Use polynomial division on -x/(x+2) to get -1 + 2/(x+2). So starting with y = 1/x Stretch parallel to the y-axis factor 2: y = 2/x Translate by the vector [-2,-1] y = 2/(x+2) - 1 which is the same as y = -1 + 2/(x+2) = -x/(x+2)
I'm having trouble deriving what y = 1 /2-x would look like from y = 1 /x. if i do y = 1/-x first i get the y = 1/x reflected in the y -axis, which is fine, but then if i add the 2 (y =1/2-x) i get a translation of 2 spaces left, which is incorrect, it should be 2 spaces right. if i do y = 1/x-2 first i get a translation 2 units right, which is fine, but then when i multiply the bottom by -1 i get y = 1 / 2 - x, and since we have multiplied the x by -1, we reflect in the y-axis and get y = 1/2-x as being y = 1/-x translated 2 to the left. can you explain how you would go about doing it so that you get the right answer, and what i am doing wrong.
1/x Translate the graph by the vector [-2,0], replaces the x with x+2 1/(x+2) which is the same as 1/(2+x) Then reflect in the y-axis, which replaces the x with -x. 1/(2-x)
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This is outrageously helpful
Have my paper tomorrow, thanks alot!
Getting ready for A-level maths next year. Really helpful.
Tariq Lamptey maths 🔥🔥⚡
Really helpful, thank you
11:05, would I be right to say that via the BIDMAS method the minus would be considered first before the translation of +6?
Yes
But both gives the same result right?
Great vid explained so well thx
amazing teacher :)
you are THE GOAT
Thank you so much that was really helpful!
3:23 sir why do you move it to the right when it's minus
Go back to ruclips.net/video/rY05LSy9usA/видео.html&feature=emb_logo
I love your videos
Howm can i get from 1/x to -x/x+2?
Use polynomial division on -x/(x+2) to get -1 + 2/(x+2).
So starting with y = 1/x
Stretch parallel to the y-axis factor 2:
y = 2/x
Translate by the vector [-2,-1]
y = 2/(x+2) - 1
which is the same as
y = -1 + 2/(x+2) = -x/(x+2)
TL maths is the goat
What a vid! Crazy help
At 3:23 why do we move it to the right when its -2? Thank you for the vid btw
Helped me a lot
Thank you so much
nice video bro
THANK YOU SO MUCH!!!
how is it a positive on q5 for (x-3)2 if its inside the bracket?
sorry im confused
Thanks
thanks sir
I'm having trouble deriving what y = 1 /2-x would look like from y = 1 /x.
if i do y = 1/-x first i get the y = 1/x reflected in the y -axis, which is fine, but then if i add the 2
(y =1/2-x) i get a translation of 2 spaces left, which is incorrect, it should be 2 spaces right.
if i do y = 1/x-2 first i get a translation 2 units right, which is fine, but then when i multiply the bottom by -1 i get y = 1 / 2 - x, and since we have multiplied the x by -1, we reflect in the y-axis and get y = 1/2-x as being y = 1/-x translated 2 to the left.
can you explain how you would go about doing it so that you get the right answer, and what i am doing wrong.
1/x
Translate the graph by the vector [-2,0], replaces the x with x+2
1/(x+2)
which is the same as 1/(2+x)
Then reflect in the y-axis, which replaces the x with -x.
1/(2-x)
Goat