Hey man i have no clue how no one's probably said this to you, but you're a life saver, probably an angel honestly 😂❤️ you're saving my A levels grade thank you soo much ❤️❤️❤️
Sir. For the first one, can you not draw |3x-5| on it's own. And then do y=4 separately. When I draw |3x-5| i get the y intercept as 5. I'm so confused. Note: When I solve it using 3x-5=4 And -3x+5=4 I get the same answers as you Thanks
Yes you can - both of these methods are synonymous. It's like solving the equation 2x + 5 = 3 and x + 5/2 = 3/2 are the same. The reason I did it this way in this video is that I've found a number of students have found it difficult to interpret the vertex of the modulus graph for y = |3x - 5|, and they have been happier when I factored out the 3 to get y = 3|x - 5/3|
Do you mean in order to solve |4x+3| = -2 ? This won't have any solutions as |4x+3| >= 0. As can be seen here the graphs don't intersect www.desmos.com/calculator/zpnk15e4yn
I'm not sure what I'd say... The best I can do is direct you to my tips videos: sites.google.com/view/tlmaths/home/a-level-maths/revision-tips-videos?authuser=0
The issue here is that you're suggesting that y = |x - 5/3| and y = x + 5/3 are the same function. However, when you substitute in x = -1, for example, you get y = |-1 - 5/3| = 8/3 for the first, and y = -1 + 5/3 = 2/3 for the second. So they can't be the same.
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Hey man i have no clue how no one's probably said this to you, but you're a life saver, probably an angel honestly 😂❤️ you're saving my A levels grade thank you soo much ❤️❤️❤️
You're one of the greatest teachers ,I've ever came across .Thank you for being kind.
Sir. For the first one, can you not draw |3x-5| on it's own. And then do y=4 separately. When I draw |3x-5| i get the y intercept as 5. I'm so confused.
Note: When I solve it using 3x-5=4
And -3x+5=4 I get the same answers as you
Thanks
Yes you can - both of these methods are synonymous. It's like solving the equation 2x + 5 = 3 and x + 5/2 = 3/2 are the same. The reason I did it this way in this video is that I've found a number of students have found it difficult to interpret the vertex of the modulus graph for y = |3x - 5|, and they have been happier when I factored out the 3 to get y = 3|x - 5/3|
Makes so much sense
Ur videos are really helpful can u make more teaching videos for further As in this style
As soon as I can
at 5:34 why did you take the mod of -4
If |3x-5| = 4, then either 3x-5 = 4 or 3x-5 = -4 because |4| = 4 and |-4| = 4
You should also add a step into the first method where you identify the ranges for the positive and negative parts.
What do you mean?
do we essentially treat the modulus lines as brackets?
Sometimes it may seem that way. You can't expand a modulus function like you can brackets though
@@TLMaths oh alright thank you
you can't use the second method for questions where the equation is equal to a negative number such as 4x+3=-2, is that right?
Do you mean in order to solve |4x+3| = -2 ? This won't have any solutions as |4x+3| >= 0. As can be seen here the graphs don't intersect www.desmos.com/calculator/zpnk15e4yn
@@TLMaths right, thank you
Hi, wouldn’t it be crossing the y axis at 5? Because when you solve y when X=0 the mod of the equation is 5
I've sketched y = |x - 5/3|, not y = |3x - 5|
@@TLMaths thank you!!
Thanks a lot!!!!
could you make an a level maths motivation video :(?
I'm not sure what I'd say... The best I can do is direct you to my tips videos: sites.google.com/view/tlmaths/home/a-level-maths/revision-tips-videos?authuser=0
@@TLMaths a rocky spin off sequence would suffice
Well next time I'm in Philadelphia, I'll film myself running up the steps and jumping about at the top.
Amazing
When doing |x-5/3| =4/3
Why doesn’t the modulus make it positive
So it would be x+5/3=4/3
The issue here is that you're suggesting that y = |x - 5/3| and y = x + 5/3 are the same function. However, when you substitute in x = -1, for example, you get y = |-1 - 5/3| = 8/3 for the first, and y = -1 + 5/3 = 2/3 for the second. So they can't be the same.
how would you solve |3x+4|=x
The graphs of y = |3x+4| and y = x don't intersect so there are no solutions to that equation: www.desmos.com/calculator/x5buonpynn