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Sir please can you explain me something I dont understand. What determines the RAx ,RAy,RBx,RBy whether they are in the positivie or negative direction of x and y ?
@@irdisulko dear at the start we don't know their directions so we just assume their directions. If we get positive answer for any reaction then it means that our assumption is correct and we can continue with that assumed direction. But if get negative value then that means our assumed direction is wrong so for further calculations we have to reverse that assumed direction.
Hello sir in order to find FHF FGH would we take the moment at a different point then at H? Because even though we have FIG to be 13.12 we still have two unknowns for Fx and Fy?
I really hope you reply me on this. You resolved forces in the x direction using sine and resolved forces on Y direction using cosine...Why? Shouldn't it be the other way?
Dear, for this you have to understand the resolution of forces. Look, it is not a rule that we should always use cosine in horizontal direction and sine in vertical direction. During resolution of forces we have to decide that with which component we are considering the angle of the resultant force. Suppose, the resultant force P makes 30 degree angle with the horizontal component and 60 degree with the vertical component. Now if you want to use 30 degree angle in the resolution of forces then as this angle is with horizontal component then the horizontal component must be cosine component and thus vertical component will be sine component. Thus horizontal component will be Pcos 30 and vertical component will be Psin30. But if you want to use 60 degree angle in the resolution of forces then as this angle is with the vertical component then this time vertical component must be cosine component and the horizontal component will be sine component. Thus, horizontal component will be Psin 60 and vertical component will be Pcos60. Now compare the above two choices: in the first choice when we took 30 degree angle then the horizontal component was Pcos30 and in the second choice horizontal component was Psin60. Now, see cos30 and sin60 have same values thus, in both the choices, the values of the components are same. So, when ever we have to decide cosine and sine components, we just have to see with which component we want to consider the angle of resultant force, then that component will become cosine component irrespective of its direction whether it is vertical or horizontal. I hope you understand
Because we took the moment of force Fig with respect to joint H and the perpendicular distance between Fig and joint H is distance HI, which we have already calculated as 16/3
Dear, we have used similar triangle law for the triangles LFG and LHI. In similar triangles, we can equate perpendicular divided by base of one traingle with the perpendicular divided by base of other triangle according to maths of similar triangles. That is why we have divided 8/15 that is perpendicular divided by base of bigger triangle and equated it with the perpendicular divided by base of smaller triangle that is HI/10.
I think you have not watched video carefully. At C it is clockwise and in the equation it is written as -5x5. Watch it again. And for your information there is no such rule of taking antibclockwise positive and clockwise negative or vice versa. Antibclockwise moments can be taken positive or negative, but you have to take reverse sign for clockwise moment thats it. If you see foreign author books they take clockwise negative and antibclockwise positive and some authors take reverse. So both ways it is correct.
My channel needs your support. If you find video useful kindly LIKE and COMMENT. As it will help in satisfying youtube algorithm rules and cover greater audience. God Bless You.
Sir please can you explain me something I dont understand.
What determines the RAx ,RAy,RBx,RBy whether they are in the positivie or negative direction of x and y ?
@@irdisulko dear at the start we don't know their directions so we just assume their directions. If we get positive answer for any reaction then it means that our assumption is correct and we can continue with that assumed direction. But if get negative value then that means our assumed direction is wrong so for further calculations we have to reverse that assumed direction.
Hello sir in order to find FHF FGH would we take the moment at a different point then at H? Because even though we have FIG to be 13.12 we still have two unknowns for Fx and Fy?
I really hope you reply me on this. You resolved forces in the x direction using sine and resolved forces on Y direction using cosine...Why? Shouldn't it be the other way?
Dear, for this you have to understand the resolution of forces. Look, it is not a rule that we should always use cosine in horizontal direction and sine in vertical direction.
During resolution of forces we have to decide that with which component we are considering the angle of the resultant force. Suppose, the resultant force P makes 30 degree angle with the horizontal component and 60 degree with the vertical component.
