Current Dividers Explained!

This physics video tutorial provides a basic introduction into the current divider circuit. It explains how to calculate the current flowing through each resistor in a two resistor parallel circuit using a simple formula given the total current entering the circuit. It also includes examples with a parallel circuit with three resistors and one with four resistors in parallel. The voltage across each resistor in a parallel circuit is the same and the currents flowing through each branch must add to the current entering the circuit based on kirchoff's current law / junction rule. This video contains plenty of examples and practice problems for you to master this concept.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
How To Solve DC Circuits:
• How To Solve Any Resis...
_________________________
Voltage Divider Circuit:
• Voltage Divider Circui...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
____________________________
KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Norton's Theorem - Circuit Analysis:
• Norton's Theorem and T...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...

[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/

[@MS-qh3iz]

Been using his videos for all my uni classes and honestly what an absolute genius. It really takes a lot of skill explain EVERYTHING so clearly and concisely. Absolutely impressed.

[@taiedy]

How Current Divider Formula is derived:
In parallel, the voltage across the two resistors is the same. Thus, V1 = V2.
And we know V1 = I1 * R1 & V2 = I2 * R2. Thus, I1 * R1 = I2 * R2.
Also, Sum of I (in) = Sum of I(out) as in Kirchhoff's Current Law, thus, I (total) = I1 +I2.
We know have two simultaneous equations:
I1 * R1 = I2 * R2 .................... (i)
I(total) = I1 + I2 ..................... (ii)
If you sustitute I1, you get the formula to find I2:
I2 = I(total) [(R1)/(R1 +R2)]
If you sustitute I2, you get the formula to find I1:
I1 = I(total) [(R2)/(R1 +R2)]
Hope this helps!

[@vanshkhoshya3297]

Thanks

[@memesop8812]

Who asked for it

[@raed9152]

@@memesop8812 STFU he is trying to give more help

[@arki3134]

@@memesop8812 your mom

[@memesop8812]

@@raed9152 toh muhmelele uska usko bhi return me help ho jayegi

[@TheHonchoofAllSpearheads]

The most comprehensive CDR tutorial video yet! You generally explained at every inch and all of the plausible techniques we can use other than merely CDR!

[@johngalan3754]

You deserve much more credit than you're given. You have helped me with nearly every subject I've taken in a very sensible and cohesive manner. Keep doing what you do!

[@G12eem]

Which subjects do you study?

[@kennedymukwakwa]

Can you please come teach us at the university of Zambia 🙏

[@manwahal-mashani8910]

This is probably the best hands-on explanation I've seen.
THANK YOU SO MUCH!

[@asyncawaited]

This is probably the best hands-on explanation I've seen.

[@DanielInfrangible]

Fact

[@paarthjagga7287]

Facts

[@whysohypocritical]

Thank you so much guys. You don’t know how much your videos mean to me . Sometimes I feel so sick..like I can’t understand anything..but your videos help me understand that..I’m not actually dumb. Thank you so much 👏

[@stereophotog]

It is so simple when it is explained masterly by you! Thanks!

[@EastTennesseeVol]

Such a wonderful way of presenting this. Great job!

[@joeford3727]

La mejor expresión que he podido encontrar y la más fácil, gracias hermano eres un verdadero profesional tus explicaciones son verdaderamente entendibles.....Felicidades....

[@3dilson]

Duuude, thank you so much
My teacher literally gave me the wrong formula for this, i knew that something was wrong because the value for each individual resistor didn't add up, but I didn't know why.
You just saved me

[@madjack821]

So anyway...I have this “self-teaching” pdf on electronics and it complicates this WAY too much on the basic level....👍👍 to you! Thank you!

[@origami3001]

You explained way better than what my lecturer is teaching in class.

[@millenialmuscle8254]

After 2:14 it all clicked for me thank you. The intuitive method also was very very useful in grasping the concept and application. 👍🏻👍🏻

[@tawandagame6406]

Thank you so much for such a simple, easy on-point explanation.

