Vector Equations of Spheres (2 of 2: Circle of intersection)

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  • Опубликовано: 28 окт 2024

Комментарии • 9

  • @沈博智-x5y
    @沈博智-x5y 3 года назад +3

    instead of comparing similar triangles, i compared areas.
    Area of that triangle made with radii 3 & 4 is 0.5(3)(4) = 6
    From another angle, it's 0.5(5)h = 6 (making 5 the base, the line segment joining the two centres)
    h = 12/5 (this is the radius of the circle of intersection)
    Use pythagoras to find the "scalar projection" length
    z = sqrt(3^2 - (12/5)^2) = sqrt(81/25)
    therefore z = 9/5
    equation of circle of intersection on the plane z = 9/5 is
    x^2 + y^2 = 144/25 (and z = 9/5)
    so radius of cicle of intersection is 12/5
    centre at (0, 0, 9/5)

    • @ashish4k07
      @ashish4k07 3 года назад

      yeah its an easy method

  • @mathsandsciencechannel
    @mathsandsciencechannel 3 года назад +2

    Great video sir... ♥️♥️♥️

  • @aashsyed1277
    @aashsyed1277 3 года назад +2

    9:29 when a proffeser becomes a *master* at math.

  • @CMtutorials313maths
    @CMtutorials313maths 3 года назад

    Ratio of two numbers is 3 : 4
    And their HCF = 4
    What is the LCM= ?
    #hshmaths313

  • @aashsyed1277
    @aashsyed1277 3 года назад +2

    let me guess the future.......tomorrow he will be uploading a integration video i promise.

  • @thejojoshow9238
    @thejojoshow9238 3 года назад +1

    😘😘😘😘💛💛💛🥕🥕🥕
    Thank you.

  • @CMtutorials313maths
    @CMtutorials313maths 3 года назад +1

    5-2+6÷3 = ?
    If your answer is 1 or 3 then you are Wrong
    #hshmaths313