dude THANK YOU! I've been reading my notes over and over again and still quite lost in the derivation. You explain it quick & nice, I finally understand it. honestly i don't think it's too fast or anything. i kinda like the pace cause I tend to lose focus if the vid is too slow or long
Please answer this question at the earliest, if possible: Are "V" (the one you introduced in the beginning of the video), and "Vzero" (the one you started talking about halfway through the video), the same thing?
dude we had this class at my uni, and even tho the biochem professor said the exact same things, somehow you made them understandable in comparison to what he said. And English isn't even my mother tong. Thank you very much for this helpful video plz dont ever stop
THANK YOU!!!! Rewatching my bichem lecture three times, and attending two tutorial classes i thought i was never going to learn this. its so dang simple when you explain it. THANK YOU!
Very usefull! Taking a course on enzyme dynamics next semester and need to know michealis menten kinetics but never learned it. I feel like this video will really help me!
I see a lot of people complaining but honestly let's just thank him for doing this for free, the video is more than ok if you know what each term means.
I like this. My only problem with it is that Km is defined in terms of S. Km is already defined by the rate constants of the individual reactions (k1, k-1, k2). Probably more accurate to say that *when* [S] = Km, Vnaught = Vmax/2. edit: rather than the other way around, let Km = [S]. Semantics but conceptually clearer this way.
Nour Kamaly same and it sounds awful when you slow it down. Rather have the option to speed up the video. I’m sure it would be a wonderful video if it wasn’t already sped up.
Although this video is fast, if you follow him and pause it and rewind at your own pace it is not that bad. The reason you want your Km to be low is when looking at the graph it has a linear form at the bottom which means your substrate is low and the enzyme as great efficiency hence the linear characteristic of the graph. Then as the substrate increases the efficiency of the enzyme goes to zero as shown by the graph going to zero velocity.
Perfect video, literally. Well paced and so informative. Breaking concepts down too much can often cause complications hence I love the well paced style of teaching by this educator.
Thanks for completely writing all the steps of the equation out. I never understand formulas/equations unless it's actually shown WHY it is the way it is
I think it was very helpful, I don’t understand why people r saying that it was too complex or fast. The subject is not an easy one and you don’t have to know all of the steps for the last formula. And you can still watch it again or slow the video down.
The old format where the videos were in real time on a black background were so much easier to learn from. These videos that are in fast forward are good for review but way to fast to learn something and there is no time for the detailed explanation that makes it memorable....
You should be clear that KM is an equilibrium constant hence the upper case K and kcat is a rate constant therefore a lower case k, here you don't show that and it's a very important fact when you takes these things further.
This video helps me to understand some of the concepts that is critical in my studies. Thank you to Ross Firestone to create it. I also thank my lecture Dr. Missa for encouraging me to watch this video. Much appreciation.
The one logic gap that I continue to struggle with is how is the FORMATION of ES equal to the LOSS of ES AFTER the elimination of K-2. You no longer have the breakdown of the Product (which does make sense, given the stability of it) but then that's an entire source of ES production that isn't there!!! So you have 2 routes out of ES (formation of P and breakdown of ES to E+S) and 1 route to ES(formation of ES from E+S). Still holding the initial belief that was applied to 2 routes out and 2 routes to. The only way I can sort of make it make sense, but not confidently, is at the beginning of the reaction where K1 and K-1 might hold more weight than K2 but I'm not sure I'm right with that idea.
Please answer this question at the earliest, if possible: Would it be fair to say that the dissociation of enzyme substrate complex (to product or back to substrate) is a first order reaction, and the formation of the ES complex (from substrate) is a second order reaction?
That is correct however, as [S]>>[E] k1 (E+S = ES) can in practise be considered a first order rate reaction as the overall concentration of S changes very little over the course of the reaction (The reaction is only really dependent on the concentration of the enzyme). It's what is known as a "pseudo first order rate constant"
Certainly! Here’s a shorter version: "When a product forms in an enzyme reaction, it’s thermodynamically more stable than the enzyme-substrate complex because the reaction releases energy, relieving any strain on the substrate. This lowers the system’s energy, making the product a stable, final state. As a result, the backward reaction (from product to enzyme-substrate complex) is rare." From chatgpt
Wasn't exactly able to follow the derivation of the formula to the fullest but everything else was extremely helpful. Definitely not for beginners though haha. Read the textbook first, guys! Or watch a simpler video
Ace Case you need to know a little of kinetics first, the speed of a reaction is v=K*[R]. R being the concentration of the reactant and as a correction factor they add a K
You should watch the first video to this series. In addition, the Michaelis Menton equation is used to describe rates. You should know what rates, and kinetics are (usually taught at the end of Chemistry as Chemical Kinetics) to understand what a K value is. You can have a whole 2 hour lecture on what K values are. For this video, just recognizing that it's a constant is sufficient.
