- Видео 46
- Просмотров 134 373
Physix Daily
Добавлен 3 мар 2021
I am Prottoy.
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
Просмотров: 723
Видео
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
Просмотров 5310 месяцев назад
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
Просмотров 292Год назад
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
Просмотров 636Год назад
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
Problem 2.5: Introduction to Quantum Mechanics by David Griffiths
Просмотров 718Год назад
Problem 2.4 : ruclips.net/video/GdTpK418Ppo/видео.html
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
Просмотров 635Год назад
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
Просмотров 183Год назад
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
Просмотров 1,4 тыс.Год назад
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
Allowed Energy of particle trapped in the Infinite Square Well
Просмотров 194Год назад
Here is the link to the Derivation of the Wave Function of particle in the Infinite Square Well: ruclips.net/video/Ho-iJ-iR6lE/видео.html
The Infinite Square Well: Deriving the Wave Function
Просмотров 298Год назад
The Infinite Square Well: Deriving the Wave Function
The Photoelectric Effect - Introduction
Просмотров 1752 года назад
The Photoelectric Effect - Introduction
Calculus based proof of Snell's Law
Просмотров 1,3 тыс.2 года назад
Calculus based proof of Snell's Law
Derivation of the Mirror / Lens Equation
Просмотров 1352 года назад
Derivation of the Mirror / Lens Equation
How to derive displacement function of Simple Harmonic Motion
Просмотров 1,7 тыс.2 года назад
How to derive displacement function of Simple Harmonic Motion
Deducing Lorentz Transformation Equations
Просмотров 4932 года назад
Deducing Lorentz Transformation Equations
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
Просмотров 1 тыс.2 года назад
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
Springs, Mechanisms, Time Period and Work
Просмотров 1,9 тыс.3 года назад
Springs, Mechanisms, Time Period and Work
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
Просмотров 88 тыс.3 года назад
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
Heat Engine | Mechanism and Efficiency
Просмотров 453 года назад
Heat Engine | Mechanism and Efficiency
Carnot's Engine | Mechanism and Work Done
Просмотров 973 года назад
Carnot's Engine | Mechanism and Work Done
The Second and Third Law of Thermodynamics Explained in 6 mins
Просмотров 733 года назад
The Second and Third Law of Thermodynamics Explained in 6 mins
Change in Entropy in Different Thermodynamics Processes
Просмотров 6613 года назад
Change in Entropy in Different Thermodynamics Processes
Classic Problem 5 | Calculating "g" from time of flight
Просмотров 3703 года назад
Classic Problem 5 | Calculating "g" from time of flight
Classic Problem 4 | Use of 1st Law of Thermodynamics
Просмотров 1483 года назад
Classic Problem 4 | Use of 1st Law of Thermodynamics
Why is Adiabatic Curve steeper than Isothermal Curve
Просмотров 17 тыс.3 года назад
Why is Adiabatic Curve steeper than Isothermal Curve
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
Просмотров 3673 года назад
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
Relationship between Thermodynamics Variables in Adiabatic Process
Просмотров 2083 года назад
Relationship between Thermodynamics Variables in Adiabatic Process
gud
nice videooo !
super underrated channel thank u so much!!
Like it
It's a pretty good video, but using the same symbol for 2 different quantities (k for kinetic energy, and for the force constant) is a bit confusing.
I came here for the integration part in the last..but he directly gave the results! 🥲
This tutorial need another tutorial
😮Thank you so much
Thanks a lot sir.. explained clearly...
You used wrong formula in part 1 But the answer will came Sin^2x = 1- cos2x/2 Cos term will give zero
Why in the beginning x =ct ! Why there is c isn't x =vt , why every explanation someone had to do something looks wrong ?
Why don't you make your own videos that will be error free.
