That last example was what I was looking for. So many times I got a little bit confused on why or how voltage division was used in the middle of a circuit. But that last example gave me the exact knowledge on how and when to use voltage division. Thank you very much.
Thank you so much!!!! I don't know why I pay money for university when they just can't explain it in 2 hours that took you almost 12 minutes!! + I love how you have a good handwriting that is easily to understand and everything is also awesome 👍🏻 Thank you so much sir I'm definitely going to subscribe and study from your channel. 💗
Sebastian, Glad you liked the video. All my videos start with "ECE 100" so if you search for "ECE 100 Nodal Analysis" you should find about six videos that may be helpful to you.
I have a transformerless LED driver from a China LED Bulb but it's voltage output is more than 300V DC. Can I reduce the V-out to 45V DC using this Voltage Divider Method? Will it be safe to used to turn on several SMD LED in series??
Max, I'm afraid that I can't answer your question, because it would all depend on how much current the LEDs draw. In the limit where they draw zero current (Which is certainly not the case), then this circuit could be used safely as you suggest. But I think you'd be better off using a transformer to ensure the circuit operates properly. Doug
We do this so that we can calculate the current. It is much easier if we simplify the circuit down to a single voltage source connected to one resistor, and then we work our way back to the original circuit.
V2 is the voltage across the parallel combination of 3 ohms and 6 ohms, which is 2 ohms combined. This will also be the voltage across both the 3 ohm and the 6 ohm resistors.
Im a little confused with how you found the voltage division for V_a from the last problem. how did you know to do V_a=15(7.5/7.5+15) instead of V_a=15(15/15+7.5)? I would really appreciate it if someone could explain this for me
Va is the voltage on top of the 7.5ohm resistor in the last circuit diagram. Another way of saying this is that it is the voltage between the indicated node and the reference node. In other words, it is the voltage across the 7.5ohm resistor. Since voltage division always places the resistor we are considering in the numerator, it is correct to say that Va =15(7.5/(15+7.5)). The alternate equation you suggested would be used to find the voltage across the 15ohm resistor, which is not correct.
To find V5 in the last example it is probably easier to apply Thevenin's theorem to the circuit assuming the 5 ohm resistor is the load. You still have to use voltage division (twice) with this approach but it is still much easier than collapsing the circuit only to have to expand it again.
That last example was what I was looking for. So many times I got a little bit confused on why or how voltage division was used in the middle of a circuit. But that last example gave me the exact knowledge on how and when to use voltage division. Thank you very much.
Same here.
thanks
I could never wrap my head around some of the more complicated voltage division problems, but that last example really helped me. Thanks!
FORREAL BRO
Your presentation is OUTSDANDING!
GREAT, GREAT, GREAT explanation.
👏👏👏👏👏👏👏👏👏👏👏👏
Thank you so much!!!!
I don't know why I pay money for university when they just can't explain it in 2 hours that took you almost 12 minutes!!
+ I love how you have a good handwriting that is easily to understand and everything is also awesome 👍🏻
Thank you so much sir I'm definitely going to subscribe and study from your channel. 💗
the education system is annoying
Thank you for that classic voltage division.Am sure everyone was looking for the last one.
by law this should be the standard introduction video for this topic. 30 seconds and i totally answered all 4. thank you bro-sifff
I spent hours trying to solve a problem like this ! Thank you very much !!
I am from India. You are amazing
Your 's videos helps me alot
Thank you so much 🥰💞
best explanation on youtube for voltage division
Couldn't appreciate this video enough. Saved the day!
Beautifully done. Great examples and great teaching.
Wow, this is actually such a good explanation. Thanks for making this!
Amazing presentation. Thank you Sir!
Awesome explain. Gurudev
Super video Sir. Thank you very much indeed. V informative.
sir why did u use 7.5 ohms but not 15 ohms to get voltage at A
This video is very useful for students...thank you sir
I can’t thank you enough sir 😢❤
Dude I FU#*ING love you! This vid blows my university professor out of the water EASY!
Why did you not have to include the 15 ohm resistor in your division? Why wasn't the last equation 5V * (5/5+15+10)?
thanks, you explain really well you should do a Node Voltage Method video!
Sebastian, Glad you liked the video. All my videos start with "ECE 100" so if you search for "ECE 100 Nodal Analysis" you should find about six videos that may be helpful to you.
I have a transformerless LED driver from a China LED Bulb but it's voltage output is more than 300V DC. Can I reduce the V-out to 45V DC using this Voltage Divider Method? Will it be safe to used to turn on several SMD LED in series??
Max,
I'm afraid that I can't answer your question, because it would all depend on how much current the LEDs draw. In the limit where they draw zero current (Which is certainly not the case), then this circuit could be used safely as you suggest. But I think you'd be better off using a transformer to ensure the circuit operates properly.
Doug
Best explanation ever...
this man's mic is amazing
Thanks, here it is if you want one of your own: www.amazon.com/Blue-Snowball-Condenser-Microphone-Cardioid/dp/B014PYGTUQ/
Why we are finding equivalent parallel resistance if voltage is same for parallel connection? Please explain that part. @Doug Tougaw
We do this so that we can calculate the current. It is much easier if we simplify the circuit down to a single voltage source connected to one resistor, and then we work our way back to the original circuit.
@@dougtougaw7681 ok ...thank you sir.
Thank you very much!
Great explanation, thank you!
4:46 SEC SHOULD BE R2. GREAT WORK THO. KEEP IT UP. THANK YOU.
Good catch on that error! I got the number right but wrote the equation wrong at 4:46. Thanks for catching it, and thanks for the positive feedback.
@@dougtougaw7681 Absolutely! This just means we are paying really close attention to your lecture :P
I love this
Thank you so much for this!
amazing content
Hi;
You are good ...thanks:🙏🥂🤝
R1 must be R2 ..
but you calculate the voltage 2 on the resister 2 ohm not 3 ohm
V2 is the voltage across the parallel combination of 3 ohms and 6 ohms, which is 2 ohms combined. This will also be the voltage across both the 3 ohm and the 6 ohm resistors.
Im a little confused with how you found the voltage division for V_a from the last problem. how did you know to do V_a=15(7.5/7.5+15) instead of V_a=15(15/15+7.5)? I would really appreciate it if someone could explain this for me
Va is the voltage on top of the 7.5ohm resistor in the last circuit diagram. Another way of saying this is that it is the voltage between the indicated node and the reference node. In other words, it is the voltage across the 7.5ohm resistor. Since voltage division always places the resistor we are considering in the numerator, it is correct to say that Va =15(7.5/(15+7.5)). The alternate equation you suggested would be used to find the voltage across the 15ohm resistor, which is not correct.
Doug Tougaw ahh ok I see. Thanks for taking your time to help out!
My pleasure!
Awesome
thank you sooo much
thanks mate!
To find V5 in the last example it is probably easier to apply Thevenin's theorem to the circuit assuming the 5 ohm resistor is the load. You still have to use voltage division (twice) with this approach but it is still much easier than collapsing the circuit only to have to expand it again.
thanks sir
U saved me thx
Danke
thanks a lot
helpful video ta
Hello sir ECE, I would loved you be my TEACHER.
There's a rule that says voltage is same in parallel circuits🙂
Why does he beg us to solve it “please”?😩