There is a mistake in this video. With no friction and constant pipe diameter and height, there is no drop in pressure. This comes from conservation of momentum. A frictionless pipe with constant cross sectional area ought to flow forever with constant velocity and pressure, same way a ball thrown in space with no other forces acting on it goes in a straight line forever. The claim that the velocity increases with constant diameter violates continuity of flow rate for an incompressible fluid (constant flow rate Q = v*A -> constant area means constant velocity) . Bernoulli's equation dictates that if velocity and height are constant, then pressure is also constant (if you neglect friction).
Yep, there is no head loss in an inviscid flow in a pipe. Therefore trying to explain head loss with Bernoulli's Equation that holds true for inviscid flow is incorrect however there is a version of the equation for viscous flow and that must be used in the analysis.
There appears to be an error in the video. In ideal conditions, particularly when the cross-sectional area of the pipe remains constant, a static pressure drop does not occur. It is imperative to recall the principle of continuity equation in this scenario.
This video is not completely correct. But watching this you will surely understand about the Pressure drop and Pressure loss thing. and How pressure loss is related to head loss. 0:41 Static pressure decreases along the length of horizontal pipe(should have been converging pipe) along ideal fluid .. well that's where it gets wrong and messed up the whole energy balance.
omg what a video this song is for u read this!! u made my life easy bro!! hope this channel will grow!! ur tutorial are so good it brightens up my mood watching this having my food!! i want to climb thank u niltime!!
1:21 how to determine the velocity head? is it from its literally 'velocity' of water? if it's so, how could the water move faster in the identical pipe?
1:25 But v1.a = V2.a If both areas are equal how is it that the velocity can be different Are you sure pressure must be different? What if they're equal, wouldn't the liquid be in constant velocity?
If head loss is the head difference between entering region head - exiting region head, why we add pump head to the head loss equation. The head of pump already effected the head loss, why we add to the equation again???
I have a dought when velocity decrease the pressure will be increases therefor in tube column the hight of water level will be increase according to Formula h=P/pg I am not sure that I am right please solve my dought
I have a question about the pump with regard to the head loss that it is tasked to overcome. Did we not say that when the fluid velocity is increased, this creates a lower P2 pressure? So then why does speeding up the fluid somehow overcome the loss when before we said that an increase in velocity actually causes a pressure loss?
Please dont get confused here. Increasing velocity never creates pressure loss.. but it might create pressure drop. In an ideal fluid and ideal pipe, pressure loss donot exist, but there exist pressure drop. Here the initial energy of fluid is equal to final energy. So the equation is balanced in ideal fluid. And we donot need pump. Energy is conserved/constant. But in frictional fluid there is pressure drop as well as pressure loss. This presaure loss is created due to friction between layer of fluid .. roughness of pipe .. and many other reason (but not of increasing velocity) . Here The energy of fluid decreases and disseapear completely to atmosphere. So in order to give energy to fluid .. which is to overcome these pressure loss ... we use pump.
@@NiLTimeAlright so the pump increases the velocity of the fluid right, or does it simply return that velocity to its original state? And if it increases the velocity even further than the original state, would there not be a pressure drop between the entrance of the pump and the exit, essentially? Btw thanks for the answer, I didn’t choose my words carefully but I meant “pressure drop” in all cases.
@@grantstidham9322 @Grant Stidham it is better to say ..Pump gives energy to the fluid. It can return energy back to original state or increases it even more. Of course there would be pressure drop between inlet and outlet . More pressure drop .. more electric energy it consumes . The electric power that motor consumes is proportional to its pressure drop ...
what does it mean having a negative head loss? i am working on a project about hydraulic ram pump, and a few of my design cases yielded negative head loss, while some have positive head loss.
Check units first! Maybe your friction coefficient is just that low! I don't think hL can be negative. Maybe you mixed up your hL calcs? There are two formula for laminar + turbulent, thus two divergent paths, in terms of arriving at a value.
Good animation but theory is really really incorrect. Is it possible to reupload with a converging pipe? Can’t help but think how many people are led astray. Fluid increasing in speed across the same diameter violates conservation of mass.
brother Im having one doubt . if velocity 2 is greater than velocity 1 , then why we are cancelling velocities on both the sides while solving numerical . pls reply brother
If the diameter stays constant the velocity stays constant so it cancels out. The continuity equation (Q=vA) details this concept. For the velocity to change as the video states there must be a change in the pipe diameter (cross sectional area)
Beware of the wrong concept of pressure drop in straight pipe of constant crosssectional area . It breaks the continuety and conservation of mass cant be satisfied.
