I'm already a graduate by now. I was in fiitjee in 14-15. Didn't study sincerely so iit nai nikla. I graduated from a thik thak University, mit manipal Karnataka in ece. Currently placed in a good company since the covid situation has already decimated the job market. But aaj bhi rona aaya if I would had studied them then IIT se degree hota and I wouldn't had paid so much in fees. You know how expensive private colleges are. Padh lo juniors. You guys have golden opportunity right now.
@@alphagamerabhishek4221 no bird has eaten the harvest bro. I'm placed with a ctc at par with any average IITian Salary leaving the few who get placed in FAANG companies which anyway are handful from IIT too that too cse branch. IIT ain't end of road dude. You work hard and you can get what you want regardless of your situation. It only takes 3 months of dsa practice for 10 + lakh placement. It's upto you if you have the dedication it takes.
@@AnuMarathe13 Knowledge is not everytime about Preparing for any exam or Education . You can have a Bachelors Degree and Still be an Idiot ( Just an example not for you ) . Knowledge can't be measured So just its good to learn new things everytime .
20:23 yaha pe toh aapne sir mughe itni feel dila di ki me lecture bich me chodkar cricket khelne chala gya 😅😂😁🤣 Par kuch bhi bolo sir feel dila ne me aapse behhtar koi nhi💯💯
My phy sir did the same topic in class but in class i didnt understand a single thing.. But abj sir made everything clear as he explains each and every step but coaching teachers just skip the steps which makes it difficult to understand.. Hats off to abj sir
Sir I really thank you. It's only because of you that I am able to understand physics. It feels so good. Thank you sir🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️
Sir mai abhi kota ke sabse famouse coaching mai pad raha ho pr ye chap maine ap se pada tha pahle pr itna detsil aur itna achha Q waha bhi nahi krya gya 🦻🦻🦻🦻 bahut bada wala thanks 🤚🤚🤚🤚
Sir you are the world's best physics teacher. 🙏god of physics. M very grateful to you . Thankyou so much sir for doing this great work for us♥️ wish for your good health n happiness
sir i can not thank you enough i am really reallyyyyy grateful to have such a good physics teacher kash 11th ki starting me ap mile hote to drop nhi lena padta mujhe
@@vitaminprotein2142 his lectutes arent fit for board level either , i dont find use of his material at all, they just kill your concept and waste your tine
Excuse me respected sir please kinematics complete Karwa digiye aur lom start Kar digiye thank you in advance , but hamare request ke liye aap apna teaching style change nhi kijiyaga if these videos take time then sir you can take your time you are the best physics teacher personally apse nhi bol paunga pr from the bottom of my heart agar physics mein acha hua to all credits go to you sir
Sir kya app logo ke lectures and previous 41 years questions kar le toh kya IIT JEE ke liye accha rahega. By the way thank you for you and your team. 😊😊
In last question, i found Vx and Vy separately at time of striking and then applied tan alpha = Vy/ Vx . But on simplification, the relation does not match with what sir obtained. Can anybody explain ?
Sir last question mein velocity ka component ground to ground projection mein le sakte hai that is ucos(theta+alpha) and that will be same as of ucostheta . Kyunki max height pe ground to ground projection mein Vy=0 . So waise kar sakte hai
11:48 sir here when we derive range by using Vx*t n then put Vx=Ux+gt as n get Uxt+gt²...we dont get here the 1/2 along with gt² as there is when we use 2nd eqn instead of 1st why ?? #askcompitishun
41:30 Sir, I understand that we shouldn't remember the formulae, but understand the concept. But sir, in JEE there are just 3 hours for 90 qs i.e. half minute per question. Even if we attempt just 50 questions out of those 90, we have only around 2 minutes per question. So, keeping this in mind, should we not learn formulae? I mean, agar derive karenge to time thoda jyada jaayega na sir! Please guide!
