I'm so thankful for your explanations coz with this mathemtical explanation I got the clear idea of it, but sir i got confused at mAs(new)=mAs×(1.15)^5.......which i got corrected at mAs(new)=mAs×0.5😄
@@TheNettforce yes but it seems like the same concept. Increase voltage increases energy of the photon while adjusting amplitude controls the amount of photons passing through.
Yes great explanation and demostration thank you for your time
Thanks Harout, that is our aim. I have seen a number of educators dive in the 15% rule without explanation so we will have one here you can point to
@@HowRadiologyWorks yes can you explain difference between ma and mas and conection between the two
Thanks Harout that is a good idea
I'm so thankful for your explanations coz with this mathemtical explanation I got the clear idea of it, but sir i got confused at mAs(new)=mAs×(1.15)^5.......which i got corrected at mAs(new)=mAs×0.5😄
Thanks Bhavesh, yeah depends on if new kVp is greater or less. If kVp up by 15% use 0.5 mAs , if kVp down by 15% then mAs new is 2.0*mA
Isn’t this just ohms law
Ohms law has to do with resistance and here we are dealing with radiation interactions in the body
@@TheNettforce yes but it seems like the same concept. Increase voltage increases energy of the photon while adjusting amplitude controls the amount of photons passing through.