Moment distribution method from basics ruclips.net/video/rI9qaseL1rs/видео.html ruclips.net/video/giByuMBUSl0/видео.html ruclips.net/video/RljSGJHvt3A/видео.html
If you do that then the carry over factor will also need to be adjusted according to fixed - pinned beam. What you are saying and this method, both give same final result.
@@srinurao3327 If you do that then the carry over factor will also need to be adjusted according to fixed - pinned beam. What you are saying and this method, both give same final result.
Hello! A small confusion concerning distribution factor for member B-C. The stiffness factor for BC should be multiplied by 3/4 as the support at C is pinned. Correct me if am wrong please. Thank you.
Sir one thing is confusing a little why we are using different stiffness factors K for beam and frames...?? What are there different formulas please answer..
Moment distribution method from basics ruclips.net/video/rI9qaseL1rs/видео.html ruclips.net/video/giByuMBUSl0/видео.html ruclips.net/video/RljSGJHvt3A/видео.html
Moment distribution method from basics ruclips.net/video/rI9qaseL1rs/видео.html ruclips.net/video/giByuMBUSl0/видео.html ruclips.net/video/RljSGJHvt3A/видео.html
Because the members are assumed to be axial rigid and the way it is supported, there will be no sway, ie, point B will have zero horizontal displacement. In fact the displacement of point B will be 0.
Moment distribution method from basics ruclips.net/video/rI9qaseL1rs/видео.html ruclips.net/video/giByuMBUSl0/видео.html ruclips.net/video/RljSGJHvt3A/видео.html
Distribution factor for BC , here C is hinged support so stiffness must be 3I / L . Youbused 4I/ L
Moment distribution method from basics
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God bless you sir ...
Far end hinged stiffness factor should be 3I/4L.sir
Yes bro..you are correct..at hinged support stiffness K = 3/4 I/L...then all values need to be corrected
If you do that then the carry over factor will also need to be adjusted according to fixed - pinned beam. What you are saying and this method, both give same final result.
@@srinurao3327 If you do that then the carry over factor will also need to be adjusted according to fixed - pinned beam. What you are saying and this method, both give same final result.
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Hello!
A small confusion concerning distribution factor for member B-C. The stiffness factor for BC should be multiplied by 3/4 as the support at C is pinned. Correct me if am wrong please.
Thank you.
If you do that then the carry over factor will also need to be adjusted according to fixed - pinned beam. Both methods give same final result.
@@pankajkporwal Yes!
Okay great. Good to know that. Thank you 👍
Dear sir I did the same example with both methods are almost same values..thank you sir
@@pankajkporwal I can’t understand this. Plz explain
Sir one thing is confusing a little why we are using different stiffness factors K for beam and frames...??
What are there different formulas please answer..
11:44 sir i thought we cant transfer the moments in BC to CB can the ends of C is hinged and we cant have moments at end when its hinged
Sir member BC distribution carry over moment zero to c .bcoz there is hinged support
Moment distribution method from basics
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How do you know how many times to carry over and times by the distribution factor?
Moment distribution method from basics
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why sway is not calculated for this frame sir.
Because the members are assumed to be axial rigid and the way it is supported, there will be no sway, ie, point B will have zero horizontal displacement. In fact the displacement of point B will be 0.
Shouldn't C have 0 moment due to it being a pinned connection?
Moment distribution method from basics
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Sir support c is not fixed.....it is a hinged support......
Yes. That's why k_c,wall = 0. At fixed support k_wall = infinity.
@@pankajkporwal but can we take fixed end equation at C ( hinged support ) wLXL/12 imaging both are fix