41:23 "Macha rakkhi hai apun ne" 😆 Jokes aside, sir your method of teaching is truly spectacular. Sir aur ke baat agar Mohit sir se baat ho paati toh matlab mathematics ke liye koi practice book mil jayegi toh accha hoga... physics ke liye toh HCV aur Irodov hai mere paas aur woh solve karta hu mai But any material for Mathematics except Cengage bcs thats a bit expensive to buy, I mean the entrie volume.
1:26:22 #askCompetishun Isme hum v=u+at use kar sakte hai kya? V will be 0 as the projectile only has horizontal velocity, I tried but i am not getting the answer, please help
Actually, Vx is not = 0. Sir ne question ki wording galat likh di hai shayad, hona chahiye "horizontal to the ground", jaisa figure banaya he. Velocity ka x component zero tab he jab ground ko x-axis mane. Is video me last question ke alava sir ne sabhi me x-axis ko inclined plane mana he. Agar IP x-axis he to velocity ke do components aayenge. Fir har ek component ke liye separate equations bana sakte he.
EDIT: I spotted my calculation mistake; now I have got the exact answer. HINT: Mene components me resolve karne ke liye angle between I.P. aur velocity equal to alpha le liya tha.
@@user-3bs8jd83js i meant Vy, Vy will be zero when it is horizontal to ground, as it is not going up, I understood your different method, but i want to find out why can't we use v=u+at
@@Eclipsedcomet yes, I understood your question, just mistakenly wrote Vx instead of Vy. The velocity is horizontal to ground, not horizontal to the inclined plane. If we want to use Vy=usin(theta)-gtcos(alpha), the Vy here will not be 0, as we are calculating V from the IP. If V is calculated using the equations of ground-to-ground, we can take Vy=0 and directly apply Vy=Uy+AyT, as sir has done in the video.
@@user-3bs8jd83js thankyou very much for the explanation, I understood it now, The mistake i made is that, While using Time of flight formula, for tha angle, i used only theta, Instead i should have used theta+alpha, I noticed that because you clarified the difference between ground to ground and IP. Thankyou
Sir mene vo last wala question try Kiya tha jab aapne question try karne ke liye kaha Sir uss question me mene bhi starting ki approach vohi li thi Jo aapne Li par then mene dekh ki tan(a)=H/(R/2). a is alpha H is maximum height and R/2 is half of the range Because agar ham ye consider karenge ki projectile IP pe nhi hai balki complete projectile ko consider karenge to ye hi result aye ga Aur fir solve karne ke baad mujhe aya 8tan(a)=tan(theta+alpha) Kya ye result sahi hai sir Mujhe esa lagta hai ki ye result galat hoga kyuki agar ye sahi hota to aap ye padha Dede kyuki ye thoda simple answer hai Please anyone tell me whether is this right or wrong#askcompetishun
Neet wale kaha se aa jaate ho tumlog humlog ka dushman ho jaha iit level ki padhai hoti hai neet neet kah ke neet level ke karwa dete ho jaao physics wallah ke pass unki physics neet level ki hai aur ncert and hcv kar lo it's more than enough
![Noob To Max With DRAGON REWORK In Blox Fruits [FULL MOVIE]](http://i.ytimg.com/vi/LnBMOinoOvA/mqdefault.jpg)
I'm already a graduate by now. I was in fiitjee in 14-15. Didn't study sincerely so iit nai nikla. I graduated from a thik thak University, mit manipal Karnataka in ece. Currently placed in a good company since the covid situation has already decimated the job market. But aaj bhi rona aaya if I would had studied them then IIT se degree hota and I wouldn't had paid so much in fees. You know how expensive private colleges are. Padh lo juniors. You guys have golden opportunity right now.
