Javascript Freecodecamp Algorithm #32: Implement Selection Sort

[@GraceandWisdom]

Thank you for this awesome tutorial, Justin!!

[@masikajenniffer6473]

Good explanation, thank you

[@adamdreier]

I wrote it this way, way less variables.
selectionSort = (array) => {
if(array.length === 0) return;
if(array.length === 1) return array;
for(let i=0; i < array.length; i++){
for(let j = i + 1; j < array.length;j++){
if(array[i] > array[j]){
[array[i],[array[j]]] = [array[j],[array[i]]]
}
}
}
return array;
}
console.log(selectionSort([1, 4, 2, 8, 345, 123, 43, 32, 5643, 63, 123, 43, 2, 55, 1, 234, 92]))

[@andreluizmontanari7886]

Thank you!

[@franciscogarrido9742]

Thank you!!!!

[@cmdv42]

💯

[@hangor3620]

Great explanation

[@julienaz2274]

Love this content !

[@user-gx6mo6nj5i]

thank you!! i really like your video~~~~~~!!!!~!~!~

[@cinquain0]

Great

[@hellofriend3091]

Please don't stop uploading

[@kevin-johar]

To make it a pure function don't you need a deep copy, not a shallow copy as you've said?
EDIT: it seems primitive data types are copied by value not reference when using slice, whereas objects are copied by reference and therefore would stop this from being a pure function!

[@wonjaehwang7670]

11:03, I was wondering how you are making changes to the arr variable when you're not specifying it... ? Specifically you're doing [arr[x], arr[x]] = [arr[x], arr[e]]. Aren't you supposed to reassign at least?

[@rutwickgangurde3247]

That's JavaScript array assignment, you can even assign variables similarly.

[@nonipaify]

Hello Kim,
Hope you are doing great. I have understood the selection sort and I have managed to make it work by setting the min variable to the index rather than the actual value, however, I do not understand why the alternative approach which is what I came up with on my first try, does not work. If you have the time, please point out the mistake causing the following code to not work for selection sorting:
function selectionSort(array) {
for(var i = 0; i < array.length; i++){
var min = array[i];
for(var j = i+1; j < array.length; j++){
if(array[j] < min){
min = array[j];
}
}

var temp = array[i];
array[i] = min;
array[array.indexOf(min)] = temp;
}
return array;
}
console.log(selectionSort([5,2,6,1,10]));

[@rokassimkus2397]

Even though it's been a year I will answer you are setting min to array[i] (array[i] = min;) and thats why you get wrong index, just add one more temporary variable after var temp. Something like const minIndex = array.indexOf(min);

[@nonipaify]

@@rokassimkus2397 thanks a lot for the help :) it's funny how quickly a year has passed. I was watching this when I was getting started as a self taught dev. I'm working full time as full stack js dev today 😁👍

[@hebanano]

@@nonipaify I'm self learning too, came across this channel today to learn Data Structures and Algorithms. Your comments is so motivating.

[@nonipaify]

@@hebanano I'm glad you found it motivating. Good luck on your journey and don't forget these two key things that I learnt:
-keep building something/avoid tutorial hell
-dont be afraid to apply for job (if that is your goal). Don't think your "not good enough yet"

[@322fra5]

heyy, what does j++/i++ stand for? ty for your answer

[@AngleCoding]

You are incrementing those variables by 1. I suggest checking out intro to JavaScript tutorials on the “for” loops!

[@navjotsingh2251]

Example : j++ is short hand for j=j+1

[@lolonoob9874]

terrible teaching, didnt learn anything