Hey everyone ! At 15:48 in this video ...the ques that I'm solving is right but the answer is Diastereomers not Enantiomers since the reactant already had a Chiral centre . Also the products that we get are also not the mirror images of each other but they have same connectivity ...so the ans is "they are Diastereomers"
Hello mam! Thankyou so much for this video but mam in the second last question why didn't you considered the gauche interaction between R and R' ? They both are bulky groups na
31.43 i hv one daught If we consider, in the reactant both methyl grp at axial positions... Then we get (R'-Me interaction =0.9 kcal/mol + R - Me interaction = 0.9kcal/mol) that is equal to 1.8 kcal/mol for reactant only.... And 1.8 kcal/mol for product... Therefore in total we get....... 1.8 (reactant) + 1.8 (product) = 3.6 kcal/mol
In 20.03 min qsn how it is mirror image of each other H n tributyl also change in mirror image .And in qsn N attack is given in A ( product ) so how attack on other side for makes qsn of racemic himself.
Hi maam.. apke ENANTIOTOPIC and diastreotopic differentiate kia hai between H1 and H2 v/s Br1 & Br2 ... usme apne H ko DIASTEREOTOPIC bola hai becoz they are bisecting(as u explained here) aur plane dono H k beech se paas ho rha hai.... Is that bisecting????????? Apki prev. Video me aapne hi smjhaya tha ki bisecting mtlb dono H ko half half kr rha ho plane... Yaha to jab kisi bhi H ko half hi nhi kia plane ne to howcome we are saying that they are bisected??? MAAM ITNA BADA TYPE KIA HAI... PLS REPLY..
Plane is cutting both hydrogen atom, if it was passing in between both hydrogen atom then it can be considered as enantiotopic But in our case it is just cutting both hydrogen
Thank you mam for solving this previous questions.. but at 3:47 in this vedio i.e. in the 2nd question aap ne kaha mirror image nehi hai to superimosable kaise hua..?? I mean jab mirror image hi nahi hai to hum superimosable or non-superimposable detect kiun kare?
At 21:37, the stereo of H & t-butyl is not changing, then how the two products are enantiomers? Because at 15:48 since the reactant already had a chiral centre, the products formed were diastereomers. Pls clear my doubt
mam can you plz tell which book you are using to get question of csir chapterwise..because I was not able to find any book in which question of csir is given chapterwise..and plz continue to make videos because its very helpul for us...since we are from a village where no coaching institute are available...thank u mam
mam, you have calculate delta G value for product 1.8 and reactant delta g value 0.9 in gauche value detrmination. what is the delta g value of reaction . will i subtract value from product to reactant for delta G for reaction. please explain?
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Identical molecules are also the mirror images of each other. Ap hi NE btaya tha. So how can u say in 3:26 or 2nd question. It is not mirror images but superimposed. Please elaborate it.
Mam , the gb int question at 31:20 min ,(ques of the year net ,dec,2012)...i think the ans should be 0.9 kcal /mol cuz here mention the ∆ G value....i.e (1.8-0.9=0.9)
34:11 the answer is correct but the procedure is wrong..... For the cis isomer there are 3 gauche butane interaction. So ∆G= (3×0.9)-0.9= 1.8 kcal/mol. Please check.
hello mam 11th quesation mai ans A aayega naa becoz epoxide ring above the plane hai so attack below the plane hoga......so we will get only one product.......
The method she followed here is wrong. In the reactant there is only one G.B. interaction and in the product there is three G.B. interactions. So net change in G.B. interactions is (3-1) = 2 So , delG = 2×0.9 = 1.8 . This is the correct method.
Hey everyone !
At 15:48 in this video ...the ques that I'm solving is right but the answer is Diastereomers not Enantiomers since the reactant already had a Chiral centre . Also the products that we get are also not the mirror images of each other but they have same connectivity ...so the ans is "they are Diastereomers"
yes Madam.
Yes mam
Yes, I was just going to comment on this
Ryt I just comment .
Thanks for point out.
@24:40 4th carbon should be in R configuration, right?
