The Gaussian Elimination method - Matrices
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- Опубликовано: 4 окт 2024
- Gauss elimination method is used to solve a system of linear equations. Let’s recall the definition of these systems of equations. A system of linear equations is a group of linear equations with various unknown factors. As we know, unknown factors exist in multiple equations. Solving a system involves finding the value for the unknown factors to verify all the equations that make up the system.
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My exams is tomorrow thank God i found this video
Glad it was helpful. All the best 💪
futminna?
Yes lol@@ttayt1638
@@iqinitiativethank you so much 👍❤
@@ttayt1638yeah bro 😂 even you ?
Bro might have just saved me from failure in my exams 😭👏
Glad I could help
thanks bro you have saved me from failure, tomorrow i have exams .
Making it understandable. Thumbs up👍
Cheers mate 👍
Great video
Good explanation 🙏🤝
Glad it was helpful
Does the diagonal numbers always have to be equal to one? Because from what I understand is that we are eliminated the number of unknown variables to a point where we can easily solve the variables by backward substitution
No. They don't always have to be ones. You can use other numbers as well as long the you maintain the zeros and then you use backward substitution.
Well explained 🔥🔥👏👏👏
I'm glad it was helpful 😊
Tnk u sir 🙏
12:48 why is the operation R2:1/-2 ×r2
In the first exam we said 1/3 not 1/-2
How can that happen ? Can we change the operation when ever we want?
That's what I'm saying
Thank you so much
You're most welcome
thank you for this
You're welcome 😊
Sır is it necessary to make the first row corners 1?
Please where did you get the 2 operation
👏👏
👍
How can 2x1 be 0
4:24 why 2x1 =0?
It's an operation 2(1) - 2 = 0
thankyou
@@iqinitiativei don't understand, where'd the second 2 come from NJ
how can i do this one?
3x-2y=z
6x+2z+6y=2
-x+y+3z=1
x= -13/27, y= 7/9, z= 1/9
Thank ❤
You're welcome 😊
no understand
English dialect PNG? 😊
😊
Simplified 😅
Yes 🙂