEET - ruclips.net/video/1C7l7ryDQHU/видео.html
Link for Lecture -3 : Class 11 Physics | Motion in One Dimension #2 | Onion Physics Lecture - 3 for JEE & NEET - ruclips.net/video/A6qWwYHXhV4/видео.html
Playlist link for complete Concept Videos of Motion in One Dimension Chapter - ruclips.net/video/gI7vOjqNAeE/видео.html
Class 12 kb start hogi
12th kab start hoga
@@udaytripathi06 26jun
HOW TO PURCHASE PHYSICS GALAXY VOLUME BOOKS. HOW MANY BOOKS AND THEIR PRICE. PLEASE REPLY SIR.
@@Sayan3112 kise pata ?
Congratulations @PhysicsGalaxy team for your ten years of selfless service .
This series is doing very best ❤️ because of the great efforts of Ashish Sir and Physics Galaxy 👍🏻
ASHISH ARORA IS SYNONYM FOR STUDIES MOTIVATION AND EVERYTHING A ASPIRANTS NEED
14:38 muje yeh smj nhi aaya ki t=0 se lena h pr sir ne t= 2 se kyu liya
@@sofialyric ball udhar tak pohochane ke liya 2s lag jayenge
mohit sir and ashish sir are blessing for student !!!!
For chemistry who is best bro??.....
@@lovelyfamily4886for theory follow unacademy bounce back by sakshi vora, and for pyqs follow avesh chemistry.
I simply do not understand who are those people who dislike these level of teaching!! Getting it for free that's why couldn't understand the value.
Bro they are sir 's motivator
Dislikers are definitely sir's neighbour or relatives..
@@MohammedAli-uv6oj can anyone please explain me that in 25.40 sir has taken acc = 10 but we have to take g-2 na because from the ground its acceleration of bott is not 10 because the elevator is also moving with 2 acce upwards so net acceleration will be 8 downwards na.Please explain
@@Artiroy19 sir said to assume as 10m/s as u if listen it carefully bro
@@MohammedAli-uv6ojthey r jealous pw students 😂
11:22 Now this is what i call advance level teaching ❤
Finally got your point.. 😙
@@AIMIIT-in2irwhat was the point
What is so special in this?
From point of projection to rest position,
Time t = u/a = 20/10 = 2 seconds
Displacement S = at²/2 = 20m
From rest position to hitting wall, this can be thought as the motion of a ball dropped from a height 'H'. So
Time of flight = √(2H/g)
Here time to reach the wall is given by T = √(2S/a)
S = 100 + 20 = 120m
a = 10m/s²
T = √(2×120)/10 = √24 = 2√6
Total time = t + T
= 2 + 2√6
We are generally taught like this in college. The exact same way.
ashish sir is as good as HCV sir at teaching physics in a very simple way....
Only this he knows an legend 🔥🔥🔥🔥thanks sir u r incomparable 🔥🔥🎉
Your teaching is on next level sir😍
in love with this series
Make video on early drop sir..
Thank you for such a great content..
Sir I am making a proper notes of Onion physics ,and yes my concepts are getting more and more clear ! Thank you sir 😌🙏❤️
bhej de bhai
I can't express how useful these lectures are for me sir
Your physics galaxy concepts videos are very helpful thank you sir
Ek like uss ashish sir k lambi umar k liye
Sir,regarding the distance vs displacement question at 28:20 :
If we carefully use sign convention, we realise that at the instant when bolt hits elevator its v is in upward direction.Which means that the bolt won't even get enough time to reach topmost point of its trajectory and then fall from there because the elevator will hit it before it reaches the topmost point.
IN SIMPLE TERMS,IN THIS CASE DISPLACEMENT & DISTANCE WOULD BE EQUAL.
Point to be noted : If the length of elevator were sufficiently larger than 2m,say something like 10m,bolt would have got chance to reach its topmost point and then fall from there. In that case displacement & distance would have been different.
This idea calls for an important question : Find the length of elevator for which its bottom would hit the bolt exactly at the instant when it is at the topmost point of its trajectory??
This boundary length,according to me,would be 6m.
Exactly and the boundary length will also be 6m as time is 1 sec
Meri toh boundary length 5m aa rahi hai and time 1sec
You are hero of all of us
Thank you sir.... you are my favourite teacher...... Love you
Thank you so much sir 💝
For this lecture
Koi inhe alakh sir se kese compare kr skta h
Alakh sir se jyada accha toh unke Batch vale teacher h Harshhh Truth
And
Ashish Sir is Just God Level....
Ab agar sch bolne pr galiya milegi toh koi dikkat nhi....
BTW Arjuna JEE Student
Real free education revolutionary 🙏
Please sir as you have uploaded solutions for jee advanced 2020 please upload for last 10 years solutions for jee advanced please sir I was mesmerized the level of attacking questions with basics .
