2^2 when Brought one level down 4 and vice versa 2^16386= 2^16384*2^2 =2^16386. Since multiplication is repeated addition. Actually you should use Prime Factors
That's because we are missing parentheses in these equations. (2^2)^16 is not 2^(2^16). You are treating the equation as ((x^x)^x)^3 but it's x^(x^(x^3))
"So far so good?" you ask. NO! You really need to preedit these before putting on line. Way too many misleading points that should easily be eliminated. Would you have the patience if a student pulled this stuff... for a prepared problem no less?
Thanks...
Please put more of these kinds of questions...🙏🙏🙏.
I love them alot...🤩🤩🤩.
Sure
@@SyberMath thank you so much...🤝🤝🤝.
Fun and instructive. Thank you.
My pleasure!
2^2 when Brought one level down 4 and vice versa 2^16386= 2^16384*2^2 =2^16386. Since multiplication is repeated addition. Actually you should use Prime Factors
The ERROR IS THAT YOU HAVE MULTIPLIED THE RHS BY 2 WITHOUT DIVIDING ON LHS.
x=16
I think 2173....will chk later🎉
16 exp16 exp16 exp3 (=2 exp3072) is not equal to 2 exp2 exp16386 (=2 exp32772).
That's because we are missing parentheses in these equations. (2^2)^16 is not 2^(2^16). You are treating the equation as ((x^x)^x)^3 but it's x^(x^(x^3))
Thanks for your time.
good job 👏
Thanks 😁
Fantastic!
🇧🇷🇧🇷🇧🇷🇧🇷🇧🇷🇧🇷🇧🇷
Nice
Sorry 2173*2 😮 ie 4346
hk bus 16 kwun tong lam tin to mongkok pak king wan
The number is so myriad, it's difficult to verify on calculator
😁🤪
X=16 is not a solution.
It sure looks like it is.
No, 16 is indeed the solution.
Step 1: Remove the outermost "2^" at the RHS using a substitution
Let x = 2^n
(2^n)^{(2^n)^[(2^n)^3]} = 2^(2¹⁶³⁸⁶)
Known: (a^b)^c = a^(bc)
(2^n)^{(2^n)^[2^(3n)]} = 2^(2¹⁶³⁸⁶)
(2^n)^[2^(n · 2^(3n))] = 2^(2¹⁶³⁸⁶)
2^(n · 2^(n · 2^(3n))) = 2^(2¹⁶³⁸⁶)
n · 2^(n · 2^(3n)) = 2^(16386)
Step 2: Repeat Step 1 using a similar substitution
Let n = 2^t
2^(t + 2^t · 2^(3 · 2^t)) = 2^(16386)
t + 2^(t + 3 · 2^t) = 16386
t + 2^(t + 3 · 2^t) = 2¹⁴ + 2
Assume t = 2 and t + 3 · 2^t = 14.
Since 2 + 3 · 2² = 14, t = 2
-> n = 2² = 4
-> x = 2⁴ = 16
Wow! 😍
Please explain yourself instead of making statements
Thanks for your time.
"So far so good?" you ask. NO! You really need to preedit these before putting on line. Way too many misleading points that should easily be eliminated. Would you have the patience if a student pulled this stuff... for a prepared problem no less?
My thoughts exactly. You owe your viewers the courtesy of a properly edited video.
x^x^x^3
The prime factors of 16386 are 3*2*2173
RHS can bbe simplified as :
LHS 2 ,2173,2,3