A sinewave depicts movements in the form of waves. It has a datum, rapid, slowing and steady growth in one direction for a quarter cycle with reference to a datum (a reference), and then slow and faster decay in one direction for the next quarter cycle, and all these elements again in the opposite direction (reversal) of the forward movement for the next half-cycle. It has peaks and valleys. In essence, the sinewave is a perfect embodiment of oscillatory movements like springs and quantities like voltage. It retains its waveshape when added to another sinewave of the same frequency and arbitrary phase and is the only periodic waveform which has this property. The charges in a resistor subject to a sinusoidal voltage do not migrate elsewhere on the average. They merely slosh back and forth, so to say, over each cycle without a change in their position when the resistor was not energised. Electrostatics and circuits belong to one science not two. To learn the operation of circuits it is instructive to understand Current, the conduction process and Voltage at the fundamental level as in the following two videos: i. ruclips.net/video/TTtt28b1dYo/видео.html and ii. ruclips.net/video/8BQM_xw2Rfo/видео.html A sinusoidal voltage generator operates by separating charges for the positive half-cycle in one direction initially rapidly and slowing down and momentarily halting when its voltage is at the positive peak, and then gradually reuniting the separated charges to make the separation zero; when all charges reunite, the generator voltage is zero. The negative half-cycle now commences, when the generator operates by separating charges in the opposite direction initially rapidly and slowing down and momentarily halting when its voltage is at the negative peak, and then gradually reuniting the charges to make their separation zero; when all charges reunite, the generator voltage is zero. It then begins the next positive half-cycle followed by the negative half-cycle and the process repeats. The last frame References in video #1 lists textbook 4 which discusses these topics in more detail using a unified approach and provides an intuitive understanding of sinusoidal steady-state voltages and currents in capacitive and inductive circuits.
Please so always when the phase angle is negave you have to convert it to positive first before it can be added when it's sine function we should always add 180 and when its's cosine function we should substract 90?
Not necessarily. Wen you start adding voltages and currents with phase angles it sometimes makes it easier to add or subtract 180 degrees with either the sine or cosine functions. (Usually we use the cosine function).
The average voltage is equal to Vmax / sqrt(2), since the voltage is a sin curve. That is the mathematical result of the relationship between the average value and the peak value of a sin curve.
Thanks for the explanation. And I just wanted to ask what would we do if we had different frequencies in the different voltages. would you just take the average ?
Then you would use the superposition principle. Use each frequency to calculate the current and voltage and then add them (making sure you take the different phases into account)
This is just an exercise to add these two voltages together. From a mathematical perspective it doesn't make any difference. From a convention, we tend to use cosine
It's probably too late to ask but Can we directly convert -sin(wt-30) to positive cos by adding -90 -sin(wt -30-90) =cos(wt-120) Instead of converting it to positive sin and then to positive cos.
why the book that I bought is not the same as your answer. The answer to that practice problem is not the same as your answer. Is there some kind of typo in the book?
My teacher often writes the phasor form as something like (taking the 10 sin(...) function from your example) 10*e^(j*30). Is there a term for this other kind of phasor that uses the Euler number and imaginaries? I think it's something like the "analytic representation" of the phasor, but I'm not sure.
If I wanted to represent the resultant as in the form of Asin(wt+phi) could I then simply convert what you have shown by adding 90degrees to phi? i.e. Acos(wt+phi) = Asin(wt+phi+90)
What about addition of two term where one of the term does not have an angle, so how do we calculate the arc tan then? (One term has phi, the other does not)
can someone please explain why I get 12.3906i when I plug this into my ti89 calculator keeping the sin and cos fucntions with i kept on the sins? Like this sqrt( (10cos(60) + 20cos(45))^2 + ((i20sin(45))+(i10sin(60)^2 )
Thank you, sir. Your every tutorials is very important to me but your video scene isn't clear. so, please please please make it clear so that We can see easily and learn more and more from your tutorials.
Are newer videos are filmed in high definition, and there is a setting on RUclips when you watch videos, that can increase the resolution of your screen.
Sir, are we using rotation by j concept and converting the negetive vector v(t) = -10sin(wt-30) to positive vector . Since we multiply by j^2, are we adding 180 degrees and it becomes v(t)=10sin(wt+30+180) = 10sin(wt+210)?
