A Nice Polynomial Expression
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- Опубликовано: 18 ноя 2024
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? = x(x^4-29) makes it easier. x = sqrt(2)+1. x² = 3+2sqrt(2). x^4 = 17+12sqrt(2). Fill in ? = (sqrt(2)+1)(17+12sqrt(2)-29) = (sqrt(2)+1)(-12+12sqrt(2)) = ... = 12.
Or you could just use your method on x=√2+1. AKA The Silver Ratio!
x^2=3√2+1
x^3=5√2+7
x^5=29√2+41
x^5-29x=41-29=12
But keeping the x as a variable is a sweet solution.
x⁵-29x=x(x⁴-29)
x=1+sqrt(2) --> x²=3+2sqrt(2)
x⁴=17+12sqrt(2)
x⁴-29=-12[1-sqrt(2)]
x(x⁴-29)=-12[1+sqrt(2)][1-sqrt(2)]
=-12[(-1)
=12
Common procedure:
x=1+sqrt(2)
x⁵=[1+sqrt(2)]⁵
=1+5sqrt(2)+10(2)+10[2sqrt(2)]
+5(20)+4sqrt(2)
=121+29sqrt(2)
29x=29+29sqrt(2)
x⁵-29x=92
Or a recursive approach...
x₁ y₁
x₂ = x₁ + 2y₁ y₂ = x₁ + y₁
Also x₃ = 2x₂ + x₁ and y₃ = 2y₂ + y₁
1 1
3 2
7 5
17 12
41 29
Plus the value pairs, alternately, are solutions for the diophantine equations x² = 2y² - 1 and x² = 2y² + 1
x^2=2x+1; x^3=2x^2+x=5x+2; x^5=(2x+1)(5x+2)=10x^2+9x+2=29x+12
x^5-29x=29x+12-29x=12
Answer = 12