As the current in the inductor ramping up with time after 9 sec that current must exceeds 9 A which tells that n side of the diode voltage is greater then 9 v slightly which eventually make diode to turn off that mean drop across diode is 0 ? If that is true then drop across inductor become 0v which makes current through inductor also 0A according to the equation of inductor?
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As the current in the inductor ramping up with time after 9 sec that current must exceeds 9 A which tells that n side of the diode voltage is greater then 9 v slightly which eventually make diode to turn off that mean drop across diode is 0 ? If that is true then drop across inductor become 0v which makes current through inductor also 0A according to the equation of inductor?