Thanks bro
What is the use of repenting now when the bird has already eaten up the harvest 😜
Vishal Sharma stfu
@@alphagamerabhishek4221 no bird has eaten the harvest bro. I'm placed with a ctc at par with any average IITian Salary leaving the few who get placed in FAANG companies which anyway are handful from IIT too that too cse branch. IIT ain't end of road dude. You work hard and you can get what you want regardless of your situation. It only takes 3 months of dsa practice for 10 + lakh placement. It's upto you if you have the dedication it takes.
@@shankysays bro what is dsa that u mentioned. please reply
Just seeing your videos I have started developing intrest in physics again. Am 40 years now :) Hats off to your explanation. You are a gem
but thats not going to help you professionally, anyway...still welcome to Physics loving fraternity....
knowledge has no age
@@AnuMarathe13 Knowledge is not everytime about Preparing for any exam or Education . You can have a Bachelors Degree and Still be an Idiot ( Just an example not for you ) . Knowledge can't be measured So just its good to learn new things everytime .
@trying_to_study Then change the System .
Sir you are a amazing teacher
Iam looking for a physics teacher who ia as good as Mohit sir, and my search ends here
Which mohit sir?
arre maths mohit tyagi@@PRiNCE_X.D
@@PRiNCE_X.D mohit goenka sir eduniti
I wasted my time learning from pw un....etc...now I have found real jackpot...
Ya you are right this chanel is only for entertainment (pw) 😌
I m also regreting
@marinn wang- i am preaparing for Neet 2021 for that, we xan blindly follow this lectures or not??
@@sahilwasnik6181 yess dude,it's more than sufficient
@@sahilwasnik6181 absolutely bro..just follow him blindly and make proper notes... these are enough even for Olympiads
15:14 - 18:10 The trick for calculating angle for Rmax
I'm lucky to find this channel in beginning of prep
20:23 yaha pe toh aapne sir mughe itni feel dila di ki me lecture bich me chodkar cricket khelne chala gya 😅😂😁🤣
Par kuch bhi bolo sir feel dila ne me aapse behhtar koi nhi💯💯
55:30 Range = (root 3 -1)*2000/3 meters
My phy sir did the same topic in class but in class i didnt understand a single thing.. But abj sir made everything clear as he explains each and every step but coaching teachers just skip the steps which makes it difficult to understand.. Hats off to abj sir
Chaliye bacho has a different fan base. ......
Op sir !!!!!!!
🙏🙏🙏
Loved it 💕💕💕💕💕💕
Love you sir you are grate.... i am great fan of your..... 🤗🤗🤗🤗
Sir you are not bored telling:"Phir Galileo ki baat yaad agayi."
Because of abj sir my grip in kinematics increased more faster than corona virus
Sir I really thank you. It's only because of you that I am able to understand physics. It feels so good.
Thank you sir🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️🙇♀️
The way sir say mere pyaare bache. It feels really good ✨️❤️
Sir mai abhi kota ke sabse famouse coaching mai pad raha ho pr ye chap maine ap se pada tha pahle pr itna detsil aur itna achha Q waha bhi nahi krya gya 🦻🦻🦻🦻 bahut bada wala thanks 🤚🤚🤚🤚
Sir because of you.. I've started to develop interest in physics. Physics was my least fav subject and now it's fun doing physics. Thankyou sir. ❤
same mate i'm trying hard but its great due to his way of teaching . I will love my journey
Sir you are the world's best physics teacher. 🙏god of physics. M very grateful to you . Thankyou so much sir for doing this great work for us♥️ wish for your good health n happiness
jee aspirants be like: Sab smjh lenge.
