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Wonderful 👍👍👍

Teşekkürler

Teşekkürler

Mieux vaut de mettre les deux côtés au carré dans un premier temps je pense

n is 3 hhhhh

👍

3×b=b^3; b^3-3×b=0; b(b^2-3)=0; b(b+sqr(3))(b-sqr(3))=0; b1=0, b2=-sqr(3), b3=sqr(3).

Nice and more basic solution , very well explained with all steps!! I did it with complex numbers which has more pitfalls... fortunately i arrived at the correct result.

Delighted!!!

Я там немного не понял - демона всё таки аызвали в конце ?

I don't know why people think turning succinct logs into a bunch of fractions that still have logs in them is simpler. Why introduce potential arithmetic errors in "simplifying" a log, when the calculator does not care at all and works just as well either way.

6^x(1+1)=120 6^x=120/2=60=6×10 log6^x=log6×10 X=log6+log10/log6 X=log6/log6+1/log6 X=1+1/log6

9^k(1+1+1)=999 9^k=999/3=333 3^2k=333 log3^2k=log3×111 2klog3=log3+log111 K=log3/2log3+log111/2log3=1/2+log111/2log3

2^x+1=3^x log2^x+1=log3^x X+1log2=xlog3 X+1/x=log3/log2 X/x+1/x=1+1/X=log3/log2 1/X=log3/log2-1 X=log2/log3-1

x=log60/log6=(log6+log10)/log6≈(0.778+1)/0.778≈1.778/0.778≈889/388≈2.2853. Deviation is about 0.0002.

3^(x + 1) - 3^(x - 1) = 6 3^(x - 1) [9 - 1] = 6 3^(x - 1) = 6/8 = 3/4 (x - 1) = log(3/4)/log(3) x = 1 + [log(3/4)/log(3)] = 2 - [log(4)/log(3)]

Boring

9^k + 9^k + 9^k = 999 3*9^k = 999 1/3 * 3 * 9^k = 1/3 * 999 1 * 9^k = 333 (3^2)^k = 333 3^(2k) = 333 3^(2k) / (3^2) = 333 / 3^2 3^(2k - 2) = 333 / 9 3^(2k - 2) = 37 log(3^[2k - 2]) = log(37) (2k - 2)*log(3) = log(37) (2k - 2)*log(3)/log(3) = log(37)/log(3) (2k - 2)*1 = log_3(37) 2k - 2 + 2 = log_3(37) + 2 2k = log_3(37) + 2 2k/2 = (log_3[37] + 2)/2 k*1 = (log_3[37] + 2)/2 k = log_3(37)/2 + 2/2 k = log_3(37)/2 + 1

I liked. Congratulations!

Your videos are simultaneously too simple and way too complicated all at the same time. It just looks like you’re adding extra steps by constantly multiplying both sides needlessly at times. Explaining would go a long way here. Otherwise this is useless from an educational perspective and only serves to mildly entertain the people who can already solved these…. Who are very few. It would also help if you didn’t use this terrible music on repeat. Had to mute the video 30 secs in. It’s torture.

Didática show!

I just fast forward the vid all the way to the end for the answer.

to easy to watch

3

Решил за 30 секунд,прям спидран

X^4X^2X

Wonderful!!!

Good

aa - b = 133, bb - a = 133; a = ?, b = ? * aa - b = 133 = 144 - 11 = 12x12 - 11 ** bb - a = 133 = 121 + 12 = 11x11 - (-12) *** a = -12 , b = 11./.

aa = b + 13, bb = a + 13; a = ? b = ? * aa - b = 13 = 16 - 3 = 4x4 - 3 ** bb - a = 13 = 9 + 4 = 3x3 - (-4) *** a = -4, b = 3./.

XX - XY = 28, YY - XY = 21. XY = ? *. 28 = 16 + 12 = 4x4 + 12 ** 21 = 9 + 12 = 3x3 + 12 *** XY = 12 ./.

XX - Y = 73, YY - X = 73; X = ? , Y = ? * 73 = 81 - 8 = (9x9) - 8 = XX - Y 73 = (8x8) + 9 = (8x8) + 9 = YY - (-X) ** X = -9 , Y = 8./.

Excellent teacher! Thank you!!!

Maths olympiad and someone is winding and unnecessarily long

√18 + √12 + √6 = 3√2 + 2√2 + (√2)(√3) = (√2)(5 + √3) √18 - √12 + √6 = 3√2 - 2√2 + (√2)(√3) = (√2)(1 + √3) (√18 + √12 + √6)/(√18 - √12 + √6) = (5 + √3) / (1 + √3) = (5 + √3) (√3 - 1) / 2 = 2√3 - 1 (2√3 - 1)^2 = 13 - 4√3 (2√3 - 1)^3 = 30√3 - 37 (2√3 - 1)^4 = 217 - 104√3 (2√3 - 1)^7 = (30x217 + 37x104)√3 - (37x217 + 90x104)

Sbagliato

Way too many steps. Tedious.

soluzione raffinatissima👍👍

Well. Do now replacing 32 by i.

[(√3 + √2 + 1)/(√3 - √2 + 1)]⁷

5^a*5^a=50 5^(a+a)=50 5^(2*a)=50 5^2^a=50 25^a=50 |log both sides log(25^a)=log(50) a*log(25)=log(50) a=log(50)/log(25) It is not worth transforming any further because calculating each log requires the same effort. What is more, you can use a logarithm with any base

Hello, what that mesns on B/S. Thanks a lot for all your well done. ❤

Ridiculous

talent showing the method solving the problems.

Marvelous!!!

gREAT.

Brillante soluzione, coinvolgente!👏👏👏

Anybody tell me what the background music is?

B/s 😂

Made a simple equation a super complicated one!🤦🏻‍♀️