For number 8 the answer is C, there is an error, you consider the whole area under the graph, because we consider the thinking distance, so Area of a Trapezium 1/2 (0.8+5) × 20 =58m My bad
You are welcome, just trying to make it easier to understand and more interactive, hope it helps, if you have any questions please do comment or a specific paper you would like to get solved
For number 8 the answer is C, there is an error, you consider the whole area under the graph, because we consider the thinking distance, so
Area of a Trapezium
1/2 (0.8+5) × 20
=58m
My bad
Really nice explanation, clear concise
and very cool animations😂❤
You are welcome, just trying to make it easier to understand and more interactive, hope it helps, if you have any questions please do comment or a specific paper you would like to get solved
Thank u brother for solvig these papers...you are a lifesaver really thank u man 😭
Youre welcome, please do speak out if you have any questions or a specific paper you want solved
Brother if possible please try to also do 9702/11/o/n/19 😭
Ok, I will try to look into that and put it on my upload scedule
I have uploaded the video you requested, please do check it out if you are interested (ruclips.net/video/DB0P44pcv2Y/видео.html)
thank you sir!❤
hey in question 3 how did u knew Y was the resultant vector
I did same mistake as you
for no 8 ans is C
I think because there is
thinking distance so
You consider the whole
Area
Definitely, I am seeing it now, I made a mistake, thank you for pointing that out, it was supposed to be the whole area indeed, my bad
@@Alevel_Physics no worry welcome