Neet aspirant be like: Sab ratt lenge...🤣🤣
Same
As I found this channel too late but I promise that I'll do my sincere preparation from now🙏🙏
sir i can not thank you enough i am really reallyyyyy grateful to have such a good physics teacher kash 11th ki starting me ap mile hote to drop nhi lena padta mujhe
Hello bro
Bhai me 11me hu ,mere bhai ko drop year me ye teacher mile the usi ne mujhe inke bare me btaya
Bhai result update karna mat bhoolna plsss❤❤
Jee 2026 ke liye sufficient hai ye lectures? ?? 😢
Dil ek hi h kitni baar jeetoge ❤
Tumhara dil khoon se bhara hua hai. Yummy! 😋🤤
@@oreokarail😂😂
ABJ SIR IS BETTER THAN NV SIR :=}
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COMPETISHUN OP
Both are 🐯
Kahan se aate hai aeise teacher, incomparable best lecturer
Mera Dil dhak dhak hone laga jab tumne kaise 'kahan se aate hein ese teacher'😂
sir i guess 54:08 ans might be 500/root3
was wondering same thing…
Yes
Hm...Maine isliye comments khola hi tha 😂
Cool,calm nd composed ❤
Sir wedge aur pulley constraint abhi padha jaayega yaa NLM me ???
If you follow ALK sir, Mohit tyagi sir, abj sir and neeraj sir, then I am sure that you will get your dream collage
Thanks
have you been following them, Can you give a review?
And then there is Namo Kaul who proclaims himself as God of Physics 😂😂
Killer Visualisation and board level lectures 😂😂
@@vitaminprotein2142 killer visualisation and simple maths
@@vitaminprotein2142 yt pr achha content denge toh app ke through Paisa kaise kamayenge 💀
Kya mtlb wo app pr bhi khrb hi pdhate h 😂
G me daale wo apni pedagogy
@@vitaminprotein2142 his lectutes arent fit for board level either , i dont find use of his material at all, they just kill your concept and waste your tine
Greatest teacher I have ever seen love you sir
Very cool physics teacher
Excuse me respected sir please kinematics complete Karwa digiye aur lom start Kar digiye thank you in advance , but hamare request ke liye aap apna teaching style change nhi kijiyaga if these videos take time then sir you can take your time you are the best physics teacher personally apse nhi bol paunga pr from the bottom of my heart agar physics mein acha hua to all credits go to you sir
Sir kya app logo ke lectures and previous 41 years questions kar le toh kya IIT JEE ke liye accha rahega. By the way thank you for you and your team. 😊😊
mains ke liye kaafi hai
ABJ Maharaj ki JAI HO!!❤❤
I'm from Bangladesh. I used to see jee nexus and w but now i do watch tyagi sir
In last question, i found Vx and Vy separately at time of striking and then applied tan alpha = Vy/ Vx . But on simplification, the relation does not match with what sir obtained. Can anybody explain ?
Sir last question mein velocity ka component ground to ground projection mein le sakte hai that is ucos(theta+alpha) and that will be same as of ucostheta . Kyunki max height pe ground to ground projection mein Vy=0 . So waise kar sakte hai
sir maza aa gya. I love physics because of you. I'm in Aakash but no one teaches like you, feel aa jaati h aapse pdhke.
I'm also in aakash and I'm in same situation mujhe aakash m physics samajh hi nhi atti
@@vijypalruhalgmail.41com bruh another aakashian here , sala sab jagah akash m phy ghatiya hi padhate hain kya
I am in allen, muje bhi unki physics samaj nahi aati, Ig physics faculty is a problem everywhere……… (even in kota factory xD)
lol me too
@@Shataksha45
im in allen and can confirm, phy faculty is dogshit
Sir amamzing...aise hi pdhte rhe....
ABJ sir be like-: koi nhi h takkar me..😎
Dhanyawaad GURU'DEV' 🙏😇
Sir you are real gem
I was your students in resonance 2013
What a explanation
54:18 pe sir 500/√3 hoga hmax me pllzz check it and tnx for a great lesson on incline plane 🔥🔥
Haan bro
Sir bahut maja Aa ra h Kinematics me Thanku very much Sir😊😊😊☺☺☺☺☺☺☺
sir at 54:30 shouldn't the value of the max. height be 500/root3 ???
dhyan se suno sir ne bola 500 upon root 3
Yes , sir ne kehte vaqt sahi kaha he , bas likha galat he .
