Moment Distribution Method for Sway Frames | Portal frames

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  • Опубликовано: 22 дек 2024

Комментарии • 116

  • @souvik.fingtore
    @souvik.fingtore Год назад +5

    The word" teacher" meaning define by ur teaching style and explanation
    & thanks fram JADAVPUR UNIVERSITY.....😍

  • @mikexbox1
    @mikexbox1 4 года назад +20

    Am i the only one who enjoyed the birds? Great video, thank you

  • @mayuriassai7424
    @mayuriassai7424 5 лет назад +8

    This must be the most beautiful video that I've ever seen..... Beautifully presented.... 10/10 for this. Lots of love

  • @sahilrooplall2970
    @sahilrooplall2970 3 года назад +3

    You made this topic very easy to understand. Thank you very much.

  • @souvik.fingtore
    @souvik.fingtore Год назад +1

    Thanks a lot for creating such a helpful video. U r doing great for students, keep going.

  • @Comedyvideos-e2q
    @Comedyvideos-e2q 6 лет назад +3

    Crystal clear explanation...sir

  • @anjangaire6262
    @anjangaire6262 Год назад

    Bohot badhiya explained🧨🧨💥💥

  • @indiramishra7013
    @indiramishra7013 3 года назад

    Thanks for all these "gyan ke moti" !!!

  • @emmyemtiyax8224
    @emmyemtiyax8224 6 лет назад +2

    It was fully clear satisfaction for me
    Nyc work sir
    How can i thanks u sir

    • @DCBAonline
      @DCBAonline  6 лет назад

      Your kind words are more than enough to thank me.

  • @saninduteshan3656
    @saninduteshan3656 3 года назад

    great explain sir. I got it on my first watch.

  • @mthokozisimthembu7982
    @mthokozisimthembu7982 6 лет назад

    Thank you sir. Nice explanation. I'm busy with exam preparations, it helped me a lot thankyou

  • @hariomchandra9048
    @hariomchandra9048 4 года назад +4

    I think it is stiffness 4EI/L,not the relative stiffness because it isl/L

  • @annamalaisuresh5997
    @annamalaisuresh5997 5 лет назад +1

    Thank you bro, you made it simpler

  • @sreenithya6383
    @sreenithya6383 4 года назад +3

    Sir, What about the 16kN load acting at B, it's not included in the first step(while calculating fixed end moments in non-sway analysis) calculations

    • @DCBAonline
      @DCBAonline  4 года назад +4

      That load will not contribute in fixed end moments as it is at the end of the beam.

  • @mbalimadonsela8305
    @mbalimadonsela8305 4 года назад

    loved the video. omw it made things so much clearer

  • @RR_official-wt8qx
    @RR_official-wt8qx 3 года назад

    Thank you so much sir.... These video is helpfu for many students.

  • @srinurao3327
    @srinurao3327 3 года назад +1

    what about joint load 16KN at joint B..you didnt consider load 16KN at calculations of fixed end moments and at calculation of moment distribution..what is the concept of joint load? will it ignore? pls clarify

  • @allarjun956
    @allarjun956 6 лет назад +1

    sir why H1*5 moment positive at 12:10

    • @DCBAonline
      @DCBAonline  6 лет назад

      Ap subliminals it is because H1 is causing a sagging moment.

    • @mayuriassai7424
      @mayuriassai7424 5 лет назад

      mind nut because it's clockwise w.r.t B

  • @marthinusdekock7089
    @marthinusdekock7089 5 лет назад +1

    Thank you for the tutorial, brilliant

  • @naraharimanne5240
    @naraharimanne5240 4 года назад +1

    excellent explanation sir

  • @dr.j.thivya6916
    @dr.j.thivya6916 5 лет назад +1

    how can you assume H1 and H2 force directions

    • @DCBAonline
      @DCBAonline  5 лет назад

      you can assume any direction but generally just see logically in which direction the frame will deflect and then draw H1 H2 forces as reactions.

  • @kzero9714
    @kzero9714 3 года назад

    Any example for frame with bracing?

  • @subinas7333
    @subinas7333 4 года назад

    What is the delta value substituted

  • @constanzagil9712
    @constanzagil9712 3 года назад

    Thanks mate, very helpful!

