I love the way you explain the concepts Venugopal sir. Thank you gate academy for this initiative to create a video archive focusing engineering exams. 😊
Sir Mai gate academy plus ka abhari hu ki Ki ghr baithe itni. Achhi concept mil rhi hi This is humble request to Umesh sir Please provide industrial engineering lecture from basics
sir you are best as I am in second sem but i started this subject and i dont know a single thing about this sunject but i understand it all you r best great teaching
Sir in the last numerical of this leacture the steel submerged between the interface of hg and water, why the force due to buoyancy is not providing a downward force by the water on the surface of steel block?
Watch the lecture carefully. Sir already mentioned in the beginning of the lecture “Net Vertical Component”. Also you can see in the derivation why upward force is taken.
SIR , in the first case when B is below G , the moment due to the weight and buoyant force are in clockwise direction same as the external moment. But if we take the external moment in anti clockwise direction then even if B is below G the body will resist the external moment and we should get stable equilibrium.
Bro you can draw diagram by your own for both condition, you can see that if external force is anti clockwise the moment due to weight and buoyant force will also get in anti clockwise direction , so it will be unstable equilibrium (if B is below G) either your external force is anti clockwise or clockwise
@@rohitjamdagni9926yes absolutely perhaps the boy above didn’t verify it through diagram. You are absolutely correct that if we take the external moment in anticlockwise direction then the moment generated by the G and B will also be in anticlockwise. As a result of which an unstable equilibrium condition occurs.
Your way... Of explaining the things... Is so good..... And in this tutorial , in some cases the spelling of buoyancy was not right.... Please make more videos on numericals also....
Hello sir, hope u r doing well At 26:31 In the last problem, you added the buoyant forces(Fb1+Fb2=W). My question is, the body is has water above it putting pressure downwards. Then how can the forces be unlike force(The water is not putting any upwards force). Or am I wrong here?
Sir, what if the total buoyant force is higher than weight force...because due that we cant get the perfect ratio , we can get the ration in form of less than or greater than form...
Sir If we apply a moment in anticlockwise direction. The case becomes opposite of that you have explained. Please explain if I have understood something wrongly.
Sorry to interrupt you sir But as per my knowledge in submerged case postion of centre of buoyancy never changes . we change the centre of gravity of the material so please clear it and reply me if i am wrong 🙏🏻 Thanx alot sir
Why we are considering clock wise moment / displacement while defining the stability of body ?..if we take anti clock wise B below G condition will become Stable
If you will take anticlockwise then also the net force acting on the line if action will be in produce couple in same direction of the disturbing couple
sir, why u take external clockwise moment while proving the stability and instability of the submerged body if we take external anticlockwise direction the results will be different
Hello sir, please explain the concept behind this problem: A wooden log (S.G=0.7) has a cross-section of 300mm*300mm and is 2.50 m long. It is required to float vertically in water and for this purpose it is proposed to fasten a lead prism of cross-section 300mm*300mm to the bottom of the log. How long should be the lead prism (S.G=12) to make the log float with 0.5m length out of water?
Generally, Centre of pressure is on the surface of body ( surface phenomenon) Centre of buoyancy is in the bulk of the body ( bulk phenomenon) Hope , this might help!
I should have got your lecture 5 years back. Excellent teaching.
I love the way you explain the concepts Venugopal sir. Thank you gate academy for this initiative to create a video archive focusing engineering exams. 😊
My University was making chutiyapa lectures....This man nailed the topic ...
Good. You make extraordinary efforts
Don't demotivate due to low no. Of views.keep it up.
Digvijay Singh thanks digvijay
😘
Excellent explanation of Buoyancy 👏👏👏
I wish I'd have seen your lectures earlier.... But its never too late...
Thanks Venu Sir
Your teaching skills are awesome sir 👍👍... Thank you so much sir.. 😊😊
Sir Mai gate academy plus ka abhari hu ki
Ki ghr baithe itni. Achhi concept mil rhi hi
This is humble request to Umesh sir
Please provide industrial engineering lecture from basics
What a way of delivering concept. Exceptional venu sir 💛
once again a super lecture...thank you sir and gate academy
Sir...excellent method of explaining..