What an effort u r putting great 😀
Mam in q. No. 12 , in camphor position marked as 1 how will check R/S?? I hv tried it but my ans. is wrong, plz mam tell me
Hello mam! Thankyou so much for this video but mam in the second last question why didn't you considered the gauche interaction between R and R' ? They both are bulky groups na
Good observation....
Even i need the answer
Bcoz actually R and R' are not two different groups ... It's a ring
17.20 and 22.27 also diastereomers
Yes maam... Product is okay bt configuration of one stereocentere changes only so are diastereomers..
Mam I think in the case of markownikov addition the pdts a and b will be diastereomers by Assingning absolute configuration to the chiral centres
Ha Bhai vh diasteromers Hee h..... RS and RR absolute configuration aa raa h unka isliye
@@ronit4136 hmm thanks bro u got my point.
Mam markownikov add rxn ans should be the diastereomers(2011 june Dec)...17 mins onwards video
Maam aap is vdio me bhut ache lgre😘😘😘👨🏫🙏💫💯
31.43 i hv one daught
If we consider, in the reactant both methyl grp at axial positions... Then we get (R'-Me interaction =0.9 kcal/mol + R - Me interaction = 0.9kcal/mol) that is equal to 1.8 kcal/mol for reactant only.... And 1.8 kcal/mol for product... Therefore in total we get....... 1.8 (reactant) + 1.8 (product) = 3.6 kcal/mol
e,e conformer given in the question, ie, equitorial
Mam in case of 2nd last question no of G.B interaction for cis 1-2dimethlycyclohexene is three or two? In IIT jam 2019 it is mentioned 3
why the interaction between R and R* is not considered? plz ans mam
There is 3 gauche butane interaction delG 2.7-0.9 =1.8
I was looking for this coment, glad I found it. Thank you for commenting
In 20.03 min qsn how it is mirror image of each other H n tributyl also change in mirror image .And in qsn N attack is given in A ( product ) so how attack on other side for makes qsn of racemic himself.
Bilkul bahi meara b yhi question hn yh dou enantomers kaesae hn kk homocyclic part pae jo chiral carbon hn uski configuration dounou mae same hn. Mearae khayal sae yh diastereomers hn
Thanks ma'am. Thanks a lot
Hi maam.. apke ENANTIOTOPIC and diastreotopic differentiate kia hai between H1 and H2 v/s Br1 & Br2 ... usme apne H ko DIASTEREOTOPIC bola hai becoz they are bisecting(as u explained here) aur plane dono H k beech se paas ho rha hai.... Is that bisecting????????? Apki prev. Video me aapne hi smjhaya tha ki bisecting mtlb dono H ko half half kr rha ho plane... Yaha to jab kisi bhi H ko half hi nhi kia plane ne to howcome we are saying that they are bisected???
MAAM ITNA BADA TYPE KIA HAI...
PLS REPLY..
I have same doubt.. Pls ans ASAP
They are getting bisected..plane is passing through the hydrogen atoms.
Plane is cutting both hydrogen atom, if it was passing in between both hydrogen atom then it can be considered as enantiotopic
But in our case it is just cutting both hydrogen
Why you didn't consider the interaction between R n R' on 34.26
dear mam
at 12.51 video why we have to rotate and then find the optical activity?why cant we directly find the optical activity?kindly reply
Thank you mam for solving this previous questions.. but at 3:47 in this vedio i.e. in the 2nd question aap ne kaha mirror image nehi hai to superimosable kaise hua..?? I mean jab mirror image hi nahi hai to hum superimosable or non-superimposable detect kiun kare?
Mam if mirror images is not there then it's diesteriomer
At 21:37, the stereo of H & t-butyl is not changing, then how the two products are enantiomers? Because at 15:48 since the reactant already had a chiral centre, the products formed were diastereomers. Pls clear my doubt
Yes you are right (c) option is correct. Product formed will be diastereomers
Tbh you're looking so pretty in this video ma'am ❤🙏
Happy teacher day "maam"😍😍😍😍💫👩🎓👩🎓👨🏫💯💥
Mam please check at 22:41 the position of oh and 2 degree amine is fixed with respect to tertiary carbon i.e given but stereochemistry is different
The answer will be (c)two diastereomers.