  • @subinas7333
    @subinas7333 4 года назад

    Well explained.. Loved your video

  • @GAMMASTAR321
    @GAMMASTAR321 3 года назад

    hey can i know why the horizontal 16Kn force was not included in the FEM calculations in the beginning?

    • @DCBAonline
      @DCBAonline  3 года назад +1

      Because its not acting on any member. Its acting on rigid joint

  • @ritamdas_ju
    @ritamdas_ju Год назад

    Sir... what would be the number of no. of iteration? Is there any criteria?

    • @DCBAonline
      @DCBAonline  Год назад

      Generally 5 iteration should yield a fairly accurate answer

  • @naveen6893
    @naveen6893 Год назад

    Sir here both P, Q force direction was same. What to do if directions are different? Should we take the ratio as negative?

  • @discovernepal779
    @discovernepal779 3 года назад

    Tq for this knowledge video.what to do for the joint that constant 3 member.make video on this

  • @fasdffd4771
    @fasdffd4771 5 лет назад

    Hi there. Can I ask you how to solve an indeterminate frame whose legs are not equal and have a support hinge. Thanksss. Any Idea could help me thanksss

  • @raysaha1893
    @raysaha1893 3 года назад

    Sir thanks a lot.... Helped me in my test💜

  • @llendymanulat2659
    @llendymanulat2659 5 лет назад +1

    THANK YOU SO MUCH. GOD BLESS YOU PO

  • @ayushvishwkarma1876
    @ayushvishwkarma1876 2 года назад

    Brilliant step by step description....🫡

  • @Sully...
    @Sully... 6 лет назад

    Do we have to release if the end supports are simply supported in case of a beam?

    • @DCBAonline
      @DCBAonline  6 лет назад

      Ashton Benjamin yes if ends are pinned than you need to release the moments.

  • @PS-te7qc
    @PS-te7qc 4 года назад

    Sir,Would there be deflection at A due to sway force if end A was hinged?

    • @DCBAonline
      @DCBAonline  4 года назад

      If A is a type of support especially fixed or hinged then there is no possibility of translational deflection at that point.

  • @PS-te7qc
    @PS-te7qc 4 года назад +1

    Sir why is relative stifness 4EI/L & not EI/L as in your other videos of beams. I think 4EI/L is the formula for stifness & not relative stifness. Please reply

    • @DCBAonline
      @DCBAonline  4 года назад +6

      Actually you can take either 4EI/L when far end fixed and 3EI/L when far end hinged or you can take EI/L when far end fixed and 3EI/4L when far end hinged it will give you same answer.

    • @PS-te7qc
      @PS-te7qc 4 года назад

      @@DCBAonline thank you sir

  • @Mighty3000
    @Mighty3000 4 года назад

    can you do the same question in Kani's method, please??????

  • @raviraj7383
    @raviraj7383 Год назад

    amazing 😍😍😍😍😍😍😍

  • @ahmedhyd867
    @ahmedhyd867 6 лет назад +1

    Thanks friend, the way you explain everything in detail is very nice, it is very helpful . Kindly solve the same frame but with hinge/pin support at both ends by KANI's method
    *****I have solved the same problem by KANI's method and the result matches to your moment distribution method....Thanks again for this sway frame MDM

  • @subakaranr.9252
    @subakaranr.9252 5 лет назад

    hy I have a doubt, all the end joints are considered to be fixed, only in portal frame or in any situations like, if we consider a simple horizontal beam????

    • @raviakash2955
      @raviakash2955 4 года назад

      The intermediate joint are considered to be fixed for all the cases(for the horizontal beam as well)

  • @sremix2818
    @sremix2818 2 года назад

    What will be the sign of P/Q? + or -?

  • @dusaripraneethbabu7202
    @dusaripraneethbabu7202 2 года назад

    Thank you sir understood perfectly 👍

  • @shutterbeat5426
    @shutterbeat5426 5 лет назад

    Nice Explanation 👌

  • @madhavreddy3489
    @madhavreddy3489 6 лет назад +1

    well done bro... thankyou so much .. kindly do SWAY ANALYSIS for SLOPE DEFLECTION METHOD and also KANI'S METHOD

  • @C_O_LAIS
    @C_O_LAIS Год назад

    if you arbitrarily substitute "EI delta" Value, then everyone will get a different final answer right?