[@fullmetalyellowjacket8560]

I've seen this guy teach all the subjects im studying , i can tell from his voice

[@abdelrahmanharidy6930]

i spend all day in this channel because i have exam after few hours and realy thanks man i appreciate ur effort

[@joeford3727]

Gracias hermano usted no enseña para que uno aprenda solamente, usted enseña para hacer expertos ....😀 muchas gracias hermano ...

[@no2know121]

That's what I really searched for. Thanks man❤

[@asadrking]

What an amazing video. God bless you 🙏.

[@muhammedshaheer9378]

how can i thank you mate !!!! you really made it easy for me to understand . may you prosper in life . love from pakistan

[@jayjayTT868]

Excellent CDR tutorial 💯

[@baconpancakes8899]

You're really on the next level

[@shahzaibraja1650]

Truly saying you're my life saver ... Thanks man!

[@Lexyvil]

The thumbnail video alone made more sense than what my professor tried teaching in half an hour. Thank you! It's clear now.

[@cheatyhotbeef2636]

but the thumbnail is wrong though

[@andrewkachedwa3164]

This guy is really wonderful ever since

[@Erhannis]

Thanks for the (1/r1) / ((1/r1) + (1/r2) + (1/r3)) form. That seems to me the most self-explaining form of the relationship.

[@jamesbroughton2199]

I cannot begin to tell you useful this tutorial is. My McGraw hill textbook is so confusing😅

[@devillain123]

For anyone wondering an easy formula that works to find the current at any point in a parallel resistor circuit is:
I(n) = I(T) * [ R(eq) / R(n) ]
Where I(n) is the current through the resistor n
I(T) is the total current before the parallel split
R(eq) is the equivalent resistance of all in parallel which is just 1/R(eq) = 1/R(1) + 1/R(2) + 1/R(3) ...
R(n) is then the resistor you want to find the current I(n) flowing through.
This works for 2,3,4,...,∞ parallel resistor circuits.

[@Electrical-Engineering-Course]

Neat and clean. Thanks

[@thatowmoyo1075]

Thank you very much. Was a great help

[@Thoalfeqargamer]

dude ill graduate from university and it is all thanks to you😍

[@CodeWithBenoit]

This guy knows almost everything

[@mohammedsami808]

You make everything easy

[@umarbumar4767]

thanks. this was so helpful.

[@moazelsawaf2000]

Thanks sir

[@desmondantony1136]

The best explanation thanks

[@skybot9998]

Great video thanks.

[@Hunter-xc5ry]

thanks man this make sense

[@dymo7607]

thank you chemistry teacher

[@danielteyehuago1633]

Thanks for sharing it

[@sabbir8035]

Thanks a bunch!!!❤️

[@SuperMoha86]

Many thanks, you are the best😍

[@devamjani8041]

Give this guy a nobel prize

[@sultanbekserik550]

I love you, you`re the best❤

[@casp3r_de_gh0st90]

Hey man, something i noticed with this video that messed me up for a while is that the equation in the thumbnail is actually wrong and is inconsistent with what you say and show in the actual video. In the thumbnail you write “I1= R1/(R1+R2) *Is” meanwhile the actual equation should have R2 in the numerator instead of R1 when solving for the current I1 at R1. Other than that typo, great video

[@ceeb830]

I searched up the rule on Google while doing my hw and used this thumbnail because OCT has lots of credibility with me, it really messed me up for a while 😅

[@jadynjc]

@@ceeb830 glad i'm not the only one who did that lol

[@lance4377]

Hes correct but it only applies to 2 resistors. The one with the improper fractions is more universal

[@bibekpangeni7644]

Short and sweet❤

[@samshakhloul9863]

I'll send you my diploma once I've graduated, you deserve it at this point

[@sarnojoshuaadonisk.2836]

Thank you so much.

[@chiranjeevshubham690]

Nice explanation! 👏👏👏👏👏👏👏👏👏🙌🙌🙌🙌🙌🙌🙌

[@cardempire360]

THE GREATEST OF ALL TIME ###

[@terencegawthorn614]

legend, thanks cobba

[@user-hq3je7ks2z]

Thanks buddy ❤

[@luthohoney7476]

You're the best ❤🎉🎉

[@lenaibrahim9773]

THANK YOU!