Bilkul bahi
mam can you plz tell which book you are using to get question of csir chapterwise..because I was not able to find any book in which question of csir is given chapterwise..and plz continue to make videos because its very helpul for us...since we are from a village where no coaching institute are available...thank u mam
ruclips.net/video/vJst9tqeMm4/видео.html
mam, you have calculate delta G value for product 1.8 and reactant delta g value 0.9 in gauche value detrmination. what is the delta g value of reaction . will i subtract value from product to reactant for delta G for reaction. please explain?
Yes...I have the same doubt...
@@beingunpredictable5497 Actually cis isomer have 3 bgi , So : 2.7-0.9 = 1.8 kcal/mol !!
Ans is correct, procedure is wrong !!
j chemistry madam please delta g value how we Calculate please explain i don't understand thanks..
Thank you so much .very intresting video
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I'm also in need of it
Mam bht achha teach krvaate ho aapn🤗🤗
Identical molecules are also the mirror images of each other. Ap hi NE btaya tha. So how can u say in 3:26 or 2nd question. It is not mirror images but superimposed. Please elaborate it.
If not mirror images is the first observation means diasteriomers she told while explaining in her previous vedio 🙄
very very thanku madam for solving the previous yrs que . it helps a lot to increase our confidence
Mam in q. 5,Me/Me has most gauche interaction but u said no gauche interaction should occur
I.e. not 60 degree occur. Why?? Plzzzz explain mam
Mam , the gb int question at 31:20 min ,(ques of the year net ,dec,2012)...i think the ans should be 0.9 kcal /mol cuz here mention the ∆ G value....i.e (1.8-0.9=0.9)
Yes ∆G = G (product) - G(reactant)
= 1.8-.9 = 0.9
Another thing is here 1,3 diaxial interaction will happen btw H and Me group so energy would be 1.8
1.Q.Superiposable mirror images ,ennontiomers
Mam markownikoff rule question me diasteriomers ans ho sakta hai??
Mam please review the answer of 24.39 min in this video?Is it correct?
Yes both are not S,S
Mam jo aapne gauche interaction ka question karvaya hai. Jiska answer 1.8 hai. Ume R R group me gauch interaction kyu nahi hogi?
Actually that's a ring ... Not two different groups thats y
@@NavneetPannu-qu9hv got it. Thanks:))👍
So if it would b a alkyl (bulky) gp than we will consider.
Mam at 34:20 why nt considering r r gauche interaction. Pls reply
Mam, last question ka aage wala question ki ans samajh nahi aaya, can you please explain it ? 🙏🏼🙏🏼
Thank you so much madam 🙏
Bahut achha hai madem ji👍👍
Thank you so much ❤️👍
20:03 ka ans aayae ga mix of diastereomers not enantiomers kk homocyclic part ka chiral carbon ki configuration dou mae same hn
Thank you ma'am
at 30:28 its not chlorine its carbon tetra iodide. Chlorine exist in diatomic molecule only not in tetra-atomic molecule.
Maam in the last question of this video, there are already 2 chiral centres present so, both H have to diastereotopic, isn't it ?
Mam please make videos on which chapter you should cover from books like d nasipuri,clyden and others book..
Thank u amazing madam
34:11 the answer is correct but the procedure is wrong.....
For the cis isomer there are 3 gauche butane interaction. So ∆G= (3×0.9)-0.9= 1.8 kcal/mol. Please check.
Bahi khali 2 hi interaction hn 3rd intraction R R nhi include hojayae gi kk woh ring ka part hn.
Thank u so much mam😊😊😊
Mam second last question me aap ne gauche interaction R&R' ki kyu nhi consider ki hai kya vo bulky nhi hai plz reply mam
Actually we are considering the ring as two parts that are R and R' ......
But in actual that's still a ring ...
24.44 min carbon 4 ka s kese configuration aega
I hv same daught
Madam ap smile bohat achcha karte ho
Maam thank you so much
hello mam 11th quesation mai ans A aayega naa becoz epoxide ring above the plane hai so attack below the plane hoga......so we will get only one product.......
Ma'am pls tell me book for previous year question papers
Mam which book your following to make this video? Will you please share it's link
Ma'am
37.48, in that question what do uh mean by DELTA G. And you r not taking R and R Interactions.
