Archimedes’ Principle || Buoyancy kya hoti hai || Gear Institute
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Archimedes' principle states: An object immersed in a fluid experiences a buoyant force that is equal in magnitude to the force of gravity on the displaced fluid.
Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.[1] Archimedes' principle is a law of physics fundamental to fluid mechanics. It was formulated by Archimedes of Syracuse
Any object, totally or partially immersed in a fluid or liquid, is buoyed up by a force equal to the weight of the fluid displaced by the object.
Archimedes' principle allows the buoyancy of any floating object partially or fully immersed in a fluid to be calculated. The downward force on the object is simply its weight. The upward, or buoyant, force on the object is that stated by Archimedes' principle, above. Thus, the net force on the object is the difference between the magnitudes of the buoyant force and its weight. If this net force is positive, the object rises; if negative, the object sinks; and if zero, the object is neutrally buoyant-that is, it remains in place without either rising or sinking. In simple words, Archimedes' principle states that, when a body is partially or completely immersed in a fluid, it experiences an apparent loss in weight that is equal to the weight of the fluid displaced by the immersed part of the body(s).
Consider a cuboid immersed in a fluid, with one (hence two: top and bottom) of its sides orthogonal to the direction of gravity (assumed constant across the cube's stretch). The fluid will exert a normal force on each face, but only the normal forces on top and bottom will contribute to buoyancy. The pressure difference between the bottom and the top face is directly proportional to the height (difference in depth of submersion). Multiplying the pressure difference by the area of a face gives a net force on the cuboid - the buoyancy, equaling in size the weight of the fluid displaced by the cuboid. By summing up sufficiently many arbitrarily small cuboids this reasoning may be extended to irregular shapes, and so, whatever the shape of the submerged body, the buoyant force is equal to the weight of the displaced fluid.
{\displaystyle {\text{ weight of displaced fluid}}={\text{weight of object in vacuum}}-{\text{weight of object in fluid}}\,}{\displaystyle {\text{ weight of displaced fluid}}={\text{weight of object in vacuum}}-{\text{weight of object in fluid}}\,}
The weight of the displaced fluid is directly proportional to the volume of the displaced fluid (if the surrounding fluid is of uniform density). The weight of the object in the fluid is reduced, because of the force acting on it, which is called upthrust. In simple terms, the principle states that the buoyant force (Fb) on an object is equal to the weight of the fluid displaced by the object, or the density (ρ) of the fluid multiplied by the submerged volume (V) times the gravity (g)[1][3]
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Sir I have selected in maruti suzuki thanks for your support and guidance I want to share my journey and experience if you allow
Congratulations
I will msg you if i need this
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Hello, I want talk to you about Maruti Suzuki, please send me instagram id
@@SantoshSingh-bz9mgलगता है सर से ही पैसे उधर मांग के खरीदे हैं
Concept bhaut acha hai
Esa hi hydraulics ka or concept dalte rhe sir
Wonderfully explained! 🔥 Thank you so much sir for your extended efforts you putted on to explain it more implementative manner.
Understood sir
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Sir aap best teacher ho
You are great sir
Understand sir😃
Hello sir iam from Nepal
You teach in a very easy way..
Sir gravity kese nikalte h
Thank you❤❤
Welcome and keep watching
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Nice one
Beyonce
why a plastic round (sphere shape ) cricket ball float whereas same shape marble sink, even marble displace more volume of fluid
Due to density
If ball has density higher than water density then sink
If ball has density lower than water density then float
Samaj aaya sir
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