Sir thank you!! You are genious.. Love from kashmir
Sir, I'm a student of Grade 10 of Bangladesh National Curriculum, but I still found the lecture very helpful. Thanks a lot Sir ❤️
sir you are best as I am in second sem but i started this subject and i dont know a single thing about this sunject but i understand it all you r best great teaching
Teacher h ya scientist ................uu rr bestttt
Sir, will type of equilibrium change when we make external moment in Anti clockwise direction?
Sir, In last question, if we displaced water by air then we consider buoyancy force by air or not because air is also a fluid?
Word which are used to expain r very easy ..thanks sir
Nice explanation of buoyancy
Sir khatarnak he video pura faddiahe apne.
You're awesome sir..!!❤
Understood clearly❤
Sir in the last numerical of this leacture the steel submerged between the interface of hg and water, why the force due to buoyancy is not providing a downward force by the water on the surface of steel block?
bouyoncy means upthrust force and upthrust acts in upward direction.......
Watch the lecture carefully. Sir already mentioned in the beginning of the lecture “Net Vertical Component”. Also you can see in the derivation why upward force is taken.
Thank you sir itne ache se explain krne ke liye bhut sara dhnywad.
Your teaching style is great Sir.
SIR , in the first case when B is below G , the moment due to the weight and buoyant force are in clockwise direction same as the external moment. But if we take the external moment in anti clockwise direction then even if B is below G the body will resist the external moment and we should get stable equilibrium.
..
Bro you can draw diagram by your own for both condition, you can see that if external force is anti clockwise the moment due to weight and buoyant force will also get in anti clockwise direction , so it will be unstable equilibrium (if B is below G) either your external force is anti clockwise or clockwise
@@rohitjamdagni9926yes absolutely perhaps the boy above didn’t verify it through diagram. You are absolutely correct that if we take the external moment in anticlockwise direction then the moment generated by the G and B will also be in anticlockwise. As a result of which an unstable equilibrium condition occurs.
Wonderful✨😍..
Excellent explanation of concepts thanks.
Sir external moment ka direction ACW ho skta h
Bhut hi shandar padhaten h aap sir
Ur lectures r simply superb
A tank of length 2cm,width 1m and height 1m is half-filled with water.find the pressure on bottom of tank ? Plzz tell me the answer sir plzz
Thanks to you sir
Sir you are the best teacher... Love you sir... From tripura
Thanku sir for making my fm easy😭😭😭😭
Nice conceptual clarify of topic
Lot of thank sir from the bottom of heart 🙏🙏🙏🙏🙏
Best lecture ever🔥🔥👍👍
Fantastic sir😘😘🤗🤗
Nice video ...and good explanation...
Your way... Of explaining the things... Is so good.....
And in this tutorial , in some cases the spelling of buoyancy was not right....
Please make more videos on numericals also....
Hello sir,
hope u r doing well
At 26:31
In the last problem, you added the buoyant forces(Fb1+Fb2=W).
My question is, the body is has water above it putting pressure downwards.
Then how can the forces be unlike force(The water is not putting any upwards force).
Or am I wrong here?
Same problem with me ?
The term Net Vertical Component of Hydrostatic Force comes into play. The upward force will be dominant than the downward force.
Thank u sir..It's very helpful..
What a beautiful lectures
Sir, what if the total buoyant force is higher than weight force...because due that we cant get the perfect ratio , we can get the ration in form of less than or greater than form...
You are the best sir
Good explanation👌👌
Sir what will be the bouyancy force when body touches bottom
Excellent teaching...
Superb lecture 👏👏👏👏
Sir for completely submerged bodies the center of gravity and center of buoyancy coincides .......??
If they are not coincided then the where will be the position of center of buoyancy for completely submerged bodies
Very neat explanation thank you so much sir
Sir can we get any site from where we can have the full exact notes of these lectures or we have to make our own notes by copying.
