I am inherently good at quant and got a Q51 in an official mock. However, I did not know around 80% of the techniques used in this video. Proud to say this webinar was useful for me and I am sure would be for everyone.
Answer to 700 ( last question ) is both conditions are sufficient. On solving the given equation, we will get two solutions x=y or x+y=-4 (remove the mod and solve by type3). To remove x=y solution, we need a statement to say x and y are not equal. XY2, Y
Wow, I am speechless after watching Aditya’s inequalities and absolute value sessions. No one (I mean it… absolutely “No One” 😊) could have explained these topics better than him. MUST MUST WATCH, if you really want to understand these concepts !!
The question around minute 38, I think the question should be is x>IyI? and not is x>y. Therefore, the answer to the question should be E and not C. For the second case where the conditions are y>0 and x>y, yes the answer is C. Please correct me if I am wrong. Thank you very much for this very insightful video.
I am not sure if Aditya (the instructor in this video) is actively following the comments posted here. Perhaps it would be a good idea to post this question and your query in GMAT Club quant forum to seek feedback from the community and experts. gmatclub.com/forum/quantitative-7/
Thank you so much Aditya. I have been struggling with Absolute Value since long. It used to haunt me like anything. You just made it approachable for me. Thanks a ton
In the question is x|y| > y^2 along with conditions x > 0 , x > y we can also add one more that is y < 0 bcz in the equation y is inside mode on the L.H.S and getting squared on the R.H.S where it converted into postive both the sides .
Thank you so much for this video - Aditya and GMAT club! I've been struggling with inequalities since the beginning of my prep, and I'm so glad I found this video. FINALLY, I feel like I have an idea of how to approach these questions. How you've managed to make even this topic seem easy is beyond me.
Glad it was helpful! It's indeed a speciality of Aditya to teach complex subjects in easy and simple language. Pls don't forget to press LIKE and SUBSCRIBE!
It think there is mistake @38:26.......The answer will be "E" for the first question. Because the right condition we need to satisfy would be x > |y|, not just "x > y". For example, consider, x = 4 and y = -3, this makes the question true. However, we consider x = 4, y = -6, then it negates the above equation, while both cases are complying with the two options i.e. x>0 and x>y. Hence I am saying that the essential condition is x>|y|, and not x > y.
Yeah that's right. But while solving it he said the magnitude of x should be greater than the magnitude of y; and if we say |x| > |y|, and x>0, then it would suffice.
Hello, wouldn't we need in the problem "x * IyI > power(y , 2)", the information confirming that y != 0? This is given in the second instance of the problem, where y > 0 and x > y, but not in x > 0 and x > y. Therefore, I would think the info from both last statements to be insufficient. Thank you for your time. I hope to get an answer, please.
Hello aditya, great work but help me umderstand why in 33:44 a and b cannot both be negative because |-2+ -3| which is |-5| is not < |-2- -3| which is |1|
Aditya thank you so much. You're an amazing teacher! Made this complex topic soo soo easy and really made us understand that how incorrect rather time consuming the plug-in approach is.
Very good explanation of concept & beautiful sample questions to build the right & easy understand. Hope to have more videos like this on other topics as well.
Thank you very much! Do Subscribe to our channel to get notifications of future sessions. Upon subscribing, you will get FREE Access to our Premium GMAT Question Bank for 7 Days gmatclub.com/google_verify.php
In 43:20, why do we make the sign of the entire absolute variable be negative, and not just the variable? Meaning, if we are plugging in the variable x, wouldn't we only change the sign of the X?
In the question ‘what is the value of y?’ Can I directly say that 1 will give me 2 values of x coz degree is 2 which means I can’t find y directly. Moving on to 2 gives me 2 possibilities which when I check in 1 show that y will be imaginary if x is -8. Giving me my answer c and y=14. Please tell me if this is the correct way to see this?
the answer should either be E or changed question: prompt: x|y|>y^2 ? 1. x> 0 2. x> y you don't know if y >0. statement E. or change question to "x|y|>y^2 ? if y > or < 0" then answer is statement C
@@jaanvidaiya but based on "the prompt" is x*abs(y) > y^2 and then the info from the statements.... if y is 0 then the term is not greater, if y is greater than 0, it is.
