Oxford University Pure Mathematics Entrance exam

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  • Опубликовано: 6 ноя 2024
  • University Admission Exam Question || Algebra Problem || Entrance Aptitude Simplification Test || Tricky Interview
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Комментарии • 3

  • @RealQinnMalloryu4
    @RealQinnMalloryu4 День назад

    log(2)+log(3) =5 (y ➖ 3x+2). log(2)+log(3)=5 (y ➖ 3x+2).

  • @anestismoutafidis4575
    @anestismoutafidis4575 22 часа назад

    1,4+3,6=5; 1,4•3,6=5,0
    log(1,398)=25; log(3,602)=4000
    log(25)+log(4000)=5
    log(25)•log(4000)=5
    x=25; y=4000

  • @key_board_x
    @key_board_x День назад

    Log(x) + Log(y) = 5 ← this is the sum S
    Log(x).Log(y) = 5 ← this is the product P
    Log(x) & Log(y) are the solution of the equation:
    a² - Sa + P = 0
    a² - 5a + 5 = 0
    Δ = (- 5)² - (4 * 5) = 25 - 20 = 5
    a = (5 ± √5)/2 ← this is Log(x) & Log(y)
    First solution:
    Log(x) = (5 + √5)/2
    Ln(x) / Ln(10) = (5 + √5)/2
    Ln(x) = [(5 + √5)/2].Ln(10)
    Ln(x) = Ln(10)^[(5 + √5)/2]
    → x = 10^[(5 + √5)/2]
    Log(y) = (5 - √5)/2 → then you can deduce that:
    → y = 10^[(5 - √5)/2]
    Second solution:
    Log(x) = (5 - √5)/2 → then you can deduce that:
    → x = 10^[(5 - √5)/2]
    Log(y) = (5 + √5)/2 → then you can deduce that:
    → y = 10^[(5 + √5)/2]