  • @yuvrajkumar6792
    @yuvrajkumar6792 6 лет назад +1

    Awesome sir g, but where is next lecture

  • @vishalchaudhari4866
    @vishalchaudhari4866 5 лет назад

    Sir -9.13 h toh voh anticlockwise hoga na?

    • @baishya775
      @baishya775 5 лет назад

      Yes thankgod.. That doubt was eating my head. It should be anti clockwise

    • @vivek9763
      @vivek9763 3 года назад

      I guess he assumed the directions of moment and mentioned them with +/- sign. You see he took all moments as clockwise with +/- sign

    • @DCBAonline
      @DCBAonline  3 года назад +1

      You can either show the moment with the correct direction and a positive value ot you can show the moment with negative value and its incorrect direction. The thing here is i have shown all moments to be clockwise but i have written their values correct with the signs

  • @suravarapuharika5214
    @suravarapuharika5214 4 года назад

    You have found fixed end momend for MfAB as 9.6 but in the free body diagram you wrote 9.13 how is that possible

    • @DCBAonline
      @DCBAonline  4 года назад

      Because you have to use non sway moments for that and not fixed end moment

  • @venkatkrishna7943
    @venkatkrishna7943 6 лет назад

    What was the software you used ??

  • @dipendrakumardas5939
    @dipendrakumardas5939 6 лет назад

    Thank u so much..really.. It's been very helpful to me..😜😜

  • @pramodredekar736
    @pramodredekar736 5 лет назад

    Explanation is very good. But how you can decided the moments direction. On which basis. Plz rply me sir.

    • @jbator10
      @jbator10 5 лет назад

      seems clockwise is negative

  • @monir111monir
    @monir111monir Год назад

    Great video

  • @misszas1396
    @misszas1396 2 года назад

    Sir there is a a sign convention mistake in your drawing you have mixed clock wise and anticlockwise moment directions ,thus it creates confusion.

  • @devgupta1217
    @devgupta1217 3 года назад +1

    Formula for correction factor(x) is P+Qx =0

  • @ADITYARAJ-gl9ox
    @ADITYARAJ-gl9ox 4 года назад

    Very good video ❤️

  • @faizankamal6844
    @faizankamal6844 4 года назад

    Sir I need your help.
    Can you please tell me how to solve a frame having 2 or more storey and 2 or more bays by MDM?
    PLEASE SIR, I have been trying to look for it for many days but I haven’t found it yet.
    Please make a video on it or at least tell me the procedure to solve it.
    PLEASE DO ANSWER SIR PLEASE

    • @DCBAonline
      @DCBAonline  4 года назад +1

      It is a little bit difficult and lengthy process, the procedure although remains same finding distribution factors and other, i will try to make video but its difficult to get time these days out of other commitments of videos.

    • @faizankamal6844
      @faizankamal6844 4 года назад

      DCBA online Please do make it whenever you get free time sir. I’m pretty sure it will be very helpful to many students and we will also get a clear picture of using this method on real life structures which usually have more storeys and bays.

  • @sagarmaniraut7490
    @sagarmaniraut7490 5 лет назад

    Clear explanation

  • @chandanrajjoshi6257
    @chandanrajjoshi6257 5 лет назад

    Relative stiffness for fixed end is EI/L and you have used 4EI/L while calculating...

    • @ashmakarki1426
      @ashmakarki1426 5 лет назад

      no 4ei/l is correct

    • @chandanrajjoshi6257
      @chandanrajjoshi6257 5 лет назад

      @@ashmakarki1426 but how

    • @chandanrajjoshi6257
      @chandanrajjoshi6257 5 лет назад

      There should be EI/l and the value of I=4l then It is 4EI/L but not 16EI/L

    • @joetube6208
      @joetube6208 5 лет назад

      That is method for fixetion= 4EI/l
      And for fixed hinge =3Ei/L
      As const in this method

  • @UserNameEuouae
    @UserNameEuouae Год назад

    Why is it that the sidesway moment became clockwise in 21:37 when it is supposed to be counterclockwise just like in 14:33. Illuminate my minddd huhuhu

    • @DCBAonline
      @DCBAonline  Год назад

      It is shown considering the sign conventions

  • @munawarhussain7878
    @munawarhussain7878 4 года назад

    awesome broh

  • @knowledge-er2et
    @knowledge-er2et Год назад

    Thanks a lot sir

  • @raviakash2955
    @raviakash2955 4 года назад

    Bro I have a doubt...for continuous beam you said that the relative stiffness is EI/L but now you are saying that relative stiffness is 4EI/L(for fixed far end)why???

