Germany | Can you solve this? | Math Olympiad

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  • Опубликовано: 6 янв 2025

Комментарии • 7

  • @evrankorkut8915
    @evrankorkut8915 День назад +1

    Thank you very much

  • @mariatriantafyllou-g3d
    @mariatriantafyllou-g3d День назад +1

    when you don't have all the information, when you don't want to receive it the way it could be given to you and when you don't have the same way of thinking with the other person, you look to find the weak points of the other in places and situations that don't exist . I will keep what a friend told me two days ago "I can't hear you".

  • @AlexanderSemashkevich
    @AlexanderSemashkevich День назад +1

    5^x(5²-1)=80
    5^x=10/3
    x=(log10-log3)/log5=(1-log3)/log5
    x≈(1-0.477)/0.699≈523/699≈0.748
    Deviation is about 0.0001
    5^(0.748+2)-5^0.748≈79.99

  • @AbbasGuclu-jn3po
    @AbbasGuclu-jn3po День назад

    5^x(5^2-1)=80
    5^x×24=80
    5^x×3=10
    5^x=10/3
    log5^x=log10/3
    x =(log10-log3)/log5
    x=(1-log3)/log5
    x=log5(1-log3)

  • @ChavoMysterio
    @ChavoMysterio День назад

    5^(n+2)-5ⁿ=80
    25(5ⁿ)-5ⁿ=80
    24(5ⁿ)=80
    3(5ⁿ)=10
    3(5ⁿ)=5•2
    3[5^(n-1)]=2
    5^(n-1)=⅔
    n-1=log_5(⅔)
    n=1+log_5(⅔)
    n=1+log_5(2)-log_5(3) ❤

  • @MINIVISION2010
    @MINIVISION2010 День назад

    ! log(10)=1

  • @AbbasGuclu-jn3po
    @AbbasGuclu-jn3po День назад

    5^x(5^2-1)=80
    5^x×24=80
    5^x×3=10
    5^x=10/3
    log5^x=log10/3
    x =(log10-log3)/log5
    x=(1-log3)/log5
    x=log5(1-log3)