Support Reactions - Lesson 10

Learn all about supports: Cable, pin, roller and fixed supports are among the most widely used supports.

[@minhdang358]

First Indian Professor that talks clearly.

[@sarathsimon5636]

I have NEVER in my life seen someone who explained it so well that I got it my first attempt! Thank you !!

[@ammarnoahhatta9885]

SAME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

[@mahbubhassan7175]

Same

[@tanjidulhassan2999]

"perpendicular to the surface" that's what I was looking for. Thank you so much sir! You're such a good teacher!

[@TijwokPeter]

A lesson That I had never understood very well during schools time: has been been explained by you in an extremly short time. That it becomes easy for me now. Thanks a lot.

[@srinivasp1985]

indeed one of the best and easiest explanation to understand these joints....super cool sir!!

[@juliec_kip]

Your explanation is outstanding sir ...the included illustrations were really helpful

[@DigZworld]

I very much appreciate your description of these concepts.

[@kazishahezad5070]

Thank u sir well explainef

[@glaizarabi5575]

I appreciate the learning. Great video!

[@alyafey69]

This guy is absolute genius he made it so simple and fun!!! Than you very much for saving my life!! Let me know if there's anyway I can pay you back :)

[@529213]

teach someone else

[@eddietinstrum6448]

Very well explained, and made it super clear with the illustrations and examples (rope, scissor, lego etc). Thank you Sir!

[@HemanthKumar-cc1so]

Super sir ...this type of teaching is necessary for students

[@jhansirani6196]

Marvelous sir... I love it...

[@skyboundzoo7529]

Great teaching ,, helped me reaffirm these foundational concepts

[@MITSCG]

Superb lecture. Helped a lot understanding aero-statics. Thank you.

[@pavarnat743]

Such a great explanation, I ever seen

[@yashwanth7362]

Thank you for the information -- it was really done in a nice perspective

[@UU-ls7xy]

This was super helpful. Thank you so much.

[@varunkharayat4251]

Brilliant explanation sir

[@naomiwebb3268]

this is solid gold! thank you!

[@thowfiqali7630]

I have confusion in support conditions sir but it is cleared now thank you so much

[@مريَم-ط5م7غ]

Lifesaver! thank you so much, understanding this concept saved my cource

[@nafeessanni8578]

thank you sir, i didnt believe i could know this until i watched your video,amazing explanation

[@189thasinahmed7]

Great sir u have cleared all my doubts

[@BAM-yi7kc]

Very good explaination . Thank you Sir.

[@sasikumartherayil9620]

Great explanation
Iam a structural engineer
Really nice

[@tomasenrique]

Such a great video!

[@David-hh3oc]

Thank you Sir, very well explained.

[@shreyywadhwa]

Just a word, Wow!

[@francissakyi2354]

Good explanations 👍🏾

[@arameshyadav5144]

Keep doing more videos sir...

[@mejprabhu]

Sir, Nice lecture with simple examples. Please upload more videos sir.

[@MOHAMEDABDILLAHIARABTKT]

i am really appreciate your explanation sir
thank you very much

[@andy4christ991]

YOU ARE INDEED OUTSTANDING

[@svvelpula4592]

Excellent explanation sir ..nice

[@ronreyes7421]

Thank you this really helped!

[@toasawamura364]

love this guy

[@Prem_2701]

Osm sir👌

[@medyahaji4128]

Thank you

[@rumonsiddique5017]

sir, definitely u r god.

[@zenaiahrylle7436]

Thanks a lot!

[@engineerazeemkhan9022]

Superb sir

[@shaiksowmya5528]

Sr well said can u give pics of fixed supports related to civil engineering

[@arka800]

Very nice...

[@pawanraghav5178]

Helped a lot

[@Starlordsstudio]

great explanation sir..

[@BrindabonBD]

Thanks

[@vathani91]

excellent explanation..👍

[@ouafaeraibi7847]

thank you so much Sir it was very clear

[@navinfahmi1800]

thanks a lot

[@danishkhan-qf1bi]

amazing explanation sir

[@Tech___Tube]

Hello Professor.
I don't know which is your workplace.
Wherever, those students are lucky.

[@abhishekhbaliarsingh711]

Awesome sir

[@praveenpawar7317]

Best 👍

[@ayushyadav9747]

If I take the resultant of both forces in x and y in pin support can you tell where will be the resultant of that two forces

[@529213]

The square root of x^2 + Y^2 will be the magnitude of the resultant. You can find the angle using Inverse Tan (y/x)

[@ayushyadav9747]

Sir I do know that . But will the resultant be along the body.

[@ajayyadav5284]

thank u sir well explained

[@kumarpurushottam632]

Thanks sir

[@jdavids1332]

are wheels roller support?

[@Mrbogarrr]

Sir super

[@Its_me_you_us]

nice

[@anandkurle7851]

you are god basu

[@sajjadmanzoor6514]

nice ever..

[@shaiksowmya5528]

Sr expecting a good rplyy soon

[@vfgrfbgrb]

So thered moments

[@hemantchand1757]

Nothing understand and you give so many doubt