Hi, this was a great session. However, i do have a question on the general form for greater than. I tried applying the same to the below two questions and couldn't get the correct answer: 1. |x+5| > | 3x-2| 2. |x+3| >= 4x would highly appreciate a response on this.
hi gmat club for type 4 absolute values in 1:05:50 why not take the roots like in the case of type 3 and have x and y to be less than 0? please help. I cant seem to move forward from this
Hi Caroleg, not sure if Aditya is still following this comment thread; I think it will be more helpful if you just post your doubt in the Quant forum on GMAT Club (gmatclub.com/forum/quantitative-7/) and make sure to tag @Bunuel in your post; I am sure Bunuel and other GMAT experts on the forum will help address your question.
can the concept of 5 types be used for multiple equations as well? In our example, we had only one inequality in which there was only one parenthesis. can we use this concept if we have more than one parenthesis? If yes, please share an example
Perhaps you should ask this in Quant forum gmatclub.com/forum/quantitative-7/ Don't forget to subscribe to our channel & Get free GMAT mock tests for 7 days.. gmatclub.com/google_verify.php
These questions absolutely fried my brain lol.. but i thank you for the absolutely excellent explanation… it’s frustrating to know how absolutely useless these questions are in the real world..
In 38:56, Shouldn't the answer be E instead of C? Don't we need |x| > |y| (instead of x > y)? If x = 2 and y = -3, then LHS is 6 and RHS is 9 : then x|y| < y^2 If x = 4 and y = -3, then LHS is 12 and RHS is 9: then x|y| > y^2
We can do it with that method, but it'll only take more time. Instead, if we think that 5-x is greater than or equal to 0, then it'll make our life much easier.
Hey guys, I have a question linked to this one. During the whole webinar the explanation was that |x| = something, we can analyze that X => 0, but in this problem, the approach was to take the something =>0, and the results are different. Can anyone tell me why use 5-x =>0 instead of x-5 =>0. Thanks in advance.
You are incorrect for the question at 35:07 the correct answer is x > |y| for the equation x |y| > y^2 You have x > 0 and x>y However, to prove this incorrect. Use x = 4 and y = -5 These numbers satisfy your condition of 4 > 0 and 4 > -5 The do NOT satisfy the original equation. 4 x |-5| is not greater than (-5)^2
![How to Solve Mixture Questions on the GMAT? [Webinar]](http://i.ytimg.com/vi/SExmttNK5Mg/mqdefault.jpg)
I am inherently good at quant and got a Q51 in an official mock. However, I did not know around 80% of the techniques used in this video. Proud to say this webinar was useful for me and I am sure would be for everyone.
If it had been the question of ‘weakening the argument’
I would have gone with your comment as the answer.😅
This man is a legend! Makes things so simple, even though my quant is already good, I learnt a lot
wish he did a couple more videos
Aditya out here dropping straight knowledge. No messing around. Well structured and concise. MVP!
Thank you so much for your feedback and support 👍
What happened to solving the q on the front of the video
Answer to 700 ( last question ) is both conditions are sufficient. On solving the given equation, we will get two solutions x=y or x+y=-4 (remove the mod and solve by type3).
To remove x=y solution, we need a statement to say x and y are not equal.
XY2, Y
So ultimately what is the answer ..what is the value of X+Y?
Is it -4?
Aditya you're doing God's work. I'm watching this way 2 years in the future and this is absolutely incredible. Thank you for the work you are doing.
Wow, I am speechless after watching Aditya’s inequalities and absolute value sessions. No one (I mean it… absolutely “No One” 😊) could have explained these topics better than him. MUST MUST WATCH, if you really want to understand these concepts !!
