Organometallic Chemistry Basics I: The 18 Electron Rule

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  • Опубликовано: 2 дек 2024
  • In this video the concept of the 18 electron rule will be introduced and developed using the charged (oxidation state) formalism.

Комментарии • 27

  • @AbrihamTsano-bt6xq
    @AbrihamTsano-bt6xq 8 месяцев назад

    Waa very amazing lecturer method

  • @adamjanks4966
    @adamjanks4966 2 месяца назад +1

    Thank you !

  • @sya5599
    @sya5599 3 года назад +2

    could someone explain at 7:17, why is the iron a zero iron? thank you in advance.

    • @Shorty50
      @Shorty50 2 года назад +1

      CO is a neural ligand if we were to remove it, it would be neural CO

  • @anthonymaputi1477
    @anthonymaputi1477 3 года назад +2

    I have some reservation on the way you compute TiCp2Cl2. Why is Titanium having a charge of 0?

    • @brianng7238
      @brianng7238 2 года назад

      The titanium atom doesn't have a charge of 0; contributes 0 electrons. Titanium is a d4 metal; the 2 cyclopentadienyl (Cp) and 2 chlorine (Cl) ligands are all anionic, and thus influence the oxidation state of the titanium from d4 to d0, which is why it only contributes 0 electrons.

  • @jiminhwang3811
    @jiminhwang3811 2 года назад +1

    Thanks giving the great video.

  • @sarvanks7711
    @sarvanks7711 Год назад

    Excellent

  • @TheDnPiano
    @TheDnPiano 4 года назад +4

    Thank you very much sir!

  • @about9466
    @about9466 3 года назад +1

    ive been wondering how of organometallic can contain platinum, the most strong metal, is it possible? or there already like dimethyl or not dimethly platinum? like the dimethyl mercury, hm... confusing

    • @lozbear
      @lozbear 3 года назад +3

      There are plenty of organometallic platinum species. A very famous example is Zeise's salt, which features a platinum bonded to ethene. While platinum metal is generally unreactive (I'm assuming that's what you mean by 'strong'), you can get it to react. You just have to use some forcing conditions.

  • @trevorbroadhurst7794
    @trevorbroadhurst7794 2 года назад

    the symbol for lead is Pb not Pd.

  • @J0DD0J
    @J0DD0J 4 года назад +3

    Fe(0) is 4s2 3d6, not 3d8; and Mn(0) is 4s2 3d5, not 3d7?

    • @michaelwildy1408
      @michaelwildy1408 4 года назад +2

      d7 is representing the number of valence e-

    • @jakesmith6544
      @jakesmith6544 3 года назад +1

      When transition metals are bonded the 3d orbitals get occupied first, the 3d orbital becomes lower in energy than the 4s.

    • @ReadyViewer1
      @ReadyViewer1 3 года назад

      @@jakesmith6544 I'm studying for a test and bewildered by this because I haven't come across it in my lecture notes.

  • @dribrahimel-nahhal2477
    @dribrahimel-nahhal2477 2 года назад

    Great vid! Thanks 👍

  • @منوعات-خ4ن
    @منوعات-خ4ن 3 года назад

    , the number of e for TiCp2Cl2 is 18 as I think, why you didn't count cl electrons?

    • @brianng7238
      @brianng7238 2 года назад

      The number of electrons should be 16, because this is a square planar structure. Octahedral complexes usually contain 18 electrons, but these numbers can vary from time to time depending on the ligands, such as with olefins. He did count the Cl electrons; he write 2(Cl-) = 4 e's.

  • @aj.5127
    @aj.5127 3 года назад +2

    Can you help me to answer my homework in 18 electron 🤦🏻‍♀️🥺😭😭

  • @trz_653
    @trz_653 2 года назад

    Pd is palladium d- block element

  • @kakandesimonsimon5895
    @kakandesimonsimon5895 7 месяцев назад

    Thank yu

  • @kataetwas2825
    @kataetwas2825 3 года назад +2

    You meant Pb in the beginning, but wrote Pd

    • @markrodonis1912
      @markrodonis1912 3 года назад +1

      Thank you for your comment - I couldn't understand why he would call Palladium a p-block element.

    • @fazran_7794
      @fazran_7794 3 года назад

      Me tooo 😂

  • @ZnooAdam2
    @ZnooAdam2 3 года назад

    Iraq 😻