There are mistakes in this video 😮 1) velocity can't change without a change in area due to the continuity equation 2) You can't consider the drop in the turbine if point two is before the turbine
Cara atasi Head Loss pada pipa tekukan. inovator Gendhut Hadun Jr The Pooh dan Bagus Permono Immanuel .Tokoh inovator Surabaya ...wavin.rucika . ruclips.net/user/shorts34iHW7VaQBo?si=cd8gbV8Kzcf31oEO
I learned more from this video than a whole semester of fluid mechanics
me too hahaha
its mad coz I acc did you lot don't understand hahaha
🤓
Without this whole semester, you wouldn't be able to understand a single word from this video.
I am convinced animation videos like this help ten fold, thank you
There is a mistake in this video. With no friction and constant pipe diameter and height, there is no drop in pressure. This comes from conservation of momentum. A frictionless pipe with constant cross sectional area ought to flow forever with constant velocity and pressure, same way a ball thrown in space with no other forces acting on it goes in a straight line forever.
The claim that the velocity increases with constant diameter violates continuity of flow rate for an incompressible fluid (constant flow rate Q = v*A -> constant area means constant velocity) . Bernoulli's equation dictates that if velocity and height are constant, then pressure is also constant (if you neglect friction).
yeah I am aware of it . I should have modeled converging pipe here. Thank you for commenting it out. Hope everyone sees it ^^
Yep, there is no head loss in an inviscid flow in a pipe. Therefore trying to explain head loss with Bernoulli's Equation that holds true for inviscid flow is incorrect however there is a version of the equation for viscous flow and that must be used in the analysis.
Thanks for existence of your channel Mr. Itachi.
It has clear my age old doubt,
🙏🙏🙏🙏🙏
Slay because this what everything I wanted to see. Thanksssss
Animations are best way to understand its revolution of learning
this is a master class animation.thanks
There appears to be an error in the video. In ideal conditions, particularly when the cross-sectional area of the pipe remains constant, a static pressure drop does not occur. It is imperative to recall the principle of continuity equation in this scenario.
yeah, after spelling because as "cuz" in their video, they lost all credibility to me
great 👩❤️👩clear my whole confusion
great video, I liked the animations
Q=AV , in constant diameter pipe how is the velocity changes due to pressure change ??!
Really usefull thnx nd love from India ❤️
Greatest explanation ever i have seen 🙏
Finally i understand ,what is head loss .....😊
This is some serious content. please upload more videos related to fluid mechanics
Thank you for nice explaination.
This video is not completely correct. But watching this you will surely understand about the Pressure drop and Pressure loss thing. and How pressure loss is related to head loss.
0:41 Static pressure decreases along the length of horizontal pipe(should have been converging pipe) along ideal fluid .. well that's where it gets wrong and messed up the whole energy balance.
Thanks bro...but it'll be much helpful if you rectify the video and re-upload it. You're work is amazing. Helps us understand the concept clearly.
omg what a video
this song is for u read this!!
u made my life easy
bro!!
hope this channel will
grow!!
ur tutorial are so good
it brightens up my mood
watching this having my food!!
i want to climb
thank u niltime!!
1:21 how to determine the velocity head? is it from its literally 'velocity' of water? if it's so, how could the water move faster in the identical pipe?
I also did not understand this - if there is no friction or change in height etc... why would the velocity increase/static pressure decrease?
@MrHumourTumour chill guys . A big mistake . Should have made a converging pipe. Forgive me. :3
1:25
But v1.a = V2.a
If both areas are equal how is it that the velocity can be different
Are you sure pressure must be different? What if they're equal, wouldn't the liquid be in constant velocity?
Nice Explanation 😀
Thanks for the video dear
this video saved my lab report
Very Nice Explanation pls make more such vedios on various fluid mechanics concepts 🙏🙏
Sure I will try my best ^^
If head loss is the head difference between entering region head - exiting region head, why we add pump head to the head loss equation. The head of pump already effected the head loss, why we add to the equation again???
Best video
Great,,one 🙏,,
Many many thanks ^^
Bro your videos are awesome .. pls make some videos on potential function and stream function and fluid kinematics too
Sure I will. I am focusing on them :)
Hey NiLTime. What are the resources you used to make these videos? They are awesome.
please Do a video on turbulent flow
I have a dought when velocity decrease the pressure will be increases therefor in tube column the hight of water level will be increase according to Formula
h=P/pg
I am not sure that I am right please solve my dought
I have a question about the pump with regard to the head loss that it is tasked to overcome. Did we not say that when the fluid velocity is increased, this creates a lower P2 pressure? So then why does speeding up the fluid somehow overcome the loss when before we said that an increase in velocity actually causes a pressure loss?