Wow Aditya Kumar is brilliant at breaking down and explaining complex problems.
Thanks for really breaking things down to the very basic level and making to more interesting to learn these concepts 👍
No side hustles, straight to the point. Awsome Aditya. Very helpful. Im struggling on accuracy of Absolute values. This is saver for me :)
This was an amazing session, really recommend going through it
👍 Thank you for the feedback. We appreciate it as we look for ways to bring the right topics to our channel.
The question around minute 38, I think the question should be is x>IyI? and not is x>y. Therefore, the answer to the question should be E and not C. For the second case where the conditions are y>0 and x>y, yes the answer is C. Please correct me if I am wrong. Thank you very much for this very insightful video.
I am not sure if Aditya (the instructor in this video) is actively following the comments posted here. Perhaps it would be a good idea to post this question and your query in GMAT Club quant forum to seek feedback from the community and experts. gmatclub.com/forum/quantitative-7/
Thank you so much, Aditya! Wonderful lesson! Thank you also to the GMATClub
Thank you so much Aditya. I have been struggling with Absolute Value since long. It used to haunt me like anything. You just made it approachable for me. Thanks a ton
In the question is x|y| > y^2 along with conditions x > 0 , x > y we can also add one more that is y < 0 bcz in the equation y is inside mode on the L.H.S and getting squared on the R.H.S where it converted into postive both the sides .
Another gem of a video. Here is to more content from you sir! GMAT club are you listening!
I have never dreaded a topic more than this. Thank you so much for making it a cakewalk!!
Thank you! Stay tuned as Aditya Kumar is coming back on RUclips with more such powerful sessions. Stay Subscribed!
Thank you so much for this video - Aditya and GMAT club!
I've been struggling with inequalities since the beginning of my prep, and I'm so glad I found this video. FINALLY, I feel like I have an idea of how to approach these questions. How you've managed to make even this topic seem easy is beyond me.
Glad it was helpful! It's indeed a speciality of Aditya to teach complex subjects in easy and simple language. Pls don't forget to press LIKE and SUBSCRIBE!
It think there is mistake @38:26.......The answer will be "E" for the first question. Because the right condition we need to satisfy would be x > |y|, not just "x > y". For example, consider, x = 4 and y = -3, this makes the question true. However, we consider x = 4, y = -6, then it negates the above equation, while both cases are complying with the two options i.e. x>0 and x>y. Hence I am saying that the essential condition is x>|y|, and not x > y.
Agree was thinking the same!
The most important video on GMAT Quant on youtube.
The problem in 37:55 is wrong I think.
X>|y| this should be the case.
only X>0 and X>y will not solve the equation.
Ex: X=1, Y=-2
yeah, was thinking about making a comment that there's mistake
Yes that's true but the second part is correct where 1st statem is y>0 and 2 is x>y is accurate
Yeah that's right. But while solving it he said the magnitude of x should be greater than the magnitude of y; and if we say |x| > |y|, and x>0, then it would suffice.
Fantastic class sir! But where is the last question you just mentioned at the end (700 type question)?
This was brilliant. I was struggling a lot with absolute values with inequalities and found the video incredibly helpful
Great to hear! Do Subscribe to our channel.
Thank you so much for these amazing sessions on inequality and modulus!
Thanks a lot Aditya. Both Inequality and Abs value videos are very helpful and packed with concepts :).
Hello, wouldn't we need in the problem "x * IyI > power(y , 2)", the information confirming that y != 0? This is given in the second instance of the problem, where y > 0 and x > y, but not in x > 0 and x > y. Therefore, I would think the info from both last statements to be insufficient. Thank you for your time. I hope to get an answer, please.
Please mention the time stamp and we will see if that question is discussed on GMAT Club.
@@gmatclub39:06
By far the best video I have seen on this topic
Hello aditya, great work but help me umderstand why in 33:44 a and b cannot both be negative because |-2+ -3| which is |-5| is not < |-2- -3| which is |1|
@Aditya Kumar You are truly quant master. Learnt so much...Thanks a tons
why was the 700 question cut off?
yes?