Now if you want to use 30 degree angle in the resolution of forces then as this angle is with horizontal component then the horizontal component must be cosine component and thus vertical component will be sine component.
Thus horizontal component will be Pcos 30 and vertical component will be Psin30.
But if you want to use 60 degree angle in the resolution of forces then as this angle is with the vertical component then this time vertical component must be cosine component and the horizontal component will be sine component.
Thus, horizontal component will be Psin 60 and vertical component will be Pcos60.
Now compare the above two choices: in the first choice when we took 30 degree angle then the horizontal component was Pcos30 and in the second choice horizontal component was Psin60.
Now, see cos30 and sin60 have same values thus, in both the choices, the values of the components are same.
So, when ever we have to decide cosine and sine components, we just have to see with which component we want to consider the angle of resultant force, then that component will become cosine component irrespective of its direction whether it is vertical or horizontal.
I hope you understand
Thank you man. Really ♥️
😊How come it result to 43.15 sir? Is there any explanation?
Sir when i solve these equations im getting -1.45 and - 13.8 sir.but its its 1.37 know sir how
Thank you so much 🙏 you just saved my day😊
God bless you
Sir finding the value of HI 80/15 i think sir you did 16/3 sir explan please sir small dout
Dear when you further solve fraction 80/15 that is divide numerator and denominator by 5 then it will become 16/3
I can under stand sir thank u sir for giving reply to me sir
How do you solve for Fhf and Fhg
Why did you multiply 16/3 with FIG ??
Because we took the moment of force Fig with respect to joint H and the perpendicular distance between Fig and joint H is distance HI, which we have already calculated as 16/3
Sir how did you get the HI=16/3? Can I have the solution?
the big trianlge (FGL) which is 8/15 = x/10 which is the small triangle (HIL) so when u sovle for x u get HI as 16/3
Dear, we have used similar triangle law for the triangles LFG and LHI. In similar triangles, we can equate perpendicular divided by base of one traingle with the perpendicular divided by base of other triangle according to maths of similar triangles. That is why we have divided 8/15 that is perpendicular divided by base of bigger triangle and equated it with the perpendicular divided by base of smaller triangle that is HI/10.
Sir please explain how to solve the FHF and FHG
Dear, It is already explained in detail in the video. If you have any doubt then ask that doubt.
Sir i understand but i didn't know How to get the value of FHF and FHG by substituting (1) and (2) .
@@dharshinis1884 Give me your email id where i can send pic of the solution of eq1 and eq2
Okay sir
sir do you have complete solution for E1 abd E2?
Yes i have notes. Send me a mail at kashmirsinghghatorha@gmail.com
I will reply with notes attachment
VERY PERFECT SIR
THANK U SO MUCH SIR
Thanks dear. God bless you
perfect🔥🔥😌💯
Thanks dear!
Thank you very much sir!!
God bless you dear
Thanks sir apse maine khus tu sikha
You are welcome dear
At C step you did wrong for clockwise positive and anticlockwise negative but you taken clockwise negative and anticlockwise positive
I think you have not watched video carefully. At C it is clockwise and in the equation it is written as -5x5. Watch it again.
And for your information there is no such rule of taking antibclockwise positive and clockwise negative or vice versa. Antibclockwise moments can be taken positive or negative, but you have to take reverse sign for clockwise moment thats it. If you see foreign author books they take clockwise negative and antibclockwise positive and some authors take reverse. So both ways it is correct.
Excellent
Thanks dear
Thanks soo much
You are welcome dear. God bless you.
satisfying
God bless you.
Stop skipping to the end broo
POV: You have an exam today
Calculation rong...??
No dear. All calculations are correct. If you have any specific doubt. Kindly ask.
@@KSGEngineering when we calculated eq1 and eq2 with GI value,then we get value not similar as your another 2 value.(GI value is correct)
Sir, can you tutor me?
Which topics do you want to learn?