Can You Solve This Amazing Radical Equation? | Algebra

[@morriswangmonroewine2128]

2x=a, 3x=b

[@Shobhamaths]

Take lcm then
Let a=√(4+1/x^2), b=√(9-1/x^2)
a^2=4+1/x^2
b^2=9-1/x^2
a+b=5
a^2+b^2=13
a-b=±1
(a, b) =(3, 2), (2, 3)
x=±1/√5👍

[@Quest3669]

X#0;-1/3 hence x= +-1/√5

[@潘博宇-k4l]

X=(5)^(1/2)/5, -(5)^(1/2)/5.

[@gregevgeni1864]

x = ±√5/5

[@RealQinnMalloryu4]

2^2x^1+1/1x^1+x+3x ➖ 1/x 1^2x^1/x+x+3x ➖/x 2x/x+x+3x ➖ / 23 (x ➖ 3x+2). 5^5x/3x+1 2^3^2^3x/1x+1 2^1^1^3x/x+ 2^3x/x+ (x ➖ 3x+2)