Your request has been sent to Ashish Sir, soon he will revert on this.
@@physicsgalaxyworld thank you PG team for considering my request
SIR THANK U ISKO CONTINUE KRNA SIR PLZ BOHT ZARURAT HAI
@ 24:15
Ironman has Jarvis,
Batman has Alfred,
Ashish sir has poji😀😀
😐😐😐 I commented this first
25:52 Sir here Vb should also be negative because it is in direction of acceleration, isn't it?
U r bestest ever sir ❤️
A teacher😍😍 is like a candle 🕯 it consume itself to light the way of others
T 🥀think outside the box
E 🥀 easy goin and flexible
A🥀adopted in all situation
C 🥀child centred approach
H 🥀hard working, committed
E🥀 enthusiastic in everything
R 🥀respect pupils opinion
To the whole world you may be just a teacher ❤️🥀 but to your student you're a hero means a lot sirrrr 🙏❤️
Sir plz tell if jee2022 can also follow this series?
Yes
Great work sir
Thank you sir ❤️
Thanks a lot sir 😇😇
Sir pls bring a video of how to peepare for IPHo and IAO pls sir it is a dire need
Absolutely Brilliant.
Sir When will you bring Class 11 Ncert Short Notes?
Before this years board exams, complete class 12 NCERT SN will be uploaded and Class 11 SN will be uploaded gradually with Onion Lectures
@@physicsgalaxyworld Thanks for update. Is there something special for Physics Olympiad?
@@kritagyasharma3669 hey there.
Did you find something for it.
Can you please let me know the details .
The only onion which makes me happy
Sir 🙂...these situation based questions😣 never seem easy 😮🙃before this lecture...💖💖💜💜
Thank you so much sir💜🙏 for this to the point 🤐🤓concept grasping videos...💮
And also thanks to poji💖😊😊 for extra questions...☺that helped us to clear the concept...😊
Copypasta?
Sir please tell us the overall schedule of the syllabus
So that we can plan accordingly
Great content
legend is back
When bolt will detach from lift then only velocity will transferred to bolt ??? Will acceleration not transferred????
25:12 velocity of the bolt question:-
why didnt we use v=at since u=0 wrt the boy in elevator
please someone clear my doubt
Bhai sahab pogi to mahan hai13:40
Sir will be get the videos for class 12th before JEE 2022??
Sir can I watch it if I have completed kinematics in class 10th?? And have cengage.???
With our series it will be good if you follow theory, illustrations and practice exercises of Physics Galaxy Book.
Sir onion physics ko dekhne ke baad aur proper notes banane ke baad kya concept videos dekh sakte hai bina notes banaye ya we should make notes of that also
Sir ,plz NCERT shorts note video upload. Really we are more benifted by these SN.
Super 🎉
Sir theory ncert se cover kr skte h kya or eg bhi
Thanks sir❤❤❤❤
Sir it Should be -S2=U1t1-1/2gt1^2, the question where we are asked to find displacement
Yes thats correct
sir please start electrostatics of class 12 for the this year's class 12 students ,please sir
Really helpful
Sir please finish ncert series for physics
Because of that I am sure I will get good score in bitsat vit and state exams
24:22 solving this question using relative motion gives the answer of 4√3 acceleration of bolt is 12 initial velocity is 0 and the distance it have to travel is 2m using formula v=√2as. If someone know where i went wrong pls explain
Sir has taken initial velocity 10m/s
@@dmstudytube initial velocity is 10 but initial velocity of boult respective to observe is 0
@@dmstudytubethat's why I say solving the problem using relative motion
Same doubt mine too
THANK YOU POGIII 😃😍🥰🥰🥰
sir in second condition of ball projection in wind with no gravity
why we used s1=1/2at1^2 instead of s1=ut+1/2at^2 u is not even 0 in this case ,u=20m/s ???
Yeah, I think it should be S= ut¹ + (½at¹)²
Sir please complete advanced illustrations in physics vlog.
Concept Cleared 😶
Will sir continue NCERT NOTES series?
Yes before this years board exam complete class 12 NCERT SN will be completed and Class 11 SN will be uploaded gradually with Onion Lectures
@@physicsgalaxyworld sir please complete short notes of class 11th before jee 2022
@@physicsgalaxyworld ok
sir t 14:17 hame midway ka time nikalna hai means 70 m but sir aapne 90m ke time nikal diya kyunki 2 s 20 m wala + 70 m ka
plz.... sir answer
from starting
Sir @27:43 can we say that displacement of bolt is 2m i.e.hieght of bolt?????
