Indefinite integral of cube root of a surd

In this video, I solved 5 sample problems on Integration technique called U-Substitution. This is employed when the function cannot be easily integrated because it is a composite function.

[@Nifaofficial-ic9db]

I had been thought that integration is for elite level students but now it is different , Thank u for teaching us

[@thekingkratin9722]

Amazing video! You explained the entire problem with such simplicity- just the video I was looking for! Thanks a lot sir!

[@nicef4919]

I watch you r integration vedio so much i love it and that how I know how to integrate THANKS!

[@SuperMtheory]

Great video! I liked your substitution method. I began with two substitutions. u = sqrt x, or u^2 = x and 2u du = dx. But then to work with the 5, I used v = u+5 and dv = du. Fun problem!

[@PrimeNewtons]

Yes, this was a beautiful problem and your double substitution is a more common approach.

[@OmadiEmmanuel-qx7er]

Thanks for teaching

[@TereWilliam]

Pls tnx for ur lecture on this topic. Pls I want to know on what occasion d we u-substitution method?

[@sanchik101]

Sir, thank you so much!!!

[@hosseinmortazavi7903]

Very nice

[@RyanLewis-Johnson-wq6xs]

Integrate[Cbrt[5+Sqrt[x]],x]=3/14(Sqrt[x]+5)^(4/3)(4Sqrt[x]-15)

[@IRENENYONI]

fantastic....!

[@PrimeNewtons]

Thanks

[@klementhajrullaj1222]

Is too much bettter to substitution the cube roots of 5-Vx=u ...