18.2 Entropy | General Chemistry

Chad continues the chapter on Thermodynamics with a lesson on Entropy. First an entropy definition is provided according to Boltzmann's Equation which examines entropy from the molecular perspective and relates it to the number of possible microstates in the system. Next, a variety of factors which affect entropy are discussed including phase, temperature, volume, and the number of particles. Finally, these factors are used to examine entropy changes and to come up with a method of predicting the sign of Delta S for a reaction or process.
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00:00 Lesson Introduction
00:24 Entropy Definition (Boltzmann Equation Microstates)
07:32 Factors Affecting Entropy
17:01 Entropy Change | How to Predict the Sign of Delta S
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[@agentj890]

About to take my final in Physical Chemistry, this helped a ton!

[@ChadsPrep]

Glad to hear it - hope you do well on your final!

[@jazminrojas4431]

Makes so much more sense, thanks Chad!!

[@ChadsPrep]

Glad to hear it!

[@gavindiff9129]

thank so so much i was a little confused when my teaher went over this but I'm starting to get it! now I just gotta do some book problems and go to office hours and ill be golden.

[@ChadsPrep]

You're welcome, Gavin - glad to hear you are making progress!

[@KatherineRSendelbach]

Phenomenal as always ❤

[@ChadsPrep]

Thank you so much 😀

[@kimchi515]

Thank you so much, your video is very helpful!!! The way you explain the concept is so simple, it was really hard for me to understand the textbook and even in class because the explanation always uses complex words, the struggle of the international student:")

[@ChadsPrep]

Glad the channel is helping you - Happy Studying!

[@estimatingonediscoveringthree]

Thank you Chad
How does this relate to boze-Einstein condensate?

[@ChadsPrep]

A boze-Einstein condensate is a gas of bosons with some interesting quantum mechanical properties that is formed at near zero Kelvin. The 3rd Law of Thermodynamics speaks more broadly of any substance being cooled to absolute zero. Assuming it adopts a pure crystalline structure it would then have zero entropy. But keep in mind this is also somewhat theoretical as we never quite achieve absolute zero Kelvin in practice (but pretty close!).

[@namhlamadlala321]

best teacher ever

[@ChadsPrep]

Thank you

[@rickywilliams7919]

Do you have a Masters in Chemistry and Physics.Cheers Ricky

[@kollomalloff469]

Does your general chemistry and high school chemistry playlist cover all of AP chemistry content?

[@ChadsPrep]

Hello James. My high school playlist does not; it was designed for a standard high school chemistry class rather than an AP chemistry class. But my general chemistry playlists (old and new) definitely do. Hope this helps!

[@CanadianBrewingChannel]

I am a refrigeration mechanic. Not a chemist lol. Always been fascinated by thermodynamics. Got a little lost but I think I get it. Thanks for the video.

[@ChadsPrep]

Welcome to the channel/video - glad you found some value!

[@estimatingonediscoveringthree]

Is it appropriate to say dna has a high entropy as a molecule and as a information system?

[@ChadsPrep]

You could say that DNA has a lot of entropy as a molecule (lots of possible microstates) but I don't how exactly to relate that to its role as an information system. And with DNA people are often more concerned with the entropy CHANGE involved in its formation or existence rather than the amount of entropy a DNA molecule has. Hope this helps!

[@otsi.l]

Thanks Champ.

[@ChadsPrep]

You're welcome

[@ayshaijaz9959]

thank you thank you thank you godsend

[@ChadsPrep]

You're welcome x3 - Happy Studying!

[@adelmusaed7959]

Amazing 🎉

[@ChadsPrep]

Thank You!

[@circuitman8792]

Why did you use the symbol for ohms?

[@ChadsPrep]

The capital omega, a greek letter, is used as the symbol for Ohms in physics but also for the number of microstates here for the calculation of entropy. It is the same Greek letter used in both places. Hope this helps!

[@DanielW607]

Nice video

[@ChadsPrep]

Thanks

[@RelaxRailRide]

Nice sir

[@ChadsPrep]

Thanks!

[@skylardean4540]

As I set yet another curve and classmates ask me what my secret is, I coolly respond, "it's Chad."

[@ChadsPrep]

Let 'em know so they can be as cool as you. :-)

[@Joy_Full1333]

What a Chad

[@ChadsPrep]

Happy Studying!

[@garysampson5232]

Oops... Your formula is wrong.
2C + O2 --> 2(CO2) is not correct. You don't get 2 moles of carbon dioxide as stated in the lecture.
How about 2C + O2 --> 2(CO) You do get 2 moles of carbon monoxide.

[@Godfavorsmi]

I’m can’t help but to read his shirt as “devils son”

[@ChadsPrep]

[@adama5563]

i love you

[@ChadsPrep]

Glad the channel is helping you!

[@TheRooflesstoofless]

This comment is to let you know you’re awesome 😅

[@ChadsPrep]

Thanks!