hi could you please help to solve this question? When f(x) is divided by x - 1 and x + 2, the remainders are 4 and -2 respectively. Hence, find the remainder when f(x) is divided by x^2 + x - 2.
(x-1)(x+2) = x^2+x-2 f(x) / x - 1 = Q1(x) + 4/x -1 (Q1(x) + 4/x-1) / x+2 = Q2(x) + (4 / x^2+x-2) - (2 / x+2) = Q2(x) + (4 / x^2+x-2) - (2x-2 / x^2+x-2) = Q2(x) - (2x+6 / x^2+x-2) I don't know if this is right, I never learned how to do this type of problem.
EDWARD JOHNWOOD Times two for the whole equation (-p+q=6) which result (-2p+2q=12). This new equation is needed in order to perform elimination method in simultaneous to find value of p
pls help me solve this ques. when f(x):(p-1)x cube +px square+qx+r is divided by (x-1),(x+1)and(x+2) , the remainders are 4,0,5 respectively ;find the values of p,q and r
could you do on e with a fraction eg 3x-2 please.
hi could you please help to solve this question?
When f(x) is divided by x - 1 and x + 2, the remainders are 4 and -2 respectively. Hence, find the remainder when f(x) is divided by x^2 + x - 2.
(x-1)(x+2) = x^2+x-2
f(x) / x - 1 = Q1(x) + 4/x -1
(Q1(x) + 4/x-1) / x+2 = Q2(x) + (4 / x^2+x-2) - (2 / x+2)
= Q2(x) + (4 / x^2+x-2) - (2x-2 / x^2+x-2)
= Q2(x) - (2x+6 / x^2+x-2)
I don't know if this is right, I never learned how to do this type of problem.
how did you get equation no. 3 . please help i don't know
EDWARD JOHNWOOD Times two for the whole equation (-p+q=6) which result (-2p+2q=12). This new equation is needed in order to perform elimination method in simultaneous to find value of p
thanks
pls help me solve this ques.
when f(x):(p-1)x cube +px square+qx+r is divided by (x-1),(x+1)and(x+2) , the remainders are 4,0,5 respectively ;find the
values of p,q and r
Thank you for this sir it's helps
thanks for teaching me :D