I have a question! Why does steady state assumption only apply to enzymes, not to inorganic catalyst? I understood this that inorganic catalyst has rate-determining step, but enzymes don't. Why do enzymes don't have a slow step? Is it because of the structure of enzymes? It would be really helpful if you could answer me!
It's all Greek to me. I got a headache in class when our teacher tried to "explain" it to us and I have a headache now too. This is the only topic I can't seem to understand well...
The first assumption you made is wrong products can go back to reactants and the can obviously be exothermic the reason it’s excluded is because at the time the rate is examined the product is formed in such small volumes that it’s disassociation is negligible
for everyone struggling with the concept, make sure you understand steady state approximations since that will make this whole derivation make a lot more sense
really good video! :) But what exactly is k_1, k_(-1) and k_2? are they constants for the time it takes to form the new state? (say, it takes 3s to form ES from E and S, so k_1 = 3s?)
These are rate constants. Rate constants are obtained by dividing product concentration to the power of their stoichiometrical coefficient by substrate concentration to the power of their stoichiometrical coefficient. Rate constant has no specific unit, it changes with the reaction. (Correct me if I'm wrong, learned that 5 years ago)
he keeps on slapping me with these letters and i dont wanna live no more
same dude, i am going to live in a box
Need an update buddy, how are you doing two years later?
did you pass biochem ?
@@walkerwatters8607
you can say I'd KM[S]
I love this comment thread ive been laughing at them for 10 minutes now 😭😭😭😭
ahhh..... 3 weeks of lecture condensed in a clear and organized manner into 7 and a half minutes. Thank you so much.
dude THANK YOU! I've been reading my notes over and over again and still quite lost in the derivation. You explain it quick & nice, I finally understand it. honestly i don't think it's too fast or anything. i kinda like the pace cause I tend to lose focus if the vid is too slow or long
Tip: put the settings on 0.75 playback speed, and pause every time he writes a new line, making sure that you understand the logic of how he got there
OH. MY. GOD. literally what ive been trying to understand in past 7 hours has been summed up in 7 minutes. I LOVE YOU.
I learned so much more from this video than from reading an entire chapter two times. -.-
But perhaps reading the chapter helped you understand the video!
Exactly the reason i am here. Read the chapter and helped a little but the video tied it together.
generic comment number 2314423
Please answer this question at the earliest, if possible:
Are "V" (the one you introduced in the beginning of the video), and "Vzero" (the one you started talking about halfway through the video), the same thing?
V = reaction rate
V0 = initial reaction rate (reaction rate when time=0)
This is significantly more helpful than listening to my biochem teacher haha
comment number 232359
same here lmao
THIS!!
dude we had this class at my uni, and even tho the biochem professor said the exact same things, somehow you made them understandable in comparison to what he said. And English isn't even my mother tong. Thank you very much for this helpful video plz dont ever stop
THANK YOU!!!! Rewatching my bichem lecture three times, and attending two tutorial classes i thought i was never going to learn this. its so dang simple when you explain it. THANK YOU!
Very usefull! Taking a course on enzyme dynamics next semester and need to know michealis menten kinetics but never learned it. I feel like this video will really help me!
I see a lot of people complaining but honestly let's just thank him for doing this for free, the video is more than ok if you know what each term means.
Ain’t no way this video actually that good that it clearly brings together my book, notes, and other vids
8 min video >> 45 mins in class. Thx, really appreciate ur work
I like this. My only problem with it is that Km is defined in terms of S. Km is already defined by the rate constants of the individual reactions (k1, k-1, k2). Probably more accurate to say that *when* [S] = Km, Vnaught = Vmax/2.
edit: rather than the other way around, let Km = [S]. Semantics but conceptually clearer this way.
Usually i love your videos Ross, but seems like you rushed this one a little too much !
it was very complex indeed!
Complexity is just more layers of information. Chinese is more complex than English. Everything is relative.
This is the first time i've ever found the khan academy videos not helpful, you're going way too fast dude!!
Nour Kamaly same and it sounds awful when you slow it down. Rather have the option to speed up the video. I’m sure it would be a wonderful video if it wasn’t already sped up.
it is very helpful . u should see manytimes to get it clear..
