Consider a joint between two rigid bodies. Each rigid body has m degrees of freedom ( m = 3 for a planar rigid body and m = 6 for a spatial rigid body) in the absence of any constraints. The joint has f degrees of freedom (e.g., f = 1 for a revolute joint or f = 3 for a spherical joint). How many constraints does the joint place on the motion of one rigid body relative to the other? Write your answer as a mathematical expression in terms of m and f. How to solve the problem
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Sir type 2 sum ku method 1 use panala sir -36 _____________ | 2/3 | -18/3 | ____________ -16 X+2/3, X -6 3x + 2 , X-6 By 3 epdi na x² munadi erukura number
Ans is: (3x + 2) (x - 6)
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Consider a joint between two rigid bodies. Each rigid body has m degrees of freedom ( m = 3 for a planar rigid body and m = 6 for a spatial rigid body) in the absence of any constraints. The joint has f degrees of freedom (e.g., f = 1 for a revolute joint or f = 3 for a spherical joint). How many constraints does the joint place on the motion of one rigid body relative to the other? Write your answer as a mathematical expression in terms of m and f.
How to solve the problem
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Bro time and work'la madangu sums'la oru 4 problem solve Pani group'la share panunga bro...konjam confused'ah iruku...videos'la oru sum dhan iruku...plz bro...kind request
Thank you brother
Ans : (3x+2)(x-6).
(x-6) (3x+2)
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Thank you sir
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Answer - (x-6)(3x+2)
(X-6) (3x+2
X_6) (3x+2)
×-6 3×+2
Sir type 2 sum ku method 1 use panala sir
-36
_____________
|
2/3 | -18/3
|
____________
-16
X+2/3, X -6
3x + 2 , X-6
By 3 epdi na x² munadi erukura number
Tq
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(x-6) (3x+2)
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X^4+x^3+x^2+x nu LCM and HCF la Vara model konjam solli kudunga bro
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(3x+2)(x-6)
(x-6) (3x+2)
(x-6)(3x+2)
(x-6) (3x+2)
(x-6) (3x+2)
(x-6) (3x+2)
(x+6) (3x-2)
(x-6)(3x+2)
(x-6) (3x+2)
(x-6) (3x+2)