Ukraine l Very Nice Olympiad Math Radical Problem l m=?

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  • Опубликовано: 3 янв 2025

Комментарии • 10

  • @NadirMemon-hk7ki
    @NadirMemon-hk7ki День назад

    ❤❤❤❤

  • @BrijLalSahu-bb1lu
    @BrijLalSahu-bb1lu День назад

    Very nice @MATHS TUTORIAL (BL SAHU)

  • @wes9627
    @wes9627 2 дня назад +1

    Thinking outside the box, 49-9=40. 7^{√m/2}=7^2, so √m/2=2 or √m=4 or m=16.
    Check: 7^{√16/2}=7^{4/2}=49, 3^{√16/2}=3^{4/2}=9, and 49-9=40

  • @jonathancapps1103
    @jonathancapps1103 2 дня назад +2

    If m is an integer, u = (√m)/2, and x = 7^(u/2), must x be an integer? Maybe I just need caffeine, but that's the only step I can't follow.

    • @Krauzer33
      @Krauzer33 2 дня назад +1

      Same question here, i don't understand that restriction. Also why in 11=7^(u/2) solution impossible? If you can not calculate it in your head, that doesn't mean that you can't calculate it at all

  • @nasrullahhusnan2289
    @nasrullahhusnan2289 2 дня назад +1

    Note that 40=49-9
    =7²+3²
    =[sqrt(7)]⁴-[sqrt(3)]⁴
    It is clear that m=16

  • @novellobrancher9627
    @novellobrancher9627 2 дня назад +1

    👏👏👏and..happy good year!

  • @АндрейАнцышкин
    @АндрейАнцышкин День назад

    😊m=4 моментально

  • @ghlscitel6714
    @ghlscitel6714 8 часов назад

    M=16