Spectrophotometry | Beer-Lambert Law.

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  • Опубликовано: 1 окт 2024

Комментарии • 96

  • @AliHayek
    @AliHayek  6 лет назад +50

    I hope you find this video helpful. Please note that the answer at 5:25 is 5.0 x 10^(-3) and not 5.0 x 10^(-2) as it is shown in the video. The preparation for such videos takes lots of time and sometimes small mistakes like this slip easily. Enjoy!

  • @jackyllerena5336
    @jackyllerena5336 7 лет назад +30

    Woah, everything was so clear. This video is those kinds of videos where you can pause on a certain time and have all the information you need neatly placed with explanations and everything.
    Thanks man :D

  • @shivammkhare
    @shivammkhare 5 лет назад +5

    I am watching this in 2018, you are really great Sir, Good explanation, you deserve million subscribers but it's sad nowadays people wants to watch only Crap, youth is destroying their Time & Career.

  • @shadowwhitehart9190
    @shadowwhitehart9190 6 лет назад +5

    Time point 5:33, I think there is a mistake: 0.5 and not 5.0

  • @khinmyatthu9289
    @khinmyatthu9289 Год назад +1

    Hello Dr. Hayek,
    Thank you very much for this video. The explanation is clear, well-organized, and getting on point, which helps me a lot. I have a few questions. Is there any chemical relation between the concentration of the samples and the incident light emitting or absorbing? I am getting unstable absorbance values with measurements at low concentrations but not at high concentrations. This finding is also beyond the understanding of Absorbance = logarithms of transmission though my values are at 0.1% of T. or could you please enlighten me on the keywords I could find for the articles? Thanks a lot.

    • @AliHayek
      @AliHayek  Год назад

      Hi there,
      Light-matter interaction is a known phenomenon. Sometimes it does not affect the structure of the matter, but some other times light can be aggressive and provides enough energy to break weak bonds. If the absorbance is not stable or keeps changing, it could be that the light is transforming the matter into something that interacts less/more with light. It is a broad topic. I hope this will allow you to start your search. Best of luck.

  • @1babyflix
    @1babyflix 6 лет назад +5

    Really clear and easy to follow explanation. Good job.

  • @isaiaharchibald4438
    @isaiaharchibald4438 7 лет назад +7

    great video but the answer is 5.0 x 10-3 not 5.0 x 10-2. the video really help me thanks btw.

    • @debasishmajhi687
      @debasishmajhi687 7 лет назад

      WATCHDATFREE u know right that calculators of different types gives different value if u don't know then Google it

    • @kelw5787
      @kelw5787 6 лет назад +1

      Yeah I calculated this as well and when I heard it was 5.0 x 10-2 I was confused about what I did wrong xD

    • @rahullovesthepayne8690
      @rahullovesthepayne8690 6 лет назад +1

      i thought i was the only one lol

  • @karanmakwana5129
    @karanmakwana5129 6 лет назад +2

    Thank you so much I was facing problems in this topic but now all is clear

  • @marzenasemaj7204
    @marzenasemaj7204 2 года назад +1

    You explained it really fast and clear. Thank you for this video it will help me in a labolatory!

  • @PHYSICSINSIGHT
    @PHYSICSINSIGHT 4 года назад

    watch this uv visible spectroscopy is explained very briefly...
    @

  • @v.c.jayaramaiah4815
    @v.c.jayaramaiah4815 3 года назад

    more simple calculation of perceent transmittance or OD vaalues in to Percentage will be more useful for basic chemistry students, videos explainigncalculations msy not be available

  • @KulbirAhluwalia
    @KulbirAhluwalia 6 лет назад +2

    Awesome video sir! Thank you!

  • @tarkeshkandregula6559
    @tarkeshkandregula6559 7 лет назад +2

    thank u so muchh.. such a good video :)

  • @esraatarek953
    @esraatarek953 3 года назад

    Thanks very much for this helpful video.
    But I wanna ask about the references, please?

  • @md.ibrahimkhalil6011
    @md.ibrahimkhalil6011 6 лет назад +1

    Nice informative video. Thank you very much for sharing with us.

  • @SquatBenchDeadliftz
    @SquatBenchDeadliftz 6 лет назад +1

    Very helpful video. Easy to understand. Thanks.

