Lineweaver Burk plot data analysis

using a Lineweaver Burk plot to analyse enzyme data
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[@SuperZwiebertje]

Finally a professor that takes time in teaching you the whole thing instead of expecting that you already know 80% of it.

[@jameshigdon100]

This went from "we can find these numbers" to a solved problem.

[@amandar3299]

I was SO confused about this - you are a life saver! :)

[@CLEANDrumCovers]

Thank you, David Attenborough.

[@makhzania]

Thank you very much for the explanation, I have found it extremely helpful in my biochemistry lab work. You explain things clearly and in simple terms which many lecturers can't see to manage. Either that or as others have noted here, they seem to assume you know most of it already!

[@issie339]

Thank you so much! I wish you were my professor! So very helpful and easy to understand. Please keep making these videos, I learn more from you, than from my lectures and books.

[@magictrees101]

Use a computer software. Alot easier these days to get the values 😁 I love how you explained this fully! 💯

[@Wandelaarke]

Finally a professor that manages to explain this perfectly!

[@jonahtristian5729]

i dont mean to be offtopic but does anyone know a tool to log back into an instagram account??
I was stupid lost the password. I appreciate any help you can give me

[@owenduncan760]

@Jonah Tristian instablaster =)

[@jonahtristian5729]

@Owen Duncan i really appreciate your reply. I got to the site on google and im in the hacking process atm.
Looks like it's gonna take quite some time so I will get back to you later when my account password hopefully is recovered.

[@jonahtristian5729]

@Owen Duncan It worked and I now got access to my account again. I'm so happy!
Thank you so much you really help me out :D

[@owenduncan760]

@Jonah Tristian happy to help =)

[@rarasrizkialviani8379]

Hello, I'm from Indonesia, i'm biology collage student, i want to say thank you so much because this video helpfully.

[@davidrenteria9585]

This is gold. Thank GOD 🙏
And thank you teacher.

[@srikantadash4603]

U r just a life saver for me.... Thank you ❤😘

[@premiumedjr]

Very helpful tutorial! What say about Dixon's plot in determination of inhibition constants? It will be better appropriate than lineweaver-burk, once it take in to consideration just the inverse of velocity, while lineweaver utilizes both the inverse of velocity as the inverse of substrate concentration? Thank you!

[@xanaanak55]

That was so unbelievably helpful. Thankyou so much. Please keep making more videos!

[@ABDULGTV]

Thank you.

[@Merhawit10]

I'm still a bit confused on how Km and Vmax were calculated?

[@lukechess7477]

Reading off the Graph 1/Vmax= 0.016. This is the reciprocal, to reverse it you 1/ 1/Vmax (1/ 0.016 = 62.5) So Vmax= 62.5. You do the same for 1/ Km (1/ 0.07 = 14.3). Once you have Vmax and Km you can work out the Gradient (14.3/ 62.5 = 0.23). Again you Reverse this giving (1/ 0.23 = 4.3)

[@Boomerangpie]

THANK YOU!! this was SO helpful - a topic that has confused me for weeks :-)

[@EdisonvsTesla]

Thanks so much, may God protect 🙏 long live

[@chocolatepoodle6028]

Thank you! This really helped me in writing my biochem report. :-)

[@robynbryant2800]

Love it, thank you so much for being so helpful!!

[@sofieStormen]

you saved my life :) thanks for so many details and the good explanetions :)

[@KimHjalmarsson]

This was helpful - I don't understand some of the basics still though.. Wasn't Km supposed to be half of Vmax simply? How can it be a totally different number than Vmax in the Lineweaver-Burk-plot?

[@tsmanchester]

How did the gradient all of a sudden come up how does one work out where the gradient goes

[@Brisbane09]

there's one thing I don't get. Our teacher told us that Km has a unit mmol/l. But the reciproke of mmol/l would be 1/mmol/l = l*mmol^-1 wouldn't it?

[@frannnnn]

GRANDE VIEJOO SOS UN GROSO ...

[@SUNNI3DAY]

Very helpful! Saved my lab write up.

[@GHOST3940136]

nice videos Peter, thx, that cleared some things up.

[@1705ika]

thaaankk youuu so much Peter Kappa, you really help me, you safe my life :')

[@kathxlin]

Thanks so much!!! This really helps heaps, Dr Klappa. Cheers! =)

[@apvert]

Extremely helpful, thanks!

[@dunyalaftamohammedkufa6908]

What about ki of non competitive inhibitors

[@sweetestseed]

Thank youuuuuu you're a life saver! God bless you

[@Nadasistschoen]

Thank you very much, this was incredibly useful!!!!

[@asumangulsumkaya2887]

still I couldn't understand where Vmax come from? He said that it is 0,016 from graph but later he says it is 62,5??? Btw thank you for this enlightening video

[@SuperYersinia]

1/0,016 = 62,5

[@alvaro811994]

thanks a lot...it really helped me..keep it up!!!

[@ssoblasted]

thank you, this really helped my lap report.

[@maevecahalan1938]

Excellent!!!!!!!

[@jmse7en77]

Thank you, it was very helpful!

[@getfiasco]

i get how you work vmax but how do you work out km :s

[@dbwun]

Great video, thanks!

[@حوراءحيدر-م2ذ]

Thank you so much

[@MrFilu13]

thank u , it is very helpful

[@88abuk]

thnx very much
really helpfull

[@tajikamman]

very helpful thanks so much! :-)

[@039stephen]

40:41 jack, its called sleet

[@BioScienceClass]

For more videos on Enzyme Kinetics:ruclips.net/video/wAWYIGTRXQE/видео.html

[@gbabiebiperemene495]

Youtu.bewAWYIGTRXQE

[@gamzeyazgeldi6925]

Thanks!!

[@getfiasco]

oh i get it now. very helpful :)

[@andienlovehanif]

LIKE THIS BANGETLAH CC: NIDA MAHDA ANIDA AHLI PERHITUNGAN DI SETIAP LAPORAN

[@misschocolate383]

thank you sir

[@rajkishore5334]

nice talk..

[@EddyKackboon]

very cool =)

[@adrianculasing1279]

Bruh thank you.

[@poppyflower333]

Thanks,

[@ryanj1304]

@9Dan22
62= vmax
14= km
calculated from 1/0.016 and 1/0.07 :)