Ager do same compound jisme 2no group bhi same ho .. bt ek structure mai wedge or ek mai dash par ho to ky relation hoga..
Mam which rule is most applicable cram or felling ANH model
Ufff mam... Double mehnat hogyi😓 koi nhi. Saamne koi bethta recording me to bhi thik tha
ma'am 19:36 pe , option c me plane of symmetry kaise nahi hai ?
Mam r n r me gauche interaction ni hoga kya
Keep it up
At 33:50 why don't we consider R and R' grps bulky?
yes, same problem with me
The method she followed here is wrong. In the reactant there is only one G.B. interaction and in the product there is three G.B. interactions. So net change in G.B. interactions is (3-1) = 2
So , delG = 2×0.9 = 1.8 .
This is the correct method.
Ab del G of reaction 0.9 aayae ga
@17:40 answer is regioisomer becauz markownikoff add gives major and minor product so regioisomers are formed. I hope I'm not mistaken.
When RS rule is applied RS and RR is coming.And they are Diastero.
It's relation is given in clayden of no 394
RS and RR so diasteo
Mam no of geometrical and optical isomers count krna v batado uske bina stereo adhura... Uska question v ata he
Mam csir net jrf ke previous year questions topic wise ke liye koi books h kya.. please ho to name suggest kre
im also in the need
Ma'am 33.20 pe axial or equatorial me Kuch confusion he i think
Exactly..I can't understand why she give first Me group in equatorial position
Great mam
Mam markownikov rule wale question me diasteriomer banega?
Thank u mam
mam why u skip the enantiomeric excess problems???????????
Love you mam.......
Nice madium g
some questions you are not explain mam.... Give more reasons to the question
Ma'am pyq kha se dekh rhi h mujhe bhi Lena h ye notes kaise milega
Thank you maam
Solid state chaper v krwa dijyy na maam
Mam please pro r Or pro S configuration please sikhao
Mast
Hello mam
Mam in last que , why you could not applied C2 axis of symmetry..??
Yaa, c2 is possible nh?
💜💚🧡💛
Sister pls help me..how to creak csir exam June 2019..which topics I want to cover
ruclips.net/video/c0EUH7_jxIc/видео.html
Didi you did wrong answer in 2nd last question...you should check it..
Mem mcq books bta do please
Mam Helical chiral compound aapne kaha discuss kia he kya ?plz link dedo
ruclips.net/p/PLYXnZUqtB3K_Z1y56fUgFh0wl9lHclY2P
markonikov wala diasteriomers banta hai
Mam PDF matter mil Sakta h kya topic wise
Q. 36:30, why not homotopic? C2 axis b to ho skti h
C2 nhi h
Mam in Dec 2011 IUPAC nomenclature questions how you give the highest second priority of that carbon which is added to alkyne group.
I was having the same thought... Akyne ko 1 milna chahiye. .kyunki
Using first point of difference ruks Alkyne should b prioritized over CH2COOH
mam aapne jo stereochemistry krwai ha .wo sufficient ha kisi bhi exam kliye
plzz ans.
Yes ...Jo topics maine karaaye hain stereo mein ..woh kahin aur se padhne ki need nahi hai
thanks mam ....aur ek baat mam....csir ma kitna marks ki aati ha stereochemistry
Mam sn1 sn2 e1 e2??
HBr addition ka jo do products hai wo to diasteteomer ho raha hain. .....apne enantiomer bola
Yes sir. It will be diastereomers
Yes sir diasrereoisomer hoga lg rha
Yes
Mam meso wala smjh ni aaya 😫
Mam R and R` bhi bulky gps hai na
Yh dou ring k parts hn esi liyae interaction mae nhi ginae jayae gae
Mam markonikov question no 8 me fisher projection bana Kar ek Bar check kijiye Mera answer distereomer aa raha h
Mera v
Mera v
34:15 pe 2.7 kcal
Hoga r and r'mein bhi to interaction hogi
Abhe both me R-R interaction cancel hogi...understand?
Hello
Mam gate ans key is out did you checked ??
Yes , I did .
Am getting 60.01
@@JChemistry congratulation mam
Thanks :)