  • @ramamukumbi5566
    @ramamukumbi5566 8 лет назад +3

    man you do a good job thx
    keep up good work ;)

  • @Isaac-ru5jb
    @Isaac-ru5jb 6 лет назад +1

    Really good video! helpful and informative and easy to understand, really good job! thank you so much!:)

  • @ipekkocaoglu9482
    @ipekkocaoglu9482 4 года назад

    Hello the video is wonderful.
    I can not understand one thing which is when we look the transmittance vs wavelenght graph, why do we observe this shape or when we look the absorption vs wavelenght graph, why do we observe this shape?
    Thank you so much

    • @AliHayek
      @AliHayek  4 года назад +1

      The best way to think about it is that for the absorption spectrum, the higher the intensity of the peak, the more the light is being absorbed by the solution. Now if you think about it in terms of transmittance. The more the light is absorbed, the less of it will transmit. So transmittance measures how much light is going through the solution. So the lower the peak, the lower the percentage of light transmitted. In a simpler way, the transmittance spectrum is the opposite of the absorption spectrum. I hope it is clear now.

  • @khinmyatthu9289
    @khinmyatthu9289 Год назад

    Thank you very much. It is really appreciated.🙏

  • @loyalty6495
    @loyalty6495 3 года назад +1

    The explanation was helpful, thank you

  • @MrAbdalla1996
    @MrAbdalla1996 6 лет назад +1

    THANK U VERY MUCH
    THE DIAGRAM WITH DESCRIBTION IS VERY USEFUL

  • @saraherself98
    @saraherself98 7 лет назад +1

    Thank you so much ..a very good video :)

  • @aashnagurjar2477
    @aashnagurjar2477 7 лет назад +2

    thnq so much sir

  • @alokneet
    @alokneet 6 лет назад +1

    You are doing excellent job. A little humor will make it perfect.
    Can you tell me what software you are using for making these videos.

    • @AliHayek
      @AliHayek  6 лет назад

      +BioMania thank you. I use screenflow

  • @jeevaniroyal8407
    @jeevaniroyal8407 6 лет назад +1

    Gud lecture sir and I have few queries regarding biotechnology

  • @debasishmajhi687
    @debasishmajhi687 7 лет назад +1

    Video was very helpful sir thx a lot

  • @shubhambhosale4723
    @shubhambhosale4723 6 лет назад +2

    Good one bro

  • @dancemabu6341
    @dancemabu6341 7 лет назад +1

    very good my man,u explain nicely

  • @jeevaniroyal8407
    @jeevaniroyal8407 6 лет назад +1

    Gud lecture sir gathered more information

  • @TemeraireBjartskula
    @TemeraireBjartskula 6 лет назад +1

    I have a test about this next week and truth to be told, I did not understood a thing about it, this video helped me to clear it all up so thank you for taking the time to make this. It was really helpful!

    • @AliHayek
      @AliHayek  6 лет назад +1

      +LuciferHasPinkSparklyWings you are more than welcome.

  • @shrishantroy2494
    @shrishantroy2494 3 года назад +1

    Wow. Great explanation

  • @TheDina132
    @TheDina132 3 года назад +1

    Thank you! It s so easier!

  • @whats1983
    @whats1983 2 года назад

    I am watching from Uzbekistan. How can I contact you?

    • @AliHayek
      @AliHayek  2 года назад

      Go to www.alihayek.com. 👍

  • @michaelseraphim1056
    @michaelseraphim1056 2 года назад

    You really saved my life. God bless your heart . Thank you so much for sharing your brilliant knowledge 😊 🙏

  • @pseudomonas69
    @pseudomonas69 7 лет назад +1

    bruh you deserve an emmy for this vid

  • @manuelperezruizdiaz9418
    @manuelperezruizdiaz9418 6 лет назад +1

    thanks, that's was great it was very helpful

  • @sajamas5766
    @sajamas5766 7 лет назад +1

    راااائع جد..نريد المزيد من الفيديو

  • @dr.pratikk8930
    @dr.pratikk8930 5 лет назад

    Best video on Beer lamberts law...
    Thanks
    And keep making such videos

  • @vicentesayson2990
    @vicentesayson2990 4 года назад

    Good day sir, is the molar coefficient is a constant given per chemical substance or it's something that we can compute too?
    I am wondering how am I be able to get the Molar Coefficient of unknown Species and Unknown Concentration, that is present in the water for example lake. This is for spectrophotometer experiment, I can only get the Absorbance and Transmittance but not the
    Concentration and Molar Coefficient

    • @AliHayek
      @AliHayek  4 года назад

      In your case you will not be able to determine the concentration or molar extinction coefficient. You will need one of them known to determine the other.

  • @bharathibharathisekar484
    @bharathibharathisekar484 3 года назад +1

    Tq,sir

  • @aayataltamimi9325
    @aayataltamimi9325 6 лет назад +1

    Amazing explanation. Thanks a lot!