Convert each to the real and imaginary parts and then add the real part together and then the imaginary parts. (you are adding 3 instead of 2, but the technique is identical)
You would typically not expect to see that in a circuit, but yes, it can be done. Here is a video (on mechanical waves) that describes how to add them. Physics - Mechanics: Mechanical Waves (11 of 21) The Interference of Waves (Same Direction) in the playlist: PHYSICS 19 MECHANICAL WAVES
Hello!Thank you for the great tutorials!You explain everything so well and comprehensively. I wanted to know if there is an e.e. textbook that you would recommend.Thanks again !Sincerely , Rick Shafer
Convert all 4 to the real and imaginary part format. Add all (4) real parts together and add all (4) imaginary parts together, then the rest is the same.
Did you make a mistake with you signs at 1:00? sin(wt-90)= - cos(wt). You should have added 90 degrees to get a positive cosine function. Please verify, Thanks.
so we’re not gonna talk about how this man is teaching us voltage with little Pickachu in the corner 🥺
Awesome explanation, thank you for going over each step and not skipping anything!
You're very welcome!
Thankoyu very much.. I was trying to understand it for 2 days but no teacher was so clear like you sir during explanation.. U helped me.. Thxx
Glad this was helpful.
I have gone through many videos but I was not able to grasp it.Only with this video,I have got grip on this topic.Really helpful.
Glad you found these videos.
Thank you so much sir.
GOD BLESS YOU.
Thank you.
Really good explanation. Just the practicalities, and no BS. Thanks a million!
You're welcome!
Best explanation I have seen with clear use of formulas for each step.
Glad it was helpful!
Thank you so much Sir, i couldnt get this when i saw it in my textbook not on till i watched this life saving video. once again thanks
You are my surrogate professor. It's so clear when you explain it.
Thank you for your comment. Glad to help.
Thanks sir.. love from India 🇮🇳🇮🇳🇮🇳🇮🇳
Thank you and welcome to the channel!
youre really the best, your explanations are precise and accurate
Soo helpful, thank you.
Thank you, this makes so much more sense than what my professor did
Glad it was helpful! 🙂
Fantastic explanation!!
Sir your explanation is marvelous 🙏🙏🙏🙏
This helped me with finding phase angle relationship. Thank you!
You are welcome. Glad you found it helpful.
*In short and less time....you do good work*
Excellent.It's very helpful to below average student.Thanks a lot Sir.
A sinewave depicts movements in the form of waves. It has a datum, rapid, slowing and steady growth in one direction for a quarter cycle with reference to a datum (a reference), and then slow and faster decay in one direction for the next quarter cycle, and all these elements again in the opposite direction (reversal) of the forward movement for the next half-cycle. It has peaks and valleys.
In essence, the sinewave is a perfect embodiment of oscillatory movements like springs and quantities like voltage. It retains its waveshape when added to another sinewave of the same frequency and arbitrary phase and is the only periodic waveform which has this property.
The charges in a resistor subject to a sinusoidal voltage do not migrate elsewhere on the average. They merely slosh back and forth, so to say, over each cycle without a change in their position when the resistor was not energised.
Electrostatics and circuits belong to one science not two. To learn the operation of circuits it is instructive to understand Current, the conduction process and Voltage at the fundamental level as in the following two videos:
i. ruclips.net/video/TTtt28b1dYo/видео.html and
ii. ruclips.net/video/8BQM_xw2Rfo/видео.html
A sinusoidal voltage generator operates by separating charges for the positive half-cycle in one direction initially rapidly and slowing down and momentarily halting when its voltage is at the positive peak, and then gradually reuniting the separated charges to make the separation zero; when all charges reunite, the generator voltage is zero. The negative half-cycle now commences, when the generator operates by separating
charges in the opposite direction initially rapidly and slowing down and momentarily halting when its voltage is at the negative peak, and then gradually reuniting the charges to make their separation zero; when all charges reunite, the generator voltage is zero. It then begins the next positive half-cycle followed by the negative half-cycle and the process repeats.
The last frame References in video #1 lists textbook 4 which discusses these topics in more detail using a unified approach and provides an intuitive understanding of sinusoidal steady-state voltages and currents in capacitive and inductive circuits.
Thank you sir your explanation process is too good 🙏 now I able to solve numericals like this...
Great! Glad it helped.
Please so always when the phase angle is negave you have to convert it to positive first before it can be added
when it's sine function we should always add 180 and when its's cosine function we should substract 90?
