(a-1)/a using in 1st 3 fraction gives 4 -( 1/2023+1/2024+1/2025)+ 3/2022 which is very obvious greater than 4 as 1/ 2022 is greater than any 1/ fraction.
Let x=2022 then the left-hand number can be expressed as (1-1/(x+1))+(1-1/(x+2))+(1-1/(x+3))+(1+3/x) which is greater than 4 since 3/x > 1/(x+1) + 1/(x+2) +1/(x+3).
Correction: 6.16
3/2022=1/2022+1/2022+1/2022 (not multiplication each)
(a-1)/a using in 1st 3 fraction gives
4 -( 1/2023+1/2024+1/2025)+ 3/2022 which is very obvious greater than 4 as 1/ 2022 is greater than any 1/ fraction.
It's -3(1/2023+1/2024+1/2025) not -4
Let x=2022 then the left-hand number can be expressed as (1-1/(x+1))+(1-1/(x+2))+(1-1/(x+3))+(1+3/x) which is greater than 4 since 3/x > 1/(x+1) + 1/(x+2) +1/(x+3).
Cauchy-Schwarz?