I have same doubt🤔
Sir "onion physics" ka full series karne me kitna time lagega? Kya neet 2022 tak ho jayega...? Sir please reply
when will class 12 onion physics lecture start
Sir, t2 covers 120 m then how t2 -t1
Pls explain
yes same problem
sir has taken t2 from the release of the ball till it reaches the wall
But we should consider total time?.. can anybody pls explain
Sir has taken the time from release of the ball till v=0 as t1 and t2 as time taken by the ball to reach the wall after the release i.e.
you can think like,
t1 + time taken by ball from v=0 to reach the wall=t2
So, we need to remove t1 from
t2 to find the time of taken by ball to cover 120 m from v=0
@@rishitha9808rom above explanation,
since, in time t2(i.e. total time), t1 was also included i.e. time taken by ball till the point where its velocity became 0. Now, when we remove t1 from t2, in new time t2` ball will reach the wall from the point v=0 which means, in time t2` we have displacement of only 120m
Therefore, on solving,
t2`= t2 - t1 =√2as
we get t2-t1 =√24
and on adding t1 both sides
t2=t1+√24 => 2+√24=> this is total time.
bolt question is from irodov
Sir please upload in appp also ❤❤❤❤❤❤❤❤😘😘
How we find velocity of bolt in lift frame
Sir maths aur chemistry ki books bata dijiye
SIR PLEASE MAKE A VIDEO ON BLOCK STRAGEY FOR JEE MAINS 2021 STUDENTS
PLZZ SIR
Thanks Sir ,☺️☺️☺️
In S2 when we have to find midway time , there why we have added 2 , we have to find from t=0 ??
&
If we don't have PG book the can we solve ill. from concept video & maine ill.
Sir please upload next chapter's SN video for class 12
We are eagerly waiting for that🙏🙏
Till when will the series be over?
Be thankful.... ki ye aapko free me available hai
Sir please continue advance illustration 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir should we folow pg concept videos side by side? plz reply sir
Yes you can, it will strengthen your basics to a higher level...
Thank you sir🙏
Sir so all the formulas that you told us ,is the logic behind that in the formula T1=u/a we don't need to put the signs of the particular value??.?
time can never be negative
Complete 2 hours to attend and make notes from this lecture.
Aapko kitna time Laga comment hair.👇
Oo man, I thought I'm the only guy who took such a long time to make notes, you're also in my category lol 😂
@@Anonymous-me8sh even I was thinking the same & I think every student who attending this lecture is in our category.
25:16 sir apne acceleration-12 kyo nhi consider Kiya??
a=-12 in relative... Relative motion (is when we observe the motion of bolt in lift,then we need to consider reference frame is rest)..
Becuz acceleration of bold wrt ground is 10
Sir 12 bhi parallely kara dijiye
Will onion physics cover entire syllabus of 11th and 12th?
Sir onion physics ko PG app pr BHI upload kro... Hmare liye easy pdega... Aur please sir onion physics ka complete chapters coverage krna ...unlike hybrid physics.
Sir plzzz phy ka ch-1 and ch-2 😭😭 be padha dijiye ☹️
10:33 ... shouldnt it be s= ut+1/2at^2 ????
Since u is 20 and not 0
10:40
Sir you didn't consider the initial velocity while finding the displacement
How many students regularly see Onion Physics and Uneed lecture by Alakh Sir
U mean Ashish sir?
And whats uneed 😐
@@arkishchakraborty3787 Yes
Bhai sirf umeed dekho neet ke liye, jee ke liye pg video best hai
@@037bishalpattanaik6 Kuch bhi!
@@KC-ku7wh kya kuch bhi
Sir 12 ke topics KAB start honge????
🎶🎶Sir this video is not in playlist of Onion physics📑
😌
Sir NCERT exercise is important for JEE Mains?
Sir will ncert short notes be completed before jee 2022??
25:30 Sir velocity of bolt=4(sqrt3)m/s aa raha hai mera
MERA BHI
11:40 why did we take t2-t1?
did you underatood?
@@subhamoyroy7853 not really
@@sohamdas9903 oh I just figured it out t2 is basically the time between throwing the ball from hand and then accelerated by the wind to the wall
@@sohamdas9903 that's why in t2 there is already t1 taken twice so that they had to subtract t1 to get displacement for (100 + 20) m
Is this lecture sufficient for jee advanced ???
i am in class 12 should i use your pg book of class 11 as my class 11 is not strong
Situation 3 is from hcv nlm
Sir 12th kab start hoga
Please provide ncert short notes of ray optics
Bachche bas taarif karte rehte h Kuch hi sir ki Baatein sunte Hain.
DURING THE CASE OF BOLT THE TIME IS 1BY ROOT 3 THEN IT IS THE TIME ON ITS UPWARD JORNEY HOW CAN IT STRIKE THE GROUND AT THAT MOMENT
Sir ye series kb tak khatm hogi
Sir please class ki duration increase kijie 🙏🙏🙏🙏