Not necessarily. Wen you start adding voltages and currents with phase angles it sometimes makes it easier to add or subtract 180 degrees with either the sine or cosine functions. (Usually we use the cosine function).
Can I take your class? >.
Great video. Do we need to to add 180 after finding the phase angle thru tan-1?
Typically the phase angle is expressed in values of cos between -90 and + 90 degrees.
Can you also convert it to Sine as well and work the same way? Why did you chose Cosine?
Cosine is used by convention, but yes, you could use the sin function.
damn this is so simple but all my professor did, was made this thing complicated.
thank you so much sir!!
Yes, once you see it, it becomes pretty straight forward :)
Thank you sir love from India🇮🇳🇮🇳
Thank you and welcome to the channel! 🙂
Awesome awesome awesome awesome awesome.... Y are best .....
Its today that I appreciate more the application of complex numbers.
Liked and subscribed! Excellent explanation sir.
Thank you. Glad you found our videos. 🙂
Able to explain a matter that I couldn't perceive until now, thank you
You are welcome. Glad you found our videos. 🙂
excellently explained and so straight forward. so much better than my lecturer, also love the bowtie!
Thank you. Glad you found our videos. 🙂
Thank You very much sir, May God Bless You
Sir why do we need to divide Vmax by sqrt(2) when converting from time to phasor
The average voltage is equal to Vmax / sqrt(2), since the voltage is a sin curve. That is the mathematical result of the relationship between the average value and the peak value of a sin curve.
May I know why must it be converted into cos but not sin? or it can only be solved by cos?
Cosine is used by convention since it is easier to calculate the resistance and reactance using the cosine.
thank you so much sir...I found your tutorial very helpful for me
You are most welcome
Thanks for taking the time to explain this.
THANK YOU SO MUCH SIR!! THAT WAS VERY HELPFULL,
Thanks for the explanation. And I just wanted to ask what would we do if we had different frequencies in the different voltages. would you just take the average ?
Then you would use the superposition principle. Use each frequency to calculate the current and voltage and then add them (making sure you take the different phases into account)
Using different labels for the voltages in the time domain and in the phasor domain would greatly help minimise the confusion.
will there be a case wherein we will use V_maxsin(wt+theta) instead of V_maxcos
(wt+theta)?
Traditionally we always use the cos. But we could use the sin and mathematically that is not incorrect.
Does it matter if we get an angle greater than plus or minus 90? Do we then subtract 180 degrees and use that value?
Typically that is what is done.
I like this very much tq professor
Thank you so much. Definitely subscribing and suggesting you to my friends.❤️❤️❤️
Thank you. We appreciate the support.
This is so helpful. ....thank you sir
Why we took them in cosine form? Could I use sine form?
This is just an exercise to add these two voltages together. From a mathematical perspective it doesn't make any difference. From a convention, we tend to use cosine
It's probably too late to ask but
Can we directly convert -sin(wt-30) to positive cos by adding -90
-sin(wt -30-90) =cos(wt-120)
Instead of converting it to positive sin and then to positive cos.
You can do it in any order. It is always a good idea to check. Is - sin(30) = + cos (30 - 90) ?
why the book that I bought is not the same as your answer. The answer to that practice problem is not the same as your answer. Is there some kind of typo in the book?
Probably either myself or the book made an error. (most likely me, although viewers tend to be quick to point out the error).
What about A*cos(wt)+B*sin(wt)=C*cos(wt+phi)?
My teacher often writes the phasor form as something like (taking the 10 sin(...) function from your example) 10*e^(j*30). Is there a term for this other kind of phasor that uses the Euler number and imaginaries?
I think it's something like the "analytic representation" of the phasor, but I'm not sure.
It is just a different mathematical representation, but it means the exact same thing.
@@MichelvanBiezen
I see, thank you
If I wanted to represent the resultant as in the form of Asin(wt+phi) could I then simply convert what you have shown by adding 90degrees to phi?
i.e. Acos(wt+phi) = Asin(wt+phi+90)
Yes you can do it that way.
Thank you so much for a quick reply!
Gotta love this man! Thanks sir :)
hello, sir. thank you so much for this video! It's really helped meeee thank youu🙏🙏🙏 god bless you always!
You are very welcome
God bless you sir....
Thank you
What about addition of two term where one of the term does not have an angle, so how do we calculate the arc tan then? (One term has phi, the other does not)
It makes no difference. Think of it as an angle of zero. The calculation will be exactly the same.
Awesome😎👍🏻
It's very helpful. Thank you Sir.
