This is the best explanation of induction motor principles I have ever heard. However, there was a piece of information which I hoped to hear about in this video but it was not mentioned. This information is why do induction motors are considered constant speed motors? But, after watching this video I noticed something that may point out the answer of my question. Because the steady state speed lays in between the peak torque that could be developed by the motor and the synchronous speed, motor's speed would not change significantly if the load was changed slightly. This is because the performance curve of this specific region is almost vertical. Hence, any change in the load, whether it was relatively large or small change, would change the speed a little bit, and this small change may be neglected. That is why they call it constant speed motor.
Spendid work. One of the clearest, if not the clearest explanation of induction motor on the net. Just a remark : the right hand grip rule should give opposite pole names at 6:09 or am I mistaken ? (Or perhaps the green letters should have been placed towards the inside of the stator, in which case the pole names are correct).
Thanks you so much for helping me understand this more clearly. I am not able to find reference to what you mention to be "Slip S" at 9:39. Can you slip me a link? lol
At 5:30 onwards, am I correct to think that the pole labels correspond to the inner magnetic polarity of the coil pairs? Because each coil has two magnetic poles, therefore a coil pair (although it acts as one bar magnet) have 4 poles, 2 outer magnetic poles and 2 inner magnetic poles...
Not expert in motors here,but i would think the torque would then be opposite to the negative slip. If you consider the rotor as a frame of reference, positive and negative slip just result in a sign change in torque. So the system tries to get stabilized to the synchronous speed.
Greetings,could someone help me with this? I have not clarified whether the rotor does initialy reach the synchronous speed at an instant and then it slows down to a constant speed. Or it does never reach the synchronous speed
Hello I would really appreciate it if you could help me resolve this issue. I have a 1000 rpm 160 kw rated 3 phase Delta connected ac motor hooked to an air compressor feeding an oxygen production plant. our phase to phase supply voltage is 380 volts. our maximum running load current at working pressure is 250 Amps. This motor failed as it was running for more than 10 years. Lately we demanded more continuous load due to high demand for medical oxygen effected by covid19 pandemic. I could not find a similar replacement available. However i found another German made motor with same mounting frame and shaft size and also 1000rpm at 50 Hz the name plate says: Delta connection 660 Volts - 260 Amps - 240 KW. my question is : if i supplied this motor 380V with same delta connection will it be able to give me 160 kw power? because its limiting design current is 260 Amps as it says . Thus if am assuming its rated power will be reduced proportionally to the reduction of supply voltage. i it is rated 240 Kw at 660 Volts is it true that it will become a 160 Kw motor under 380 Volts? I am also assuming it will not overheat as the current will not exceed its rated 260 A at my demanded compressor load. Please help me if you have a definitive answer without any speculations. Best regards
I think better explanation than this is not possible
Very simple and usefully to summarize about induction motor. Thank you for your special sharing!
So far the best video i watched on this topic
This is the best explanation of induction motor principles I have ever seen!!!
Amazing! i waited for the video like this for a long time! Thank you! Very qualified video
This is the best explanation of induction motor principles I have ever heard.
However, there was a piece of information which I hoped to hear about in this video but it was not mentioned. This information is why do induction motors are considered constant speed motors? But, after watching this video I noticed something that may point out the answer of my question. Because the steady state speed lays in between the peak torque that could be developed by the motor and the synchronous speed, motor's speed would not change significantly if the load was changed slightly. This is because the performance curve of this specific region is almost vertical. Hence, any change in the load, whether it was relatively large or small change, would change the speed a little bit, and this small change may be neglected. That is why they call it constant speed motor.
One the best video ever watched about induction motor
Best explanation so far.Please make another on Synchronous generator
Oh, very well done. A valuable resource. Thank you.
This is an excellent, excellent video. Two huge thumbs up!
Spendid work. One of the clearest, if not the clearest explanation of induction motor on the net. Just a remark : the right hand grip rule should give opposite pole names at 6:09 or am I mistaken ? (Or perhaps the green letters should have been placed towards the inside of the stator, in which case the pole names are correct).
I believe you're correct
THANK YOU
Thanks you so much for helping me understand this more clearly. I am not able to find reference to what you mention to be "Slip S" at 9:39. Can you slip me a link? lol
At 5:30 onwards, am I correct to think that the pole labels correspond to the inner magnetic polarity of the coil pairs?
Because each coil has two magnetic poles, therefore a coil pair (although it acts as one bar magnet) have 4 poles, 2 outer magnetic poles and 2 inner magnetic poles...
P.S. the explanations are great Sir! thank you for this!
Thanks for the valuable information.
How the torque behaves when the slip is negative due to a prime mover?
Not expert in motors here,but i would think the torque would then be opposite to the negative slip. If you consider the rotor as a frame of reference, positive and negative slip just result in a sign change in torque. So the system tries to get stabilized to the synchronous speed.
Thanks sir..
What about them old ones with the slip rings and resistors? Wouldn't you get the low torque of a universal motor without the need for high amps?
I have a small doubt..How do the frequency of source becomes the frequency for rotor? I didn't understand that point.
Greetings,could someone help me with this? I have not clarified whether the rotor does initialy reach the synchronous speed at an instant and then it slows down to a constant speed. Or it does never reach the synchronous speed
Hello I would really appreciate it if you could help me resolve this issue. I have a 1000 rpm 160 kw rated 3 phase Delta connected ac motor hooked to an air compressor feeding an oxygen production plant. our phase to phase supply voltage is 380 volts. our maximum running load current at working pressure is 250 Amps. This motor failed as it was running for more than 10 years. Lately we demanded more continuous load due to high demand for medical oxygen effected by covid19 pandemic. I could not find a similar replacement available. However i found another German made motor with same mounting frame and shaft size and also 1000rpm at 50 Hz the name plate says: Delta connection 660 Volts - 260 Amps - 240 KW. my question is : if i supplied this motor 380V with same delta connection will it be able to give me 160 kw power? because its limiting design current is 260 Amps as it says . Thus if am assuming its rated power will be reduced proportionally to the reduction of supply voltage. i it is rated 240 Kw at 660 Volts is it true that it will become a 160 Kw motor under 380 Volts? I am also assuming it will not overheat as the current will not exceed its rated 260 A at my demanded compressor load. Please help me if you have a definitive answer without any speculations. Best regards
Please make more video
right hand grip rule violated? 2:00
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