R3.1.6 Strong and weak acids and bases

Поделиться
HTML-код
  • Опубликовано: 26 дек 2024

Комментарии •

  • @Fatima-gb1tp
    @Fatima-gb1tp 2 года назад +3

    why do strong acids (that have one sided arrow bcz of the complete ionization) have equilibrium if there is no reverse reaction, since equilibrium is rate of forward reaction = to rate of reverse reaction? please expalin in detail and thank you !!!

    • @MSJChem
      @MSJChem  2 года назад +3

      For strong acids and bases, the reaction more or less goes to completion (the equilibrium position lies very far to the right). So much so that the reverse reaction can be said to not actually occur.

    • @Fatima-gb1tp
      @Fatima-gb1tp 2 года назад

      @@MSJChem
      Thank you, but when you say it lies so far to the right what do you mean? What is the difference when we say equilibrium on the right and equilibrium so far on the right?

    • @MSJChem
      @MSJChem  2 года назад +1

      Lies very right much to the right is like saying the reaction goes to completion. Which means at equilibrium the concentration of products is very high and the reactants very low. In terms of Kc, lies very much to the right would mean a very large value of Kc.

  • @enanamanjas
    @enanamanjas Месяц назад

    Do you have a playlist of Inorganic/Organometallic Chemistry? or Coordination Chemistry? I searched in your channel but didn't find it.
    If not, are you thinking of making one? Cause I really like the way of explaining in all your playlists, and everything is well organized.

    • @MSJChem
      @MSJChem  Месяц назад +1

      I only cover topics in the DP chemistry syllabus. Organometallic chemistry is not covered so it’s unlikely I’ll make the videos.

  • @yuzesong7259
    @yuzesong7259 4 года назад +3

    these videos are useful and easy to understand! :)

    • @MSJChem
      @MSJChem  4 года назад

      Glad I could help.

  • @shalabi569
    @shalabi569 2 года назад +2

    How did u know that it is 0.004 at 2:55

    • @ButtonForest
      @ButtonForest Год назад +2

      I think he is just using that as an example of how it partially dissociates - you wouldn't need to memorize that or anything

    • @shalabi569
      @shalabi569 Год назад +2

      @@ButtonForest i finished IB bro 🤣🤣🤣

    • @ButtonForest
      @ButtonForest Год назад +2

      @@shalabi569 Damn you didn't get an answer in time 😔 At least it will help future students

    • @abhinavjain2161
      @abhinavjain2161 Год назад +1

      For us now M23

    • @Emkeys-i1v
      @Emkeys-i1v Год назад

      For us now M24

  • @XenSolation.
    @XenSolation. 8 месяцев назад

    do you have to remember which acids and bases are strong and which are weak?

    • @MSJChem
      @MSJChem  8 месяцев назад

      Yes.

    • @XenSolation.
      @XenSolation. 8 месяцев назад

      @@MSJChem do you also have to know the hierarchy, like, is this acid stronger than this one and whatnot?

    • @MSJChem
      @MSJChem  8 месяцев назад +1

      @XenSolation. No.

  • @asasiphuma
    @asasiphuma 4 года назад +1

    Can you please explain the difference between dissociation and ionization?

    • @MSJChem
      @MSJChem  4 года назад +3

      Dissociate means to break apart an ionic compound into its constituent ions. The term ionise means to form ions and is mainly used for covalent compounds. However they can be used interchangeably in this topic.

    • @asasiphuma
      @asasiphuma 4 года назад

      @@MSJChem okay. I think I understand. Would you mind giving an example?

    • @MSJChem
      @MSJChem  4 года назад +2

      @@asasiphuma Salts such as NaCl (an ionic compound) dissociate into ions (Na+ and Cl-) in solution. HCl (a covalent molecule) ionises in solution to produce H+ and Cl- ions.

    • @kellyjin2469
      @kellyjin2469 2 года назад

      @@MSJChem are all ionic compounds considered salts?

    • @MSJChem
      @MSJChem  2 года назад

      According to the IUPAC definition of a salt (a chemical compound consisting of cations and anions), yes. goldbook.iupac.org/terms/view/S05447