  • @anastaciamodo8273
    @anastaciamodo8273 6 лет назад +1

    well presented Shukran

  • @nouralrefahi6000
    @nouralrefahi6000 6 лет назад +1

    بس لو بالعربي كان فهمت

  • @Edmerls
    @Edmerls 6 лет назад +1

    Nice

  • @tiibrahim5714
    @tiibrahim5714 6 лет назад +1

    Wow! I really appreciate it Sir

  • @rabiadegia4361
    @rabiadegia4361 6 лет назад +1

    lovely explanation thank you!

  • @domlehane2819
    @domlehane2819 7 лет назад +1

    thank you very much mate!

  • @kourosh61
    @kourosh61 7 лет назад +1

    Answer is 5 x 10^-3

  • @premalathagattu907
    @premalathagattu907 3 года назад

    Sir how find (£)coficiant value
    Please reply

    • @AliHayek
      @AliHayek  3 года назад

      This is explained in details by the end of the video. This is the only way to find epsilon. Good luck.

    • @premalathagattu907
      @premalathagattu907 3 года назад

      @@AliHayek thank you sir it is very useful video

  • @adanalvarez6830
    @adanalvarez6830 4 года назад

    dude please make more chemistry videos.... every second of the video had a purpose.

  • @adeelbashir5847
    @adeelbashir5847 6 лет назад +1

    nice work sir

  • @Starwave...3821
    @Starwave...3821 7 лет назад +1

    Very good video

  • @nick1f
    @nick1f 7 лет назад

    Is I0 actually the intensity of light as read by detector when a sample of pure solvent (water) is placed in the cuvette?

    • @AliHayek
      @AliHayek  7 лет назад

      Nick F yes it is indeed. And this is called the blank and it is used for the background noise correction.

  • @sylviaemejuru1956
    @sylviaemejuru1956 4 года назад

    Thank you very much Sir

  • @mohammedabdalla8077
    @mohammedabdalla8077 Год назад

    Nice and very useful

  • @ericmanso7355
    @ericmanso7355 7 лет назад +1

    nice

  • @lamp1215
    @lamp1215 6 лет назад +1

    JazakALLAH

  • @sanaafreen1937
    @sanaafreen1937 6 лет назад

    At 2:54 % transmittance is denoted as %T and also in last line as A. Didn't get it. Please explain

    • @AliHayek
      @AliHayek  6 лет назад

      If you read carefully the last line says that the absorbance (A) can be given in terms of (%T) and the expression is given. I hope this helps.

  • @EJ-qs6qh
    @EJ-qs6qh 5 лет назад

    fantastic!! thank you. very clear and perfect pacing.

  • @samscience444
    @samscience444 5 лет назад

    helpful video thaaaaaank you so much

  • @yogitavarshney3268
    @yogitavarshney3268 6 лет назад

    Please upload beer law for mixture

  • @binteabdul6107
    @binteabdul6107 5 лет назад

    tx for uploading very helpful

  • @binteabdul6107
    @binteabdul6107 5 лет назад

    tx for uploading very helpful

  • @jamespandiannaraj5744
    @jamespandiannaraj5744 8 месяцев назад

    Excellent lecture

  • @mustaphaaliyumuhammad4656
    @mustaphaaliyumuhammad4656 3 года назад

    thank you sir

  • @edusmart1126
    @edusmart1126 5 лет назад

    thanks, you are really great sir

  • @dannyjean-noeluppiah8270
    @dannyjean-noeluppiah8270 3 года назад

    Great explanation! 👍🙏🙏

  • @piyushsen7502
    @piyushsen7502 6 лет назад

    Thanx bro it really helpful

  • @oumarshah1335
    @oumarshah1335 2 года назад

    Outstanding

  • @abdullahshahnawaz6585
    @abdullahshahnawaz6585 5 лет назад

    Thank you

  • @niranjanavadivel7388
    @niranjanavadivel7388 6 лет назад

    Nice explanation Ali Hayek

  • @knowledgejunction1643
    @knowledgejunction1643 5 лет назад

    Suuuupppppeerrrrr

  • @tharunstar1554
    @tharunstar1554 5 лет назад

    Super

  • @noorikhan2974
    @noorikhan2974 5 лет назад

    Thank u so much sir

  • @fatimasaleh9301
    @fatimasaleh9301 5 лет назад

    Love this video

  • @alysonbechtum6999
    @alysonbechtum6999 5 лет назад

    :)