@59:00 Type II, @1:01 Type III & Type IV @1:06 Type 5
Aditya thank you so much. You're an amazing teacher! Made this complex topic soo soo easy and really made us understand that how incorrect rather time consuming the plug-in approach is.
I has alwyas been a pleasure getting into your quant sessions...just loved it..
Thank you for your kind words.
Wonderful video - thank you Aditya and GMAT Club
Very good explanation of concept & beautiful sample questions to build the right & easy understand. Hope to have more videos like this on other topics as well.
Thank you very much! Do Subscribe to our channel to get notifications of future sessions. Upon subscribing, you will get FREE Access to our Premium GMAT Question Bank for 7 Days gmatclub.com/google_verify.php
Wow.. Thank you. You make things sound so simple
Aditya is a hero
In 43:20, why do we make the sign of the entire absolute variable be negative, and not just the variable? Meaning, if we are plugging in the variable x, wouldn't we only change the sign of the X?
Is there some link where I could find the whole video? I would like to check the last excercise, but it seems that tha video was cut at the last part.
Unfortunately that video is not available with us anymore.
In the question ‘what is the value of y?’ Can I directly say that 1 will give me 2 values of x coz degree is 2 which means I can’t find y directly. Moving on to 2 gives me 2 possibilities which when I check in 1 show that y will be imaginary if x is -8. Giving me my answer c and y=14. Please tell me if this is the correct way to see this?
so happy i found this session! thank you aditya
amazing video. Thanks for clearing so many concepts.
Brilliant session.
That was mind blowing! Thank you.
Really made things simple for me. Thanks.
Thank you so much Aditya!!! ✨
sir the session was so helpful thanks a lot. awesome class
@aditya kumar: can you plz upload vedios of number system?
37:38 - 2nd condition should be x>|y| -------> eg. nos to solve this, x=2, y=-3 ----> x|y| = 6, y^2=9, LHS
Thank you Aditya, I’ve atleast watched this 4 times now!
So nice! Do also subscribe to our channel.
Pls provide solution for the last question@@gmatclub
Great..
Simply brliant
Really Awesome Explanation Aditya Kumar Sir ! You have great sense of explaining.
He is good but you are not Abhijeet Patel
@@poojaarora9504 who is that
@@ryankoech I just came to know him through some admission sessions.
the answer should either be E or changed question:
prompt: x|y|>y^2 ?
1. x> 0
2. x> y
you don't know if y >0. statement E.
or change question to "x|y|>y^2 ? if y > or < 0"
then answer is statement C
Correct. Nice observation
Either way y is going to be positive or 0 so c is correct
Either way y is going to be positive or 0 so c is correct
@@jaanvidaiya but based on "the prompt" is x*abs(y) > y^2 and then the info from the statements.... if y is 0 then the term is not greater, if y is greater than 0, it is.
Legend in gmat quant !! Thank you !!
Had to write this...you are Bond...James Bond
WOW !
Super helpful, thank you!
Excellent teaching Aditya
this is such a game changer - thank you!
man this was a brilliant explanation - good stuff @Aditya
perfect. thank you for great explanation
Great video, Thanks Aditya
Glad you liked it!
Amazing session!
Thank you so much guys!!! This was so so helpful 🔥
Incredible. Thanks a lot!
Reach out to Aditya Kumar on LinkedIn www.linkedin.com/in/aditya-kumar-a29a6779/
|3-y| also means y
This is awesome, thank you!
You're very welcome! Don't forget to hit the subscribe button and get GMAT Tests FREE for 7 days gmatclub.com/google_verify.php
Very well explained , thanks !!!
Was the last 700 level question cut off from this video? I felt like it ended abruptly.