Fantastic sir I understand that topic
Sir why did u not consider the weight of body while equating vertical force
Sir one doubt !!
in case of water mercury interface water presure is down but buoyancy is upward why??????
Once again brilliant lecture sir
Lajawab
sir how we will decided that a body having B at above G or B at below G
pressure is equal in all direction when liquid in static ok, then how the pressure difference with depth sir
i think you should work on your basics ............you should also have a look on hydrostatic law .............any doubt...
Oh bhai🤣😂
Sir If we apply a moment in anticlockwise direction.
The case becomes opposite of that you have explained.
Please explain if I have understood something wrongly.
Case will be different but equilibrium will be same .
Instead of clock wise what is we apply ant-clockwise force??
it is very helpful video sir
Sir you are great...❤
Sir please upload lecture series of strength of material.
Sir aap bahot achha padhate h
Nice explanation.
Sir what is the concept about rotational stability of a submerged body
It will be stable for small rotation or oscillation, if the centre of buoyancy is above center of gravity.
Sir you have given Fb = P2A - P1A. If we take P1A this side Fb + P1A = P2A then how buyont force becomes opp to P1A
Sir how can we find center of buoyancy when in the question you solved in last?
sir why have you multiplied Area with unit weight while calculating weight of the block.where the formula for weight is roo ×G
Sorry to interrupt you sir
But as per my knowledge in submerged case postion of centre of buoyancy never changes . we change the centre of gravity of the material so please clear it and reply me if i am wrong 🙏🏻 Thanx alot sir
External moment agar anticlockwise ho to???
Sir can I get fm notes
Can u share boundary layer phenomena in internal and external flows
Great...
Speechless #✌
Awesome explanation
Sir, external force clockwise hi rahega kya...?
Wo anticlockwise Q nhi ho skta..?
Why we are considering clock wise moment / displacement while defining the stability of body ?..if we take anti clock wise B below G condition will become Stable
If you will take anticlockwise then also the net force acting on the line if action will be in produce couple in same direction of the disturbing couple
Thanks sir ❤❤❤ from Bangladesh
Well explained sir....thnx a lot...
Lot of Thanks...
Very nice explanation sir
Thank you
Thank you Sir for these lectures
3:29 Sir, you mean force? because pressure is scalar quantity.
brilliant sir ,,....thnkuuu
sir u explained everything very clearly..but plz upload a lecture on numericals of metacentric height..
Thank You So Much Sir 🙏🙏🙏
sir, why u take external clockwise moment while proving the stability and instability of the submerged body
if we take external anticlockwise direction the results will be different
totally a chawwal question...
thank a lot sir
Awesome 👍
Hello sir, please explain the concept behind this problem:
A wooden log (S.G=0.7) has a cross-section of 300mm*300mm and is 2.50 m long. It is required to float vertically in water and for this purpose it is proposed to fasten a lead prism of cross-section 300mm*300mm to the bottom of the log. How long should be the lead prism (S.G=12) to make the log float with 0.5m length out of water?
Hello di, I tried to solve this question & got my answer to this problem as 22.7 mm.. Please verify that is this correct or not..
Thank you sir ♥️😊
But sir, in B is above G wale case me W to clock wise hoga na?..
B above G ke case mein W aur Fb couple generate karenge jo ki anti-clockwise direction mein hoga.
Sir body ko agar hum ACW ghmai to stability me B force niche haga CG se kya
good teaching sir
Hello Venu sir. Please let me know what is the difference between the center of pressure and the center of buoyancy. Thank you.
..
Generally,
Centre of pressure is on the surface of body ( surface phenomenon)
Centre of buoyancy is in the bulk of the body ( bulk phenomenon)
Hope , this might help!
Please make more videos on numericals of fluid mechanics
Awesome sir. . .
Naveen Kumar ur in which year
Final year
Naveen Kumar which clg
S.K university bro in A.P