You are most welcome
can someone please explain why I get 12.3906i when I plug this into my ti89 calculator keeping the sin and cos fucntions with i kept on the sins? Like this sqrt( (10cos(60) + 20cos(45))^2 + ((i20sin(45))+(i10sin(60)^2 )
Do you have your calculator in radian mode instead of degree mode?
Very clear and thanks
Thank you, sir. Your every tutorials is very important to me but your video scene isn't clear. so, please please please make it clear so that We can see easily and learn more and more from your tutorials.
Are newer videos are filmed in high definition, and there is a setting on RUclips when you watch videos, that can increase the resolution of your screen.
But sir we consider equations in sine in ac
Typically we use the cos function. This is just for an exercise in case we need to know how to do this.
Sir, are we using rotation by j concept and converting the negetive vector v(t) = -10sin(wt-30) to positive vector . Since we multiply by j^2, are we adding 180 degrees and it becomes v(t)=10sin(wt+30+180) = 10sin(wt+210)?
i have the same question 😥
love it thank you! and thanks for the bow tie :D
Thank you Sir,Helped a lot
Glad it helped
GOD BLESS YOU.
Can we show how to Add 3 voltages and what if any 1 Voltage does not have an angle with it like
V1=10sin(wt)
V2=15sin(wt+45)
V3=20cos(wt-60)
Convert each to the real and imaginary parts and then add the real part together and then the imaginary parts. (you are adding 3 instead of 2, but the technique is identical)
Michel van Biezen but we don't have any angle associated with one voltage what happens to that voltage... That is V1=10sinwt
The phase angle is zero therefore v1 = 10 + j0
Why not divide by sqrt 2?
The video shows you one technique. Have you tried a different technique? Did you get the same answer?
@@MichelvanBiezen Yes, I tried both out and get the same answer.
Excellent. That is how you get a full understanding.
Is it posible to add 2 phasors with different frequencies? New subscriber here.
You would typically not expect to see that in a circuit, but yes, it can be done. Here is a video (on mechanical waves) that describes how to add them. Physics - Mechanics: Mechanical Waves (11 of 21) The Interference of Waves (Same Direction) in the playlist: PHYSICS 19 MECHANICAL WAVES
@@MichelvanBiezen Wow. Thanks a lot. You deserve millions of subscribers. I wish I could be as smart as you. Thanks again!
Thanks i understood everything
Thank you so much!
very helpful
Hello!Thank you for the great tutorials!You explain everything so well and comprehensively. I wanted to know if there is an e.e. textbook that you would recommend.Thanks again !Sincerely , Rick Shafer
Thanks sir ji
a. If v1= -20sin (wt - 600) and v2 = 20sin( wt + 450); find v1 + v2 =?
Kindly solve this
Michael sir please make more lectures on astronomy
That is the plan eventually, we are currently covering more of the electrical engineering and calculus.
2√2 cos(2t+45)+2 sin(2t)= ?
What if we have four values
Convert all 4 to the real and imaginary part format. Add all (4) real parts together and add all (4) imaginary parts together, then the rest is the same.
Thank you sir
You are welcome
This is so clutch.
You’re just making dumb things more interesting by the way you teach 😇
Thank you Sir!
Thanks a lot sir
-10sin(wt - 30), shouldnt it be -10cos(wt +30) ?, the negative sign in front of Vmax is missing????
He changed the sign of the amplitude. You need to add 180° to the phase angle before you can change the amplitude's sign
Muito obrigado!
helpful af. thanks man. :)
n vet like vir jou my boytjie
Glad you liked it. 🙂
legend
Thankyou so much
Thank you
Did you make a mistake with you signs at 1:00? sin(wt-90)= - cos(wt). You should have added 90 degrees to get a positive cosine function. Please verify, Thanks.
I don't see a sin(wt-90) at 1:00.
Thank u sir
i think it is mearnt to be -180 not +180
-180 and + 180 is the same thing.
thank you!!!
imma kiss ya bowtie guy you are saving my butt
thank u
You're welcome!
This is learned in class 8 in India
In which class do you read?
Shut up bastard. Stop mocking. This is taught in 1st year college
priceless
Glad you like our videos. 🙂
Please help in my case I am a bit dumb
😂
I'm glad to found your video!🤌💞
Welcome aboard! We are still actively adding to the EE videos and plan on covering all the topics.
Thank you so much sir
Thank you so much