[@eggxecution]

alright finally got it!

[@DolaLado]

Thank you.

[@sdbstar8515]

Amazing , but i hope you explain thevenin's theory

[@ChikotiPatrickB]

Thanks sir u have saved me 😍😍😍😍😍😍😍

[@nourelhagar8979]

Excellent

[@srushtisutar7561]

thankuu soo much sirr🥰

[@janshil0072]

Good .......excellent 👍🏻

[@aliciapark523]

AMAZING

[@gaurangsinghal5672]

Thank you sir

[@thamer6412]

Thanks to you i could be a good engineer

[@el-carry4624]

[@khoapham816]

thanks!

[@monara97]

Thank you

[@preciousjacob2500]

My man got to 1M subscribers
YAY🍻....CHEERS

[@fiona.e1026]

2 million now

[@Sanjoli3232]

You are great....👋👋👋👋🙋🙏🥂👍

[@mohammed__bkr1276]

Thank yooouuuu ❤❤❤❤❤

[@adilaymon9901]

bro tomorrow is my exam and you helped me alot today// thanks

[@ziddi_paradox]

cannot thank you enough... may christ give u all the happiness

[@simonvutov7575]

A much easier way to do this is by finding the total resistance, then find the voltage accross the parrellel resistors, and then just use I=V/R to find the currents

[@krishbhaag8391]

So does the current automatically divide itself in the correct way to be available to loads with different resistances?

[@kMuhammadUzair]

kindly explain how are we supposed to know which formula should be used as there r 2 diff formulas

[@hawkeye5611]

Nice lcm trick

[@donhjoe2162]

How can I resolve a problem with bridge circuit using this method, and the voltage divider method. I want to calculate the Vx and Ix

[@sanveersookdawe]

Thanks

[@joeford3727]

Y tu Inglés esta muy clarito hablas perfecto el ingles....thanks...

[@prabhakantpal4278]

Thankyou

[@mrOga]

Thank you so much, but were would you connect the load

[@VultureGamerPL]

We assume it's connected to both ends. It doesn't have to be drawn everytime.

[@en6820]

So whats the general formula?

[@andrewhamers8549]

There’s a mistake in the thumbnail for the equation containing 2 resistors! Should be I1 = I(R2/(R1+R2))

[@anasuniverse3834]

Why you put r2 in the first situation instead of which it need I1 and in the second situation you put r2 when he asks you for I2

[@datvo3076]

why do you have different formula for different circuits? arent they both parallels? can you apply the second formula to the first circuit?

[@aybuke2534]

Yes,you can apply.

[@mavihs26]

@@aybuke2534 how

[@SokachinEngineering]

Pls derive the current devider rule and to make this video different

[@muzz444]

What a god!

[@loganzimmerman9453]

your thumbnail is incorrect, at least for the two resistors in parallel

[@eddiesayo]

made you click thou?

[@AminataRogers556]

Please what if you have résistance in both parallel n circuit

[@astralmirage6353]

why did he use 1/R1 in the second example instead of R1 alone?

[@shr3anko31]

That's a special case for only two resistors

[@daayemshehzad]

I will graduate because of this.

[@jyotikathakkar4086]

What about when we have some in parallel and some in series

[@nathanzhao4903]

How come I see people say the equation is total current*(total resistance/resistor x)? Here you have total current*(resistor x/total resistance.

[@AndrewChedid]

the first formula I*Rt/Rx is for conductance, here he is doing the inverse of resistance which is the same as the I*Rt/Rx. He just did it as I*(Rx)^-1/(Rt)^-1.

[@stealthytrooper9233]

There is a mistake on the thumbnail for the two resistor equation. It should be R2 in the numerator.

[@dramaqueen9475]

god bless ur soul

[@user-hq3je7ks2z]

Ohww wiw ❤

[@generaljodd4535]

Topics which you study in university we study it in 11th grade in India

[@oluseyeajose-adeogun2642]

For the first example, how is there more current flowing in the lower resistance. Doesn't current flow through the path of least resistance?

[@dicko195]

you answered your own question. lower resistance is least resistance