W
In the letter a of the question, you use the propriety of kronecker delta to solve those integrals, and i got that. But explain to me why, on letter c you can't use the same propriety as doing the integrals by parts. For example, can't you use x=u implies du=dx, and dv= |psi1|^2dx implies v=1? I did by this and had the expect value equal 0. I know that is wrong because it doesn't make any sense physically, but i don't got why i can't use integration by parts :( Nice video, by the way! Very very good (sorry for my poor English).
How c= 1/2 A^2w^2
If you choose the moment where the velocity is 0, you can find the exact value of c by eliminating the v variable
nice video
Correct me if im wrong but in part d for <p> isnt the answer (8/3)*(h bar/a)*sin(3ωt) ? also at 20:40 and 12:10 its stated that the ω=n^2*π^2*hbar^2/2ma^2 but h bar constant is h bar not h bar squared in ω equals
Thank you for your feedback. You're exactly right. What I missed in the very last line was the omega factor which I forgot to add. If you add in omega in the last line, you should be able to simplify to whatever you have.
omg this was so helpful thank you.
What’s c mean
That's an integration constant
Nice explanation bro
0:40 Isnt x away from the equilibrium position
Isn't it cos
you can use cos or use sine. Both works.
But isn't it cos??
B cos(wt + C), still can do
I saw other videos but this one mad most sense to me
Wooooooooooooooowwwww❤❤❤❤❤❤🥰🥰🥰🥰🥰🥰🥰😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍📸📸😍😍📸📸😍😍 so beautiful it feels like im high or somthing
Thank you for this Protty. It was really helpful.
You're welcome Fatuma. I'm glad my videos reached you
Sir can you please make a video on derivation of wave motion. Plzz sir
Cool thank you!
Thanks dude <3
4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?
No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c
At 03:20, he mentioned about the chain rule. Which part is it? Why dv/dt = dv/dx*dx/dt? Can someone explain?
Part of chain rule the dx and dx cancel out and we get dv/dt
Thanks.
Thanks brother
Thanks a lot 😃
Amazing video!!!😍 I had a question in pendulum which I couldn't figure out🥺. How can I send it to you?😇
Hi! Email me at prottoymahdisamir@gmail.com
@@physixdaily6223 Thanks a lot for the assistance!!!! Just mailed u😁.
At last, somone who explains it... Thank u!!!
it's an ok explanation. He doesn't explain where the "second derivative" comes from.
@@DdoubleB03 I am explaining u.In case of 1st derivative of acceleration,we get dv/dt.After then, when we differenciate the velocity again we gets lastly d^2x/dt^2. this is how the "second derivative" comes from.
A song like this will definitely have international appeal. Just look at the comments.
This video is helpful 😀 thank sir
Thanks you sir in this concept is completed 😀 simple harmonic motion
A=amplitude X=Amplitude X=A Sqrt(A^2 - X^2) Sqrt(0)?????
X is a variable which we are analysing its behaviour as the time goes. So it is not always the same thing as the Amplitude. If they're same at a point, it means that the object moved as far as possible from the starting point which have now became as big as the position vector of the amplitude. So yeah it would be 0 in this case but you're forgetting that this term is inside of the cos function, so cos(0) would be 1 and x = A (Amplitude) as intented to be.
Please to solve the problems 2.11,2.12
Thank you. I'll post the solutions of those then!
2.12 and 2.13 Ka solution
I'll post them too!
Thanks
Unbelievable.! You taught the topic very easily within a few minutes.
Well done sir. Thank you
Best video so far
Im amazed by this form, thanks a lot bro !
Please sir which software did you used to record your videos🙏
How ω² = k/m , can anyone explain
the w itself is root of k/m then k/m equals to the ω²
@@eymendediler5357but how do you derive w = k/m? is this purely definitional?
@@mailingbox F = mw^2x = kx
@@mailingboxIt is purely definitional.
To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m
It is best on you tube 🎉
I WANT TO KNOW THE LOGIC OF ? IS THIS A CONVENTION ? OR WE CAN PROVE IT BY TAKING INTO 2D