It's seem the result (the understanding of the explanation) is different for different people...
To me every khan academy video is slow I totally avoid the whole thing and just code.
Check once again...you would've probably set it on 2X 😂
Although this video is fast, if you follow him and pause it and rewind at your own pace it is not that bad. The reason you want your Km to be low is when looking at the graph it has a linear form at the bottom which means your substrate is low and the enzyme as great efficiency hence the linear characteristic of the graph. Then as the substrate increases the efficiency of the enzyme goes to zero as shown by the graph going to zero velocity.
THIS WAS AMAZING! AS A CHEM E STUDENT WITH LITTLE TO NO EXPERIENCE IN BIOLOGY, I THANK YOU! :D
Perfect video, literally. Well paced and so informative. Breaking concepts down too much can often cause complications hence I love the well paced style of teaching by this educator.
Thank you so much, this was very helpful. I never really understand Kcat since a lot of sources just focus on defining Vmax and Km. Cheers :)
Desired speed
Sal: 2x
This guy: 0.75x
sebastian cuello painfully accurate
Thank uh soo much, I read lots of notes but cant understand derivation abd concept but now its all are clear just bcz of uh jazak Allah Khair
This video saved me from getting a panic attack. Thank you do much for explaining it so well.
Good to see a brother muslim
Helping the students all over the world
Allah is great
literally none of this makes sense to me.....
Review chemical kinetics
😂me too!
Thanks for completely writing all the steps of the equation out. I never understand formulas/equations unless it's actually shown WHY it is the way it is
This makes so much more sense. Thank you so much!!!
I think it was very helpful, I don’t understand why people r saying that it was too complex or fast. The subject is not an easy one and you don’t have to know all of the steps for the last formula. And you can still watch it again or slow the video down.
The old format where the videos were in real time on a black background were so much easier to learn from. These videos that are in fast forward are good for review but way to fast to learn something and there is no time for the detailed explanation that makes it memorable....
You should be clear that KM is an equilibrium constant hence the upper case K and kcat is a rate constant therefore a lower case k, here you don't show that and it's a very important fact when you takes these things further.
k cat is actually just k2, I love it when biologists just name the same variable with diff terms so that the math part can look complicated.
This video helps me to understand some of the concepts that is critical in my studies.
Thank you to Ross Firestone to create it. I also thank my lecture Dr. Missa for encouraging me to watch this video.
Much appreciation.
Visual learners across the globe thank you for this video.
The one logic gap that I continue to struggle with is how is the FORMATION of ES equal to the LOSS of ES AFTER the elimination of K-2.
You no longer have the breakdown of the Product (which does make sense, given the stability of it) but then that's an entire source of ES production that isn't there!!!
So you have 2 routes out of ES (formation of P and breakdown of ES to E+S) and 1 route to ES(formation of ES from E+S). Still holding the initial belief that was applied to 2 routes out and 2 routes to.
The only way I can sort of make it make sense, but not confidently, is at the beginning of the reaction where K1 and K-1 might hold more weight than K2 but I'm not sure I'm right with that idea.
Please answer this question at the earliest, if possible:
Would it be fair to say that the dissociation of enzyme substrate complex (to product or back to substrate) is a first order reaction, and the formation of the ES complex (from substrate) is a second order reaction?
That is correct however, as [S]>>[E] k1 (E+S = ES) can in practise be considered a first order rate reaction as the overall concentration of S changes very little over the course of the reaction (The reaction is only really dependent on the concentration of the enzyme). It's what is known as a "pseudo first order rate constant"
Very helpfull despite having to pause a lot.
What is Thermodynamically stable at 1:35 ?
Certainly! Here’s a shorter version:
"When a product forms in an enzyme reaction, it’s thermodynamically more stable than the enzyme-substrate complex because the reaction releases energy, relieving any strain on the substrate. This lowers the system’s energy, making the product a stable, final state. As a result, the backward reaction (from product to enzyme-substrate complex) is rare."
From chatgpt
OMG, YOU DO NOT KNOW HOW MUCH YOU HAVE JUST HELPED ME!
THANK YOU SO MUCH!
Short n sweet video ,just perfect
Can someone give this person a medal please?
I agree!!!
me too😍😍
wow that's really a lot of information in 7 mins.
Awesome video.