Hi, this was a great session. However, i do have a question on the general form for greater than. I tried applying the same to the below two questions and couldn't get the correct answer:
1. |x+5| > | 3x-2|
2. |x+3| >= 4x
would highly appreciate a response on this.
this wount go on the general form. Its more of a miscellaneous as 4x is a variable. analysis will be better here
first x> -3/4 or x< 7/2, second is x
Could I please get the link for the inequalities webinar?
Actually, all the links mentioned? They don't show in the chat window
38:25 I have a doubt, wouldn't it be 'not sufficient' "Option E" as the conditions given doesn't clarify y>0??
i think the question was whether x is positive
hi gmat club for type 4 absolute values in 1:05:50 why not take the roots like in the case of type 3 and have x and y to be less than 0? please help. I cant seem to move forward from this
Hi Caroleg, not sure if Aditya is still following this comment thread; I think it will be more helpful if you just post your doubt in the Quant forum on GMAT Club (gmatclub.com/forum/quantitative-7/) and make sure to tag @Bunuel in your post; I am sure Bunuel and other GMAT experts on the forum will help address your question.
In the type 5 example at roughly 1:14:00, why do we just have to know whether x
Thank you so much! Amazing vid
Great teacher
Thank you! 😃
can the concept of 5 types be used for multiple equations as well? In our example, we had only one inequality in which there was only one parenthesis. can we use this concept if we have more than one parenthesis? If yes, please share an example
Perhaps you should ask this in Quant forum gmatclub.com/forum/quantitative-7/
Don't forget to subscribe to our channel & Get free GMAT mock tests for 7 days.. gmatclub.com/google_verify.php
These questions absolutely fried my brain lol.. but i thank you for the absolutely excellent explanation… it’s frustrating to know how absolutely useless these questions are in the real world..
such a great video thank you!
absolutely brilliant 👍
Thank you so much sir. Really helpful 🤗
Thanks for the video
Our pleasure. Stay Subscribed!
Thank you very much
Do you offer tutoring?
I think I need help!
He does, reach him on linkedin
In 38:56,
Shouldn't the answer be E instead of C?
Don't we need |x| > |y| (instead of x > y)?
If x = 2 and y = -3, then LHS is 6 and RHS is 9 : then x|y| < y^2
If x = 4 and y = -3, then LHS is 12 and RHS is 9: then x|y| > y^2
You're right! But if we know y>0 like in the second condition, then x>y will suffice.
at 30:00 should n be anything except 0?
At time 1.15.00 hr, in that particular problem why can't we solve the equation |x-5|=5-× by considering( x-5 )can be positive or -(×-5) .
We can do it with that method, but it'll only take more time. Instead, if we think that 5-x is greater than or equal to 0, then it'll make our life much easier.
@@geetpatel5155 Thank you. Got it 👍
@@geetpatel5155 if you do by sarath method,it actually giving me x has to be either 5 or 0 only not the range,is it true?
Hey guys, I have a question linked to this one. During the whole webinar the explanation was that |x| = something, we can analyze that X => 0, but in this problem, the approach was to take the something =>0, and the results are different. Can anyone tell me why use 5-x =>0 instead of x-5 =>0. Thanks in advance.
At 37:27 in the video there must be one more condition Y>0
Please take a session on time and work, time and distance
We have a session precisely on these topics today at 9:30pm IST ruclips.net/video/MpwbvpaO7kA/видео.html
if u r some one who has not studied maths in 11th /12th should watch this video.
at 38:30 wouldnt answer be E?
9:00 Variable cancellation
14:40- Basics
49:30 - Type 1
1:01:00 - Type 2
1:08:00 - How to plug in values in sure shot way (Revise)
57:33 - how to create a range
thank you so much it s really helpful
Glad to hear that! 👍
You are incorrect for the question at 35:07 the correct answer is x > |y| for the equation x |y| > y^2
You have x > 0 and x>y
However, to prove this incorrect. Use x = 4 and y = -5
These numbers satisfy your condition of 4 > 0 and 4 > -5
The do NOT satisfy the original equation. 4 x |-5| is not greater than (-5)^2