So if I have a dump trailer that has a 2gpm pump, if I switch to pto driven wet lines from my truck with 4 times the Gpm would I be correct in assuming that would speed up my cylinders to Dump faster?
It typically means that the ports of the cylinder are tied together to speed up the cylinder. It speeds up because the oil flowing out the cylinder is combined with the cylinder entering the cylinder and the cylinder will speed up. I will try and make a video on in the future and pass it along to you.
Dear Sir..........I have single acting a cylinder with a bore of 18 mm and a rod of 10 mm and a stroke of 300 mm. I want to know what is the pressure if my cylinder presses 10 mm ........... Please advise and provide a solution with the formula
@@KletteTech thx for replying. this is a formula in CKD cylinder handbook Q=A*V*((P+0.1013)/0.1013)*(10^-6)*60 which Q : l/min D : mm V : mm/s P : mpa why does his formula show the piston speed is related to the air pressure?
I am not sure. I have not seen the handbook. If it is talking about pnuematic cylinder that is a different formula all together. This is for a hydraulic cylinder.
Just to understand. Why arent we considering the stroke length of the cylinder. Why arent we considering pi r*r*h because technically the cylinder moves for the stroke length. I would appreciate if you can help me understand
Great question. There are a number of factors that come into play. If there is not a flow control or a non compensated flow control, you need to know that GPM going to the cylinder. This will change based on the load. The more load less GPM and visa versa. You also need to take into account the other components in the system. If the GPM is not known then there are formulas for figure that out but they go beyond what I have in this video and there only estimates. Also, remember that the speed will be different on the return (fast with the same GPM) because there is less volume on the cylinder return because of the cylinder rod.
@@KletteTech This was a question on a classroom lab I had last week. Major cylinder area was 12.566 sq. in. and minor cylinder area was 10.161 sq. in. Cylinder was had a static load of 800 lbs. on extension and retraction. Psi for extension was 63.66 psi. Psi for retraction was 78.73 psi. Was asked to calculate cylinder speed in inches per minute. The only formula in the textbook was for an unloaded cylinder which the instructor allowed us to calculate for since he couldn't provide the formula for a loaded cylinder. The flow was 4 gpm thus giving a extension speed of 73.5 ipm and retraction speed of 90.9 ipm. Have searched for one but have been unable to find it.
@@johns8771 Your answer is actually correct. The trick to this question is that the 4 gpm is actually taking into account the load. Depending on the circuit's components the load can or cannot have an affect on the GPM entering the cylinder. Either way, once the gpm has been given or discovered the load no longer affects the speed. To summarize, the load only affects gpm. Once gpm is known the formula is the same for loaded on unloaded cylinders. Make sense?
So if I have a dump trailer that has a 2gpm pump, if I switch to pto driven wet lines from my truck with 4 times the Gpm would I be correct in assuming that would speed up my cylinders to Dump faster?
Supposing that there is one more throttle-valve at the outlet of cylinder, so what is the speed of cylinder in this case ?
What about the velocity when cylinder retracts
Pat thank you what is cylinder regeneration means
It typically means that the ports of the cylinder are tied together to speed up the cylinder. It speeds up because the oil flowing out the cylinder is combined with the cylinder entering the cylinder and the cylinder will speed up. I will try and make a video on in the future and pass it along to you.
How is your formula supposed to take care of the stroke length?
It is not. Stroke length is not a factor in speed when you are looking at the idea circuit like this.
Dear Sir..........I have single acting a cylinder with a bore of 18 mm and a rod of 10 mm and a stroke of 300 mm. I want to know what is the pressure if my cylinder presses 10 mm ........... Please advise and provide a solution with the formula
Calculate in SI unit
how to get the number 231? thx for replying
The number 231 is a constant. It represents how many cubic inches are in a gallon.
@@KletteTech thx for replying. this is a formula in CKD cylinder handbook
Q=A*V*((P+0.1013)/0.1013)*(10^-6)*60
which Q : l/min D : mm V : mm/s P : mpa
why does his formula show the piston speed is related to the air pressure?
I am not sure. I have not seen the handbook. If it is talking about pnuematic cylinder that is a different formula all together. This is for a hydraulic cylinder.
@@KletteTech thx for replying again, our discussion above shows why a hydraulic system is more stable than pneumatic on the topic "Incompressibility".
@@chianyuchen8152 Could not agree more. Any other conversions you want to have, please reach out.
pretty sick vid bro keep up the stellar work!! :)
Just to understand. Why arent we considering the stroke length of the cylinder. Why arent we considering pi r*r*h because technically the cylinder moves for the stroke length. I would appreciate if you can help me understand
Stroke length does not affect speed. The cylinder can be 2 ft or 20 feet and the speed as which it moves will be the same.
@@KletteTech Thank you for clearing my doubt.
How do you calculate the cylinder speed with a known load? Say the cylinder is pushing / pulling 500 lbs.
Great question. There are a number of factors that come into play. If there is not a flow control or a non compensated flow control, you need to know that GPM going to the cylinder. This will change based on the load. The more load less GPM and visa versa. You also need to take into account the other components in the system. If the GPM is not known then there are formulas for figure that out but they go beyond what I have in this video and there only estimates. Also, remember that the speed will be different on the return (fast with the same GPM) because there is less volume on the cylinder return because of the cylinder rod.
@@KletteTech This was a question on a classroom lab I had last week. Major cylinder area was 12.566 sq. in. and minor cylinder area was 10.161 sq. in. Cylinder was had a static load of 800 lbs. on extension and retraction. Psi for extension was 63.66 psi. Psi for retraction was 78.73 psi. Was asked to calculate cylinder speed in inches per minute. The only formula in the textbook was for an unloaded cylinder which the instructor allowed us to calculate for since he couldn't provide the formula for a loaded cylinder. The flow was 4 gpm thus giving a extension speed of 73.5 ipm and retraction speed of 90.9 ipm. Have searched for one but have been unable to find it.
John S once I’m at my computer I will send you the answer.
@@johns8771 Your answer is actually correct. The trick to this question is that the 4 gpm is actually taking into account the load. Depending on the circuit's components the load can or cannot have an affect on the GPM entering the cylinder. Either way, once the gpm has been given or discovered the load no longer affects the speed. To summarize, the load only affects gpm. Once gpm is known the formula is the same for loaded on unloaded cylinders. Make sense?
@@KletteTech Yes it does. Thanks for the information.
0.785 is it steel density?
.7854 is the constant to convert from diameter to area.
Here is a video explaining it.
ruclips.net/video/7dkjGTf1Kak/видео.html
Formula plsss...
USE SI UNIT who use foot arms length damn ?
Thank you
Sir. Ple translate in Hindi