how come the coordinates arent (5,0) for the third question? doesn't it become positive either way when it's a modulus function? or is it because we are completing the square? thanks
If you substitute x=5 into the equation y = |2x + 10| you get y = |2*5+10| = 20, not zero. When you substitute a negative number in, you don't change it to being positive before you substitute it in.
comparing it to completing the square - such a good method, never heard of it before. Thanks!
this guy is a legend
I love your videos my dawg. Praying they get me through my exam today. Big love
Nicely explained in easy way
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Nicely edited
Wow! Very clearly explained! :)
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Nice video, thanks❤
Why isn't the vertex (5,0) for Q3? I though you have to take the modulus (positive) of 5
But x=-5 makes what is inside the modulus zero, and hence y is zero at that point. So the vertex is at (-5,0).
how come the coordinates arent (5,0) for the third question? doesn't it become positive either way when it's a modulus function? or is it because we are completing the square? thanks
If you substitute x=5 into the equation y = |2x + 10| you get y = |2*5+10| = 20, not zero. When you substitute a negative number in, you don't change it to being positive before you substitute it in.
Good sir
How come it hasn’t been reflected for when y
When x = 3, you get y = |3 - 3| - 3 = -3, so the graph definitely goes below the x-axis?