4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?
No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c
To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m
It doesn't matter. Sin and Cos can be used interchangeably if you change the phase constant. So if phi is 90 degrees, then it becomes cos and phi becomes 0
He integrated w but with respect to t so w becomes a constant and gets multiplied by it and if you take its derivative it becomes w hence lhs equal to rhs
If the particle starts from its mean position we take sine as position is 0 but when the particle in shm starts from its maximum displacement A then we say it as cos
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At last, somone who explains it... Thank u!!!
it's an ok explanation. He doesn't explain where the "second derivative" comes from.
Unbelievable.! You taught the topic very easily within a few minutes.
I saw other videos but this one mad most sense to me
Very good at explaining ,,,
How is this easier than adding? You teach well. Thank you.
It is best on you tube 🎉
Good learning from continu
How c= 1/2 A^2w^2
4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?
No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c
0:40 Isnt x away from the equilibrium position
How ω² = k/m , can anyone explain
the w itself is root of k/m then k/m equals to the ω²
@@eymendediler5357but how do you derive w = k/m? is this purely definitional?
@@mailingbox F = mw^2x = kx
@@mailingboxIt is purely definitional.
To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m
omg this was so helpful thank you.
😮Thank you so much
Nice explanation bro
Im amazed by this form, thanks a lot bro !
At 03:20, he mentioned about the chain rule. Which part is it? Why dv/dt = dv/dx*dx/dt? Can someone explain?
Part of chain rule the dx and dx cancel out and we get dv/dt
At which case shm equation will be in cosine and when it will be in Sine ?? Please clarify
Sin will be in displacement and acceleration while cosin is in velocity
@@Luxuryhitler not necessary...sin and cosine functions can be converted to each other interchangeably..
@@Venu_GD yaeh ofc I've speaking abt general form
Hi
It doesn't matter. Sin and Cos can be used interchangeably if you change the phase constant. So if phi is 90 degrees, then it becomes cos and phi becomes 0
Please in the course of finding the integral why didn't you integrate (w)?,
I think because the integration only depends on x and t, then ω becomes constant that can be placed outside of integral
He integrated w but with respect to t so w becomes a constant and gets multiplied by it and if you take its derivative it becomes w hence lhs equal to rhs
ω here is a constant watch video again he takes ω=sqrt(k/m)
A=amplitude
X=Amplitude
X=A
Sqrt(A^2 - X^2)
Sqrt(0)?????
Thanks you sir in this concept is completed 😀 simple harmonic motion
isnt it suppose to be Acos(wt+Ö)
If the particle starts from its mean position we take sine as position is 0 but when the particle in shm starts from its maximum displacement A then we say it as cos
@@suchitawasnik3633thanks
This tutorial need another tutorial
Please sir which software did you used to record your videos🙏
Thanks dude
Nice
TOP G
this video doesn't even make sense.
@@dylanbrookbank1935 it helped me thu, i do not know about u
What’s c mean
That's an integration constant
Isn't it cos
you can use cos or use sine. Both works.
sin(sin^-1(x/A)) =/= x/A
??
It is
Sin*(Sin^-1) is Sin*(1/Sin) by considering basic maths , you will get the rest X/A .
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