A Nice Polynomial Expression

Поделиться
HTML-код
  • Опубликовано: 18 ноя 2024
  • 🤩 Hello everyone, I'm very excited to bring you a new channel (SyberMath Shorts).
    Enjoy...and thank you for your support!!! 🧡🥰🎉🥳🧡
    / @sybermath
    / @aplusbi
    ⭐ Join this channel to get access to perks:→ bit.ly/3cBgfR1
    My merch → teespring.com/...
    Follow me → / sybermath
    Subscribe → www.youtube.co...
    ⭐ Suggest → forms.gle/A5bG...
    If you need to post a picture of your solution or idea:
    in...
    #algebra #polynomials #polynomial
    via @RUclips @Apple @Desmos @NotabilityApp @googledocs @canva
    PLAYLISTS 🎵 :
    ▶ Trigonometry: • Trigonometry
    ▶ Algebra: • Algebra
    ▶ Complex Numbers: • Complex Numbers
    ▶ Calculus: • Calculus
    ▶ Geometry: • Geometry
    ▶ Sequences And Series: • Sequences And Series

Комментарии • 6

  • @mystychief
    @mystychief Месяц назад +1

    ? = x(x^4-29) makes it easier. x = sqrt(2)+1. x² = 3+2sqrt(2). x^4 = 17+12sqrt(2). Fill in ? = (sqrt(2)+1)(17+12sqrt(2)-29) = (sqrt(2)+1)(-12+12sqrt(2)) = ... = 12.

  • @ianfowler9340
    @ianfowler9340 Месяц назад

    Or you could just use your method on x=√2+1. AKA The Silver Ratio!
    x^2=3√2+1
    x^3=5√2+7
    x^5=29√2+41
    x^5-29x=41-29=12
    But keeping the x as a variable is a sweet solution.

  • @nasrullahhusnan2289
    @nasrullahhusnan2289 Месяц назад

    x⁵-29x=x(x⁴-29)
    x=1+sqrt(2) --> x²=3+2sqrt(2)
    x⁴=17+12sqrt(2)
    x⁴-29=-12[1-sqrt(2)]
    x(x⁴-29)=-12[1+sqrt(2)][1-sqrt(2)]
    =-12[(-1)
    =12
    Common procedure:
    x=1+sqrt(2)
    x⁵=[1+sqrt(2)]⁵
    =1+5sqrt(2)+10(2)+10[2sqrt(2)]
    +5(20)+4sqrt(2)
    =121+29sqrt(2)
    29x=29+29sqrt(2)
    x⁵-29x=92

  • @paulortega5317
    @paulortega5317 Месяц назад

    Or a recursive approach...
    x₁ y₁
    x₂ = x₁ + 2y₁ y₂ = x₁ + y₁
    Also x₃ = 2x₂ + x₁ and y₃ = 2y₂ + y₁
    1 1
    3 2
    7 5
    17 12
    41 29
    Plus the value pairs, alternately, are solutions for the diophantine equations x² = 2y² - 1 and x² = 2y² + 1

  • @wes9627
    @wes9627 Месяц назад

    x^2=2x+1; x^3=2x^2+x=5x+2; x^5=(2x+1)(5x+2)=10x^2+9x+2=29x+12
    x^5-29x=29x+12-29x=12

  • @trojanleo123
    @trojanleo123 Месяц назад

    Answer = 12