Today, I'll be describing how to trim a distribution so that the outliers don't affect the mean as much. If you want to support me, feel free to donate here: paypal.me/olgaandreeva1 :)
If (17.5×n) is not an integer. It can be calculated by weighted average of X% trimmed mean(which is just less than 17.5% and X%×n is a integer) and some Y% trimmed mean (which is just more than 17.5% and Y% × n is a integer) n =no of observations.
thank you!!! your explanation helped a lot!!
Thanks a lot. That really helped
Thank you sooo much 💕💕💕 you made my day
Thankyou it was really helpful
Thank you for the help, you simplified statistics for an old Fart!
Thanks!
Thankyou!!!
THANKS!!!!!!!
but what is the mathmatical law, i have meant like (a+b)^2 type law
What to do if 15% trimmed mean given?
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how did you get 34.066?
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how deice the trimmed mean value? is it given in the question ?
The trimmed mean is the sum of all of the numbers that are given divided by how many numbers there are => 1004 / 25 = 40.16.
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[ banana + concise + cute + articulate + apple ] --> find the 20% trimmed mean. Hint: It's an upvote.
What if they ask 17.5 % trimmed mean?
If (17.5×n) is not an integer.
It can be calculated by weighted average of X% trimmed mean(which is just less than 17.5% and X%×n is a integer) and some Y% trimmed mean (which is just more than 17.5% and Y% × n is a integer)
n =no of observations.
thank you!!!...It was really helpful..