Thank you Michel for this kind of teaching! I've read several different electrical engineering books and noone of them have helped me to fully understand the concepts of the subject like you explain them. I fell a tear of joy when I saw that you have more subjects in mechanical engineering such as math and physics, which I've always struggled with due to lack of deep knowledge. Thanks to your help I finally learned more in two weeks (while watching videos in 2x speed) than my 5 years of mechanical engineering studies! You are truly the Best teacher I've ever had in this subjects.
The elaboration you gave on phasor is absolutely the best and all representation, transformation and conversion have become very simple to comprehend. thank you so much... your clips are helpful and keep doing the needy
Fantastic video! I was getting so mixed up on when exactly to convert these values and how to do operations with them but your explanation made everything crystal clear! Thank you so much!
Hi Michel. Great work once again thank you for your generosity. I have an error report. Step (3 or) 4 should be (21.3 - j13)/(38+j37) which yields 0.47 |_ -75.6º.
Thank you very much for your explanation, there is a small error in the divisor, it says 38-j37, it should be 38+j37, excellent explanation, your videos have helped me a lot, greetings from Mexico
Can you multiply by the conjugate? So instead of converting numerator and the denominator into abbreviate phasor, just multiply by (38+j37) for both numerator and denominator.
the only question is around 2:53 j 45 - j 8 becomes - j 37 why is that? i thought it would be a positive result since the positive term is the bigger coefficient.
YOU SAVED ME I SPENT 3HRS ONLINE LOOKING HOW TO DO PHASOR MATH !!!
Thank you Michel for this kind of teaching! I've read several different electrical engineering books and noone of them have helped me to fully understand the concepts of the subject like you explain them. I fell a tear of joy when I saw that you have more subjects in mechanical engineering such as math and physics, which I've always struggled with due to lack of deep knowledge. Thanks to your help I finally learned more in two weeks (while watching videos in 2x speed) than my 5 years of mechanical engineering studies! You are truly the Best teacher I've ever had in this subjects.
Thank you for your kind words. We are glad we were able to help.
@@MichelvanBiezen 5 years later you're still helping :) Thanks!
Same Here, 4 months after the 5 years ;), appreciate the help as a sophomore comp engineer. Have a good day
The elaboration you gave on phasor is absolutely the best and all representation, transformation and conversion have become very simple to comprehend. thank you so much... your clips are helpful and keep doing the needy
Thank you. Glad you found our videos. 🙂
@@MichelvanBiezen IMHO Michel, you're the GOAT of teaching. Majok accurately described your lectures, which is why you are the goat
This explanation is definitely the best explanation I came across so far. Thank you so much
You're very welcome! Glad you found our videos. 🙂
Phasor algebra made AC a piece of cake for me.Thanks a lot, subbed :)
Thanks for the sub!
Fantastic video! I was getting so mixed up on when exactly to convert these values and how to do operations with them but your explanation made everything crystal clear! Thank you so much!
Thank you. Glad you found our videos. 🙂
Since the denominator should have been 38+j37, should the answer be 0.47∠-75.6 instead?
I got 2.88 ∠12.84degress
same dude. -j^218 should equal to +18 since j^2 = -1 and by substitution, -1(-1)(18) should be 18
I also got the same
Yeah 38+j37
what happened to the y^2
This is quite helpful. I was confused by these phasor calculations.
Thank you very much
Spent a whole week trying to understand this
Glad you found these videos helpful! 🙂
Thank you for helping me doing my exam! extremely helpful, clear explanation!!!
Glad it helped! Hope you did well on your exam. 🙂
thank u soooooo much u saved my day i was searching everywhere but where have u been thank u sooooooooooooooooo much again :D
Glad we were able to help!
Isn’t +j37, not -j37 since you were adding -j8 +j45 = j(-8+45)= j37 ??
Yes, you are correct. That should be +j37. Thanks for pointing that out.
Ya that's what, so the ans will change
Hi Michel. Great work once again thank you for your generosity. I have an error report. Step (3 or) 4 should be (21.3 - j13)/(38+j37) which yields 0.47 |_ -75.6º.
Thanks for your comment. Yes the error is noted right on the thumbnail of the video.
Thank you very much for your explanation, there is a small error in the divisor, it says 38-j37, it should be 38+j37, excellent explanation, your videos have helped me a lot, greetings from Mexico
Yes, you are right Note the comment in the title.
@@MichelvanBiezen What a shame, professor, I saw it from the beginning but I didn't understand what it meant, I'm sorry.
Thankyou for sharing this trick sir big thank from India
Glad you found our videos. Welcome to the channel! 🙂
Really very helpful! Was confused from a long time in these calculations.
Glad it was helpful!
thank you, Michel, so much. you don't know how lost I was until I saw your video.
me too
I understood the calculation very well now, thank you sir.
Glad you found our videos.
i love you so much, i hope you have an amazing day. i finally understand whats going on, i am so overwhelmed with love right now i could start crying
Thank you. Glad you found our videos and you found them helpful. 🙂
Thanks sir
Your all videos are very very useful
50 minutes to exam but you saved my a** T_T thanks ;D
Hope you did well.
@@MichelvanBiezen yes will definitely score above 90% ;D
thanks prof, I've learned a lot !
You are welcome!
Alhamdulillah বুঝতে পারছি 😊😊
Thank you so much!
Awesome explanation
Glad it was helpful!
Can you multiply by the conjugate? So instead of converting numerator and the denominator into abbreviate phasor, just multiply by (38+j37) for both numerator and denominator.
Try it and see if you get the same answer.
Yep, it works!
That is how we learn. Thanks.
I would have done the conjugate aswell
bang makasih bang yak udah bantu UAS gua sehat2 trs bang
Glad the videos were helpful! 🙂
@@MichelvanBiezen sumpah makasih banget bang aku juga berhasil uasnya
I'm very thankful for you 👌
So nice of you
Very nice solution.thank you sir
Most welcome
Just loved it!
thanks Michel for the video I have learned more
Thank you so much for this !!!!
You are welcome. 🙂
the only question is around 2:53 j 45 - j 8 becomes - j 37 why is that? i thought it would be a positive result since the positive term is the bigger coefficient.
Yes that is an error. (Notice the note in the video title). That is a good catch.
Tq very much professor
Best video ever
Where did the j^2 go from the first example
Not sure what you mean by "the first example".
@@MichelvanBiezen sorry i didnt watch the full video so I thought there was more than one problem.
THANK YOU
You are welcome. 🙂
Thank you!!!
You're welcome! Glad you found our videos! 🙂
thank you
You're welcome
where did the -j^2 disappear to?
j x j = -1 therefore - j^2 = + 1
Very useful.. thanks
Thanks!
I think the answer is 0.47 angle 75.6 degrees
Note the correction in the title. Thank you.
Slight mistake when calculating denominator, should be 38+j37 and it changes the end result
Yes, (that is why we have the note in the title of the video).
Thank you so much
sir - ki place pr +aaega
1+j 1.0 angle cos inverse (0.85)×1.75 .. how to calculate
isn't the denominator sir 38+j37 instead of "38-j37"? Please elaborate it, because i am getting confused here.
You are correct. (see comments below)
thanks sir
Thanks!
Welcome!
the answer should be 0.47
thanks sir
You are welcome.
Sir, -j8+j45 should be j37 not -j37
yes, you are correct.
Thank you
Welcome!
Thanks.
You are welcome. 🙂