Please dont get confused here. Increasing velocity never creates pressure loss.. but it might create pressure drop. In an ideal fluid and ideal pipe, pressure loss donot exist, but there exist pressure drop. Here the initial energy of fluid is equal to final energy. So the equation is balanced in ideal fluid. And we donot need pump. Energy is conserved/constant.
But in frictional fluid there is pressure drop as well as pressure loss. This presaure loss is created due to friction between layer of fluid .. roughness of pipe .. and many other reason (but not of increasing velocity) . Here The energy of fluid decreases and disseapear completely to atmosphere. So in order to give energy to fluid .. which is to overcome these pressure loss ... we use pump.
@@NiLTimeAlright so the pump increases the velocity of the fluid right, or does it simply return that velocity to its original state? And if it increases the velocity even further than the original state, would there not be a pressure drop between the entrance of the pump and the exit, essentially?
Btw thanks for the answer, I didn’t choose my words carefully but I meant “pressure drop” in all cases.
@@grantstidham9322 @Grant Stidham it is better to say ..Pump gives energy to the fluid. It can return energy back to original state or increases it even more. Of course there would be pressure drop between inlet and outlet . More pressure drop .. more electric energy it consumes . The electric power that motor consumes is proportional to its pressure drop ...
Plastic also gradually develops cracks and abrasions, that's why causes head losses
Never thought Itachi would help me revise fluid mechanics 😂
best viedo
great job!
Thx ^^
mah 4 month sem could not teach me this , but this 5min 15 sec video did. :>
Thank you for interesting lecture..I think we can also reduce friction losses by providing timber and natural materials that has less friction
timber pipes? what?
You are on drugs mate
Do we need to used fluid variable (water) always whenever we calculate the P drop? Or do we need to consider the flow medium?
higher viscosity fluids will result in greater frictional head loss and hence pressure drop as well
Does increase in loss of head mean that my pressure is low?
I fucking love this channel
what does it mean having a negative head loss? i am working on a project about hydraulic ram pump, and a few of my design cases yielded negative head loss, while some have positive head loss.
Check units first! Maybe your friction coefficient is just that low! I don't think hL can be negative. Maybe you mixed up your hL calcs? There are two formula for laminar + turbulent, thus two divergent paths, in terms of arriving at a value.
Good animation but theory is really really incorrect. Is it possible to reupload with a converging pipe? Can’t help but think how many people are led astray.
Fluid increasing in speed across the same diameter violates conservation of mass.
Grateful
Good Job
THx ^^
You can't pause life. That's why I always learn chemical engineering!
Thanks... 🇧🇩🇧🇩♥️♥️
the question is how to simulate the fluid correctly?
how the turbine decreases the pressure=P2???
what are the type of pressure involve in pressure drop analysis???
type of pressure?
brother Im having one doubt . if velocity 2 is greater than velocity 1 , then why we are cancelling velocities on both the sides while solving numerical . pls reply brother
If the diameter stays constant the velocity stays constant so it cancels out. The continuity equation (Q=vA) details this concept. For the velocity to change as the video states there must be a change in the pipe diameter (cross sectional area)
Nice explanation man.
WLC btw ^^
thank you
WLC ^^
Beware of the wrong concept of pressure drop in straight pipe of constant crosssectional area . It breaks the continuety and conservation of mass cant be satisfied.
There are mistakes in this video 😮
1) velocity can't change without a change in area due to the continuity equation
2) You can't consider the drop in the turbine if point two is before the turbine
This will make me remember that pressure head = pressure/(density * gravity)
yeh ^^
In the final part, ig the point 2 should be situated after the turbine.
i wish this cyborg was my teacher!
haha yeah me too ^^
bro what is your job are you teacher or student?
Just Graduated this year on feb 2021 ^^
@@NiLTime im happy to hear that, i wish you the best :))
what does iireversible even mean here
Hi
I can’t understand these robot voices.
video is totally wrong , must have made a converging pipe
about decreasing static pressure? yeh for ideal fluid :)
wtf is this "CUZ of friction"? Is that supposed to mean "because". How are you teaching engineering, but using slang!?!?
Cara atasi Head Loss pada pipa tekukan. inovator Gendhut Hadun Jr The Pooh dan Bagus Permono Immanuel .Tokoh inovator Surabaya ...wavin.rucika . ruclips.net/user/shorts34iHW7VaQBo?si=cd8gbV8Kzcf31oEO
Thank you