Me checking to make sure my video was at normal speed 😂. But thank youu, good explanation just had to watch it couple times.
please answer this: why did we only consider k2 for calculating reaction rate! ie v0 in vo=k2[ES]
Wasn't exactly able to follow the derivation of the formula to the fullest but everything else was extremely helpful. Definitely not for beginners though haha. Read the textbook first, guys! Or watch a simpler video
2:12 - 4:50 wtf happened -.-
Ace Case you need to know a little of kinetics first, the speed of a reaction is v=K*[R]. R being the concentration of the reactant and as a correction factor they add a K
math
lmao
Ifkr?!
You should watch the first video to this series. In addition, the Michaelis Menton equation is used to describe rates. You should know what rates, and kinetics are (usually taught at the end of Chemistry as Chemical Kinetics) to understand what a K value is. You can have a whole 2 hour lecture on what K values are. For this video, just recognizing that it's a constant is sufficient.
The math/derivation is beyond the scope of the MCAT.
Thank you so much !! This was absolutely helpful :)
Absolutely brilliant ❤
Thank you so much!
thank you! It was a bit fast but i loved to stop and rewind! ^^
you just simplified an entire 8 pages of derivation thank you
Thank you... Thank you.... Thank you ❤❤❤
This guy is way better than my biochemistry professor
ㅇㅈ 대학 수업들을필요 없음 유튜브에 치면 판때기하나놓고 설명 오지게잘해줌
My bio chem teacher took 2 hours to explain this! LoL
Future of education!!, so much better than readling the long boring books where the author is probably paid per page written.
Really useful! Thank you so much!
This video is good and condensed and DAMN BLESS YALL
Slow down!!!! I usually love your videos but this is way too fast!
Amazing! Thank you very much
Thank you very much!
great...I was struggling to understand it in my lecture but now I find it easier and more clear ..thanx 👍🏻
Very helpful. Thank you
Thanks a lot , u saved me
thanks for the explanation!
I've never understand it before watching this video, thank you a lot
Thank you so much
If you're here for MCAT review, you can ignore the "lets do some math" section where he derives the equation.
Thank you for breaking this down!
THIS WAS SO HELPFUL THANK YOU THANK YOU THANK YOU
Really helpful videos, thanks so much!
Usually have to watch videos on 2x speed, not here! Thank you!
Nicely explained/derived
What's the difference between Kcat and K2? if Vmax = kcat x [E]t and vmax also = k2 x [E]t, are they the same?
I have the same question
Fantastic explanation, best I've watched
I understand it, but it took me over an hour. I had to rewind, pause, think, and then move forward with the video.
I have a question! Why does steady state assumption only apply to enzymes, not to inorganic catalyst?
I understood this that inorganic catalyst has rate-determining step, but enzymes don't.
Why do enzymes don't have a slow step? Is it because of the structure of enzymes?
It would be really helpful if you could answer me!
Excellent explanation.
واقعا خیلی خوب توضیح داده شده ممنونم❤
Beautifully explained.
It's all Greek to me. I got a headache in class when our teacher tried to "explain" it to us and I have a headache now too. This is the only topic I can't seem to understand well...
😑
just thank you
thank you. this helped alot
Great job
The value of kcat /Km of different enzymes are not comparable. It should only be used to compare different substrates to the same enzyme.
You helped SO much, thank you for the wonderful explanation!!
Love this video so much. Thank you!!!
Awesome video man, keep it up.
Do I need to know how to derive the equation for the MCAT?
Thank you so much! This was so helpful.
The first assumption you made is wrong products can go back to reactants and the can obviously be exothermic the reason it’s excluded is because at the time the rate is examined the product is formed in such small volumes that it’s disassociation is negligible
Why are we "pretending Km is equal to [S]"?
Did the graph or the math come first for Enzyme kinetics?
for everyone struggling with the concept, make sure you understand steady state approximations since that will make this whole derivation make a lot more sense
amazing video! Really good explaind?! Thanks a lot !
really good video! :)
But what exactly is k_1, k_(-1) and k_2? are they constants for the time it takes to form the new state? (say, it takes 3s to form ES from E and S, so k_1 = 3s?)
These are rate constants. Rate constants are obtained by dividing product concentration to the power of their stoichiometrical coefficient by substrate concentration to the power of their stoichiometrical coefficient. Rate constant has no specific unit, it changes with the reaction.
(Correct me if I'm wrong, learned that 5 years ago)
And I have a test in 5 hours and I don't know wtf happened from 2:10 - 4:50
Btw wish me luck guys...
Just I want to comment
Educator is good
to anyone out there: WATCH IT AT LEAST TWICE
dude's got that biochemistry swag
do we really need know this for the mcat?