    • @DCBAonline
      @DCBAonline  4 года назад +1

      See you can use either of these formulas
      1) far end hinged =3EI/4L
      2) far end fixed = EI/L
      OR
      1) Far end hinged =3EI/L
      2) Far end fixed = 4EI/L
      both set of formulas are correct in the first set 4 is take common.

    • @raviakash2955
      @raviakash2955 4 года назад

      @@DCBAonline thanks bro...got it

  • @fazelally1049
    @fazelally1049 6 лет назад

    can you solve a question where there is a arch resting on columns using a compatibility method

  • @JM-lw1dr
    @JM-lw1dr 4 года назад

    why is 4EI/L = (4E * 4I)/L?

    • @DCBAonline
      @DCBAonline  4 года назад +1

      Because moment of inertia of that section was 4I

    • @JM-lw1dr
      @JM-lw1dr 4 года назад

      @@DCBAonline yeah i noticed it a couple of hours after thanks man!

  • @sharadmanikpuri8016
    @sharadmanikpuri8016 6 лет назад

    thank you so much Sir

  • @sailendranathpal8
    @sailendranathpal8 Год назад +1

    😊❤

  • @tejaswinipatil4799
    @tejaswinipatil4799 6 лет назад

    Thank u so much sir....

  • @sajasy3563
    @sajasy3563 6 лет назад

    thanks very much

  • @gowrisankararao8827
    @gowrisankararao8827 3 года назад

    GOOD VIDEO

  • @Alma127
    @Alma127 5 лет назад

    Thank you very mucy

  • @kalyanvenkatesh1431
    @kalyanvenkatesh1431 3 года назад

    MFAB was -ve and MFBA was +ve in Non sway analysis. But you took both of them in the same direction. Please look.

    • @TanveshDabholkar
      @TanveshDabholkar 3 года назад

      Although directions are shown same, but the values are written with signs in consideration.

    • @kalyanvenkatesh1431
      @kalyanvenkatesh1431 3 года назад

      @@TanveshDabholkar Oops, sorry, I didn't see the minus. Yes you are correct.
      Thank you 👍🏻🙏🏻

  • @roham1981
    @roham1981 5 лет назад

    Thanks alot

  • @dr.j.thivya6916
    @dr.j.thivya6916 5 лет назад

    thank u

  • @ImranKhan-qs6st
    @ImranKhan-qs6st 5 лет назад

    Sir MDm method m overhang frame ka analysis ap ny n kea.plzzzzzzzz sir do it

  • @BejjankiGaneshChary
    @BejjankiGaneshChary 3 года назад

    Tq

  • @energeniq-sahilpatra7401
    @energeniq-sahilpatra7401 3 года назад

    Tnx

  • @Sully...
    @Sully... 6 лет назад

    Please reply asap as I have exams tomorrow.

  • @biswaranjanpradhan6248
    @biswaranjanpradhan6248 4 года назад

    Q force ka direction to galat liye ho.... Its is towards left... Because h1, h2 both are towards left

  • @ashokchoudhary4805
    @ashokchoudhary4805 5 лет назад

    Are method ko pura complicated bana diya yarr

  • @amnakulsoom7214
    @amnakulsoom7214 3 года назад

    Have you gone maddddd??? I though id learn something but you dont know basic math, I m stopping at 2.59, like seriously 4EI =4E .4I like seriously what is this ... Its multiplication not addition or subtraction.

    • @DCBAonline
      @DCBAonline  3 года назад

      Woman are you idiot? Do you understand what 'I' stands for in 4EI/L, its moment of inertia of the cross section and that particular cross section is having 4 times moment of inertia as compared to a section having MOI of 'I'. So its perfectly correct numerical, go and check it with any software and before commenting mind your tongue. Think for a moment understand engineering and then comment.