You are right beta.
Ha vo sir ne bola sahi likha galat 😂
Sir that trick was really helpful .thank you
Respect 📈📈
11:48 sir here when we derive range by using Vx*t n then put Vx=Ux+gt as n get Uxt+gt²...we dont get here the 1/2 along with gt² as there is when we use 2nd eqn instead of 1st why ?? #askcompitishun
Thank u so so much sir❤️❤️❤️❤️
It is literally for the first time when my all cncpt is cleared in projectile motion.
Respect 📈📈
Thank you sir ❤
Far better then paid batches
Abj sir is real God of physics
54:17, sir the answer is 500root3/3 and not 500 root 3.
yes it is 500/root3 i was also very confused
Salute to camera man who records this lecture
camera stand pe camera rakha rehta h
sir records the lectures himself by adjusting the camera.....hats off to him bruh
We are ready to learn with u Sir.....
amazing teacher
Sir in 54:35 q the range will be 500/√3 not 500√3 ??
Sir you are best teacher for all students thanks for a lot
Best explanation:-)thankyou sir
Sir do we need to learn those formulas for these special cases of projectile because I am able to solve the illustrations by using equations of motion
It's a time of waste to learn/memorise this because in exam we will fu"k it up and use wrong formula
54:16 Sir this answer should be 500/ √3 right?
yes..🎉🎉🎉🎉
41:30 Sir, I understand that we shouldn't remember the formulae, but understand the concept. But sir, in JEE there are just 3 hours for 90 qs i.e. half minute per question. Even if we attempt just 50 questions out of those 90, we have only around 2 minutes per question.
So, keeping this in mind, should we not learn formulae? I mean, agar derive karenge to time thoda jyada jaayega na sir! Please guide!
I think we should but, should know how the formula was derived just in case we forget.
3hr = 180 min , 180min / 90 = 2min /ques,
for 50question --- 180 min /50 = 3min 36 second/ question ...
3×60÷90=2 minutes
Thanks 😊 🫂
@@suryanshgarg5358 haha
And if we do 50 correctly 99 percentile is ours 😊🥺 and ** we get 3.6 mins*
Feel aa gyi sir
Sir plz electrostatics of class 12th increase frequency 🙏🙏🙏😭😭😭😭
Sir ye g cos alpha kiske responsible hai?
41:23
"Macha rakkhi hai apun ne" 😆
Jokes aside, sir your method of teaching is truly spectacular.
Sir aur ke baat agar Mohit sir se baat ho paati toh matlab mathematics ke liye koi practice book mil jayegi toh accha hoga... physics ke liye toh HCV aur Irodov hai mere paas aur woh solve karta hu mai
But any material for Mathematics except Cengage bcs thats a bit expensive to buy, I mean the entrie volume.
Questions are jee main or jee adv or olympiad level ke he ya fir
18:30 inclined projectile motion
Sir will you upload all lectures of chemistry
20:27 MSD sir bacha lenge ball ko 😂😂
sir sukhriya :)
Range for 55:19 2000(root3-1)/3
Sir you are awesome and very cool
Phir baat yaad aayi galilio ki 😁
tbh i was irritated but thankful for the lecture
1:26:22
#askCompetishun
Isme hum v=u+at use kar sakte hai kya?
V will be 0 as the projectile only has horizontal velocity,
I tried but i am not getting the answer, please help
Actually, Vx is not = 0. Sir ne question ki wording galat likh di hai shayad, hona chahiye "horizontal to the ground", jaisa figure banaya he.
Velocity ka x component zero tab he jab ground ko x-axis mane. Is video me last question ke alava sir ne sabhi me x-axis ko inclined plane mana he. Agar IP x-axis he to velocity ke do components aayenge. Fir har ek component ke liye separate equations bana sakte he.
EDIT: I spotted my calculation mistake; now I have got the exact answer.
HINT:
Mene components me resolve karne ke liye angle between I.P. aur velocity equal to alpha le liya tha.
@@user-3bs8jd83js i meant Vy,
Vy will be zero when it is horizontal to ground, as it is not going up,
I understood your different method, but i want to find out why can't we use v=u+at
@@Eclipsedcomet yes, I understood your question, just mistakenly wrote Vx instead of Vy.
The velocity is horizontal to ground, not horizontal to the inclined plane. If we want to use Vy=usin(theta)-gtcos(alpha), the Vy here will not be 0, as we are calculating V from the IP.
If V is calculated using the equations of ground-to-ground, we can take Vy=0 and directly apply Vy=Uy+AyT, as sir has done in the video.
@@user-3bs8jd83js thankyou very much for the explanation,
I understood it now,
The mistake i made is that,
While using Time of flight formula, for tha angle, i used only theta,
Instead i should have used theta+alpha,
I noticed that because you clarified the difference between ground to ground and IP.
Thankyou
Great effort sir
Goc 2 kb daloge sir
Sir mene vo last wala question try Kiya tha jab aapne question try karne ke liye kaha
Sir uss question me mene bhi starting ki approach vohi li thi Jo aapne Li par then mene dekh ki
tan(a)=H/(R/2). a is alpha
H is maximum height and R/2 is half of the range
Because agar ham ye consider karenge ki projectile IP pe nhi hai balki complete projectile ko consider karenge to ye hi result aye ga
Aur fir solve karne ke baad mujhe aya
8tan(a)=tan(theta+alpha)
Kya ye result sahi hai sir
Mujhe esa lagta hai ki ye result galat hoga kyuki agar ye sahi hota to aap ye padha Dede kyuki ye thoda simple answer hai
Please anyone tell me whether is this right or wrong#askcompetishun
at 1:16:03 sir the value of sine30
it is correct or ........
53:55 sir h=500
oot 3 aa raha h please seeee?// ABJ SIR
Sir last question me agar y ki velocity 0 kar de to nhi chalega?
But then we dont get the relation between theta and alpha cauz everything cuts off
Sir are these videos enough for neet
@@cuetcompetishun sir when will you upload lectures of bulk matter your explanation is amazing thanks
Neet wale kaha se aa jaate ho tumlog humlog ka dushman ho jaha iit level ki padhai hoti hai neet neet kah ke neet level ke karwa dete ho jaao physics wallah ke pass unki physics neet level ki hai aur ncert and hcv kar lo it's more than enough
@@Unknown120xash physics is physics be it neet or jee . If somebody wants to know more then what's wrong in that.
Don't underestimate anyone.
@@minaksheedash6383 arey tum uski baat tog suno woh puch rha h joh jee ki pdhai woh neet k liye sufficient h kya
54:08 sir answer is 500/√3
Yeah
Sir for last question I got cota+2 tana = cot theta
I am able to do these questions easily
Hat's off sir🙏🙏🙏🙏🙏
are there other methods to solve last question ??
thank you sir
sir will these formulae work if we change the x axis direction or y axis direction? or would we have to change the sign??
sir 55:00 - Hmax should be 500/rt3
and Range mai cos square alpha hoyga cos^2(alpha)
right? kuch galat toh nahi hai na? anyone... just confirm
Y
1:27:22 sir is question me velocity in y zero karke bhi solution nikal sakte hai kya
nhi
sir we can calculate the the range with the help of equation of trajectory
Same
15:14 - 18:10 The trick for calculating angle for Rmax
👍
Ux = u cos theta ke liye ax= gsin alpha kyo ?? Gcos alpha kyo nhi ?
Sir maja aa gaya
Thank u sir ❤️❤️❤️
Sir excercise sheet kaha